Plans for saving electricity节电方案计划Today's companies face a wide range of competition, and constantly reduce the power consumption is not only an important way to reduce costs to improve competitiveness over a long period of time, and is the realization of their own is the effective means to make contributions to reduce emissions当今企业面临广泛的竞争，不断降低电力能耗不仅是长期降低成本提高竞争力的重要途径，而且是实现自身为降低排放作贡献的有效手段。

The way of energy saving of enterprises企业电力节能的途径First, because of the power efficiency of the electric power sector, the improvement of power factor can make no work penalty.一是由于电力部门考核的电力效能，即功率因素提高方面，可使无功罚款转变为无功奖励。

Second，The energy saving effect can be about 8 ~ 15% of the compensation of the load on the side of the load二是自身负载侧的无功修正及线损补偿，其节能效果可以达到8~15%左右。

Third，Electric power special aspects: such as load management, may reduce power load peak power 5 ~ 30%, for a lot of electricity companies such as steel mills, a year can save electricity cost millions三是电力能源的特殊方面:比如负荷管理，可能使电力负荷高峰功率降低5~30%，对一个大量用电企业如钢厂，每年可节约用电费用几百万之巨！Fourth，Clean energy saving on electricity, with a focus on the possible power grid harmonic filter, on the basis of conventional energy saving effect, improve skills 3 ~ 50%, especially can improve the reliability of the system四是着力于电力清洁节能，重点是滤除可能存在的电网谐波,可在常规节能效果的基础上，提高技能率3~50%，特别是可以提高系统的可靠性。

Fifth，Comprehensive energy management, comprehensive, scientific and efficient management of electricity, water and gas can increase comprehensive energy efficiency to about 10-20%五是综合性的能源管理，对电、水、气等实行综合、科学、高效的管理，可将综合能源利用率提高到10~20%左右。

The enterprise is reactive power and harm企业无功功率及危害The reverse of the magnetic field generated by the current hysteresis of a transformer,motor, induction heater, coil, etc. Is called reactive power. Moreover, the transmission of electricity also produces a lot of reactive power. They lead to：电网中的变压器、电机、感应加热器、线圈等感性负载的电流滞后产生的磁场反向能称为无功功率。

此外电力的输送也会产生大量的无功功率。

他们导致:Companies have low corporate factors and fines企业企业因数低而罚款Increased power consumption and electricity costs增加电能消耗及用电成本Increase the power loss of power grid and drop the power grid增大电网功率损耗及电网压降Reducing transmission efficiency降低输电效率Increase transformer loss and distribution cable size增加变压器损耗及配电电缆尺寸Cause transient, transient, fluctuation, distortion, lower concave, etc引发瞬变，暂态，波动，畸变，下凹等The power factor of the various load of the enterprise企业各种负载的功率因数Load categories 负载类别Male child ~ full半载~满载Induction motor 感应电机 0.6~0.9The general industry 一般工业 0.6~0.8The paper industry 造纸工业 0.5~0.8Chemical equipment 化工设备 0.75~0.85Arc furnace电弧炉 0.6~0.8The cement industry 水泥工业 0.75~0.85Ac welding machine 交流焊机 0.35~0.4The steel industry 钢铁工业 0.6~0.85The plastics industry 塑胶工业 0.6~0.75Enterprises improve the economy of power factors企业提高功率因数的经济性●Reduce the total current of the system降低系统总电流总有功无功●Reduce the loss of transformer and transmission lines降低变压器及输电线路损失P=3*I2*RReduction of I reduces the loss power PI减少使损失功率P相应减少●Increase the utilization of transformer and line增加变压器及线路的利用率●Stabilize and improve system voltage稳定及提高系统电压●The payback period is between 6 and 24 months投资回收期在6-24个月之间●To meet the development concept of environmental protection (saving 1 degree of electricity and reducing carbon dioxide emissions by 0.997 kg)符合节约环保的发展理念（节约1度电可减排0.997kg二氧化碳）Here are the examples of the storaenso factory:针对斯道拉恩索工厂计算示例如下：Reactive power compensation capacity fast query table■无功功率补偿容量快速查询表Compensation capacity query and calculation补偿容量查询与计算Qc=Pw×FQc：The amount of reactive capacity that needs to be compensated需补偿的无功容量Pw：The system has the power of power系统有功功率F：The coefficient in the query table查询表中系数Cos Φ before 1 by compensation and compensation of cosine Φ 2 queries由补偿前的cosΦ1及补偿后的cosΦ2查询得出。

