机械原理课程设计任务书（十一）姓名 专业 班级 学号一、设计题目：插床齿轮机构的设计 二、系统简图：三、工作条件已知：齿数1Z 传动，齿轮与曲柄共轴。
四、原始数据五、要求：1）选择变位系数；2）计算该对齿轮传动的各部分尺寸； 3）A2纸上画出三对齿啮合图； 4）编写说明书。
指导教师：开始日期： 年 月 日 完成日期： 年 月 日1数学模型1中心距a '：2)(21z z m a +⨯= ；a '=（a/5+1）⨯5；2啮合角α'：；)cos(2)()cos(21ααα⨯'⨯+='z z m实αααinv z z x x inv +++=')/()(tan 22121；3分配变位系数21x x 、；17sin 22min≈=*αah zmin 1min min 1/)(z z z h x a -=*；min 2min min 2/)(z z z h x a -=*；；αααtan 2))((2121z z inv inv x x +-'=+4齿轮基本参数：（注：下列尺寸单位为mm ）齿顶高系数：0.1=*a h齿根高系数： 25.0=*c齿顶高变动系数： y x x -+=21σ分度圆直径； 11mz d = 22mz d =基圆直径； αcos 11mz d b = αcos 22mz d b =齿顶高： )(11σ-+=*x h m h a a)(22σ-+=*x h m h a a 齿根高： )(11x c h m h a f -+=*)(22x c h m h a f -+=**齿顶圆直径： 1112a a h d d += 2222a a h d d +=齿根圆直径； 1112f f h d d -= 2222f f h d d -=节圆直径： αα'='cos cos 11d dαα'='cos cos 22d d齿距： m p π= 节圆齿距： αα'='cos cos pp基圆齿距： απcos m p b =中心距变动系数 y=(a a -')/m ； 分度圆齿厚：απtan 22155m m x s +=απtan 22166m m x s +=5 重合度：)]tan (tan )tan (tan [212211ααααπε'-+'-=a a z z)/(cos 1111a b a d d -=α)/(cos 2212a b a d d -=α一般情况应保证2.1≥ε6齿顶圆齿厚：)(2111111ααinv inv r r r s s a a a a --=)(2222222ααinv inv r r r s s a a a a --=一般取25.0≥a s7 展角：'-'=11111arccos )tan(arccosd d d d b b θ'-'=22222arccos )tan(arccosd d d d b b θ2程序框图3程序清单及运行结果#include"math.h"#include"stdio.h"#define z1 13.0#define z2 40.0#define t 20*3.14/180 /*yalijiao,unit:rad*/#define m 8 /*moshu*/#define hax 1.0#define cx 0.25#define Zmin 17.0#define pi 3.14main( ){ int a,ai; double ti; /*niehejiao*/double x1,x2,xh;double db1,db2; /*jiyuanzhijing*/double d1,d2; /*fenduyuanzhijing*/ double ha1,ha2; /*chidinggao*/double hf1,hf2; /*chigengao*/double df1,df2; /*chigenyuanzhijing*/double di1,di2; /*jieyuanzhijing*/double da1,da2; /*chidingyuanzhijing*/ double p; /*chiju*/double p1; /*jieyuanchiju*/double pb; /*jiyuanchiju*/double S1,S2; /*chihou*/double Sb1,Sb2; /*jiyuanchihou*/double Sa1,Sa2; /*chidinghou*/double o1,o2; /*jieyuanzhanjiao*/double e; /*chonghedu*/double y,Xmin1,Xmin2; /*y shifenlixishu*/double cdb;double cgm; /*chidingaobiandongxishu*/ int j,i;a=m*(z1+z2)/2;printf("a=%d \n",a);i=a/5;ai=(i+1)*5;printf("ai=%d (mm)\n",ai);ti=acos(a*cos(t)/ai);printf("ti=%4.3f (rad)\n",ti);cdb=z2/z1;printf("\n cdb=%5.3f \n",cdb);y=0.5*(z1+z2)*(cos(t)/cos(ti)-1);printf("y=%5.3f \n",y);d1=m*z1;d2=m*z2;printf("d1=%5.3f,d2=%5.3f (mm)\n",d1,d2);db1=m*z1*cos(t);db2=m*z2*cos(t);printf("db1=%5.3f,db2=%5.3%f (mm)\n",db1,db2); di1=d1*cos(t)/cos(ti);di2=d2*cos(t)/cos(ti);printf("di1=%5.3f,di2=%5.3f (mm)\n",di1,di2);p=m*pi;printf("p=%5.3f (mm)\n",p);p1=p*cos(t)/cos(ti);pb=pi*m*cos(t);printf("p1=%5.3f,pb=%5.3f (mm)\n",p,p1,pb); Xmin1=hax*(Zmin-z1)/Zmin;printf("Xmin1=%3.4f (mm)\n",Xmin1);Xmin2=hax*(Zmin-z2)/Zmin;printf("Xmin2=%3.4f (mm)\n",Xmin2);xh=0.5*(tan(ti)-ti-(tan(t)-t))*(z1+z2)/tan(t);printf("xh=x1+x2=%5.3f \n",xh);for(j=0;j<10;j++){x1=Xmin1+0.04*j;x2=xh-x1;if(x2<Xmin2)break;cgm=x1+x2-y;ha1=m*(hax+x1-cgm);ha2=m*(hax+x2-cgm);hf1=(hax+cx-x1)*m;hf2=(hax+cx-x2)*m;da1=d1+2*ha1;da2=d2+2*ha2;df1=d1-2*hf1;df2=d2-2*hf2;S1=0.5*pi*m+2*x1*m*tan(t);S2=0.5*pi*m+2*x2*m*tan(t);Sb1=S1*db1/d1-db1*(tan(acos(db1/db1))-acos(db1/db1)-(tan(t)-t)); Sb2=S2*db2/d2-db2*(tan(acos(db2/db2))-acos(db2/db2)-(tan(t)-t)); Sa1=S1*da1/d1-da1*(tan(acos(db1/da1))-acos(db1/da1)-(tan(t)-t)); Sa2=S2*db2/d2-da2*(tan(acos(db2/da2))-acos(db2/da2)-(tan(t)-t)); o1=tan(acos(db1/di1))-acos(db1/di1);o2=tan(acos(db2/di2))-acos(db2/di2);e=(z1*(tan(acos(db1/da1))-tan(ti))+z2*(tan(acos(db2/da2))-tan(ti)) )/(2*pi);if((S1>cx*m)&&(S2>cx*m)&&(Sb1>cx*m)&&(Sb2>cx*m)&&(Sa1>cx*m)&&(Sa2>cx*m)&&(e>1.2)){ printf("x1=%5.3f,x2=%5.3f (mm)\n",x1,x2);printf("cgm=%5.3f \n",cgm);printf("ha1=%5.3f,ha2=%5.3f (mm)\n",ha1,ha2);printf("hf1=%5.3f,hf2=%5.3f (mm)\n",hf1,hf2);printf("da1=%5.3f,da2=%5.3f (mm)\n",da1,da2);printf("df1=%5.3f,df2=%5.3f (mm)\n",df1,df2);printf("S1=%5.3f,S2=%5.3f (mm)\n",S1,S2);printf("Sb1=%5.3f,Sb2=%5.3f (mm)\n",Sb1,Sb2);printf("Sa1=%5.3f,Sa2=%5.3f (mm)\n",Sa1,Sa2);printf("o1=%6.5f,o2=%6.5f (rad)\n",o1,o2);printf("e=%5.3f \n",e);printf("db1=%5.3f,db2=%5.3f (mm)\n",db1,db2);}}}运行结果ai=215 (mm)ti=0.385 (rad)df1=92.885, df2=297.421 (mm) s1=15.792, s2=11.622 (mm)sb1=16.295, sb2=15.397 (mm)o1=0.02029, o2=0.02029 (mm)e=1.381db1=97.734, db2=300.721 (mm) x1=0.595, x2=-0.201 (mm)cgm=0.019ha1=12.609, ha2=6.238 (mm)hf1=5.238, hf2=11.609 (mm)da1=129.219, da2=332.475 (mm) df1=93.525, df2=296.781 (mm) s1=16.025, s2=11.389 (mm)sb1=16.514, sb2=15.178 (mm)sa1=2.215, sa2=5.372 (mm)o1=0.02029, o2=0.02029e=1.370db1=97.734, db2=300.721 (mm)4 设计总结一周的课程设计就要结束了，通过这短短的一周，我学到了很多，首先是对插床齿轮的进一步了解，还有增强了自己动手的实践能力，很多很多，真是受益匪浅。