一、800AE03●3.5 MVA transformer3.5MVA的变压器●35/0.72 kv transformer35/0.72kv变压器●The actual current average of 1600A实际电流平均值1600A●The average power factor is 0.8原功率因数平均值为0.8●The target power factor 0.96目标功率因数0.96To calculate：Cos Φ 1 = 0.8, cos Φ 2 = 0.96, U = 0.69 KVPw=*U*I* cosΦ, thePw=From 0.8 to 0.96, the coefficient is F = 0.458The amount of reactive capacity that needs to be compensated for is Pw x F = 1835* 0.458 = 840KvarWhen the voltage is 690V, the rated voltage is 815V, and the resistance rate is 7%The installed capacity of the reduced capacity is approximately 1089KvarCompensation before: the total currentI总1===1919A，Power consumption P1=U*I总1=0.69*1919=1324 Kw·h After the compensation: total currentI总2===1599A，Power consumption P2=U*I总2=0.69*1599=1103 Kw·hI差= I总1- I总2=1919-1599=320ASaving electricity per hourP差= P1 - P2 = 1324-1103 = 221Kw/hThe annual cost of saving the electric bill is the same as the P差* 24 * 365 * 0.52 = 1006699.2 yuan计算：cosΦ1=0.8，cosΦ2=0.96，U=0.69KVPw=*U*I* cosΦ，则Pw=*0.69*1600*0.96=1835Kw则由0.8至0.96从上表中查出系数为F=0.458则需补偿的无功容量Qc= Pw×F =1835*0.458=840Kvar而当系统电压为690V，采用额定电压为815V，电抗率为7%时，需要考虑降容那么降容后的安装容量Qn约为1089Kvar补偿前：总电流I总1===1919A，耗电P1=U*I总1=0.69*1919=1324 Kw·hθ==1599A，耗电P2=U*I总2=0.69*1599=1103 Kw·h 补偿后：总电流I总2=θI差= I总1- I总2=1919-1599=320A每小时节电：P差=P1 -P2=1324-1103=221Kw·h每年节约电费P差*24*365*0.52=1006699.2元The compensation plan is as follows:System voltage 690 v, rated voltage 815 v, the reactance rate was 7%, the actual installation capacity of 794 kvar (by 800 kvar to compensation), points to two cabinet, 400 kvar respectively, single tank points 9 loop, 25 kvar * 2 + 50 kvar *7, the configuration list as follows:补偿方案如下：系统电压690V，采用额定电压815V，电抗率为7%，则实际安装容量1089kvar（按1100kvar 来补偿），分两个柜子，分别为550kvar，单柜分12个回路，25kvar*2+50kvar*10，配置清Rated current compensation I===779A, draw out the switch capacity to choose 5 to 7 times the rated current, size in 3895A(or two 1947A separate control cabinet) above!Summary: (800AE03)1、The installed reactive capacity is 1100kvar2、The current is reduced by 320A after the reactive power compensation cabinet is installed3、The cost of saving energy is 1006699.2yuan ($0.52) per year after installing the reactive tank.补偿柜额定电流I===779A，抽屉式开关容量选择额定电流的5-7倍来计算，大小在3895A（或者2个1947A分别控制2个柜子）以上！总结：（800AE03区域）1、安装无功补偿容量为1100kvar2、安装无功补偿柜之后，电流减少了320A3、安装无功补偿柜后，每年节约电费是1006699.2元（电费每度0.52元）二、800AE04●3.5 MVA transformer3.5MVA的变压器●35/0.72 kv transformer35/0.72kv变压器●The actual current average of 1400A实际电流平均值1400A●The average power factor is 0.7原功率因数平均值为0.7●The target power factor 0.96目标功率因数0.96To calculate：Cos Φ 1 = 0.7, cos Φ 2 = 0.96, U = 0.69 KVPw=*U*I* cosΦ, the Pw=From 0.7 to 0.96, the coefficient is F = 0.729The amount of reactive capacity that needs to be compensated for is Qc= Pw×F =1606*0.729=1170KvarWhen the voltage is 690V, the rated voltage is 815V, and the resistance rate is 7%The installed capacity of the reduced capacity is approximately 1518KvarCompensation before: the total currentI总1===1919A，Power consumption P1=U*I总1=0.69*1919=1324 Kw·h After the compensation: total currentI总2===1399A，Power consumption电P2=U*I总2=0.69*1399=965 Kw·hI差= I总1- I总2=1919-1396=523ASaving electricity per hourP差=P1 -P2=1324-965=359Kw·hThe annual cost of saving the electric bill is the same as the P差*24*365*0.52=1635316.8 yuan计算：cosΦ1=0.7，cosΦ2=0.96，U=0.69KVPw=*U*I* cosΦ，则Pw=*0.69*1400*0.96=1606Kw则由0.7至0.96从上表中查出系数为F=0.729则需补偿的无功容量Qc= Pw×F =1606*0.729=1170Kvar而当系统电压为690V，采用额定电压为815V，电抗率为7%时，需要考虑降容那么降容后的安装容量Qn约为1518Kvar补偿前：总电流I总1===1919A，耗电P1=U*I总1=0.69*1919=1324 Kw·h补偿后：总电流I总2===1399A，耗电P2=U*I总2=0.69*1399=965 Kw·hI差= I总1- I总2=1919-1396=523A每小时节电：P差=P1 -P2=1324-965=359Kw·h每年节约电费P差*24*365*0.52=1635316.8元The compensation plan is as follows:System voltage 690 v, rated voltage 815 v, the reactance rate was 7%, the actual installation capacity of 1518 kvar (by1500 kvar to compensation), points to three cabinet, 500 kvar respectively, single tank points 11 loop, 25 kvar * 2 + 50 kvar *9, the configuration list as follows:补偿方案如下：系统电压690V，采用额定电压815V，电抗率为7%，则实际安装容量1518kvar（按1500kvar 来补偿），分三个柜子，每个柜子为500kvar，单柜分11个回路，25kvar*2+50kvar*9，配Rated current compensation draw out the switch capacity tochoose 5 to 7 times the rated current, size in 5313 A(or three 1771 A separate control cabinet) above!Summary: (800AE04)4、The installed reactive capacity is 1500kvar5、The current is reduced by 523A after the reactive power compensation cabinet is installed6、The cost of saving energy is 1635316.8 yuan ($0.52) per year after installing the reactive tank.补偿柜额定电流I===1062A，抽屉式开关容量选择额定电流的5-7倍来计算，大小在5313A（或者3个1771分别控制3个柜子）以上！总结：（800AE04区域）4、安装无功补偿容量为1500kvar5、安装无功补偿柜之后，电流减少了523A6、安装无功补偿柜后，每年节约电费是1635316.8元（电费每度0.52元）三、911AE02●3.5 MVA transformer3.5MVA的变压器●35/0.72 kv transformer35/0.72kv变压器●The actual current average of 2050A实际电流平均值2050A●The average power factor is 0.8原功率因数平均值为0.8●The target power factor 0.96目标功率因数0.96To calculate：Cos Φ 1 = 0.8, cos Φ 2 = 0.96, U = 0.69 KVPw=*U*I* cosΦ, the Pw=From 0.8 to 0.96, the coefficient is F = 0.458The amount of reactive capacity that needs to be compensated for is Qc= Pw×F =2352*0.458=1077KvarWhen the voltage is 690V, the rated voltage is 815V, and the resistance rate is 7%The installed capacity of the reduced capacity is approximately 1397KvarCompensation before: the total currentI总1===2460A，Power consumption P1=U*I总1=0.69*2460=1697 Kw·h After the compensation: total currentI总2===2050A，Power consumption P2=U*I总2=0.69*2050=1414 Kw·hI差= I总1- I总2=2460-2050=410ASaving electricity per hour P差=P1 -P2=1697-1414=283Kw·hThe annual cost of saving the electric bill is the same as the P差*24*365*0.52=1289121.6 yuan计算：cosΦ1=0.8，cosΦ2=0.96，U=0.69KVPw=*U*I* cosΦ，则Pw=*0.69*2050*0.96=2352Kw则由0.8至0.96从上表中查出系数为F=0.458则需补偿的无功容量Qc= Pw×F =2352*0.458=1077Kvar而当系统电压为690V，采用额定电压为815V，电抗率为7%时，需要考虑降容那么降容后的安装容量Qn约为1397Kvar补偿前：总电流I总1===2460A，耗电P1=U*I总1=0.69*2460=1697 Kw·h补偿后：总电流I总2===2050A，耗电P2=U*I总2=0.69*2050=1414 Kw·hI差= I总1- I总2=2460-2050=410A每小时节电：P差=P1 -P2=1697-1414=283Kw·h每年节约电费P差*24*365*0.52=1289121.6元The compensation plan is as follows:System voltage 690 v, rated voltage 815 v, the reactance rate was 7%, the actual installation capacity of 1397 kvar (by1400 kvar to compensation), points to three cabinet, 400kvar+2*500 kvar respectively, 400kvar tank points 9 loop, 25 kvar * 2 + 50 kvar *7，500kvar tank points 11 loop, 25 kvar * 2 + 50 kvar *9, the configuration list as follows:补偿方案如下：系统电压690V，采用额定电压815V，电抗率为7%，则实际安装容量1397kvar（按1400kvar 来补偿），分3个柜子，分别为400kvar+2*500kvar，400kvar单柜分9个回路，Rated current compensation I===992A, draw out the switch capacity to choose5 to 7 times the rated current, size in 4960 A(or three 1653 A separate control cabinet) above!Summary: (911AE02)7、The installed reactive capacity is 1400kvar8、The current is reduced by 410A after the reactive power compensation cabinet is installed9、The cost of saving energy is 1289121.6 yuan ($0.52) per year after installing the reactive tank.补偿柜额定电流I===992A，抽屉式开关容量选择额定电流的5-7倍来计算，大小在4960A（或者3个1653A分别控制3个柜子）以上！总结：（911AE02区域）7、安装无功补偿容量为1400kvar8、安装无功补偿柜之后，电流减少了410A9、安装无功补偿柜后，每年节约电费是1289121.6元（电费每度0.52元）四、911AE03●3.5 MVA transformer3.5MVA的变压器●35/0.72 kv transformer35/0.72kv变压器●The actual current average of 1400A实际电流平均值1400A●The average power factor is 0.8原功率因数平均值为0.8●The target power factor 0.96目标功率因数0.96To calculate：Cos Φ 1 = 0.8, cos Φ 2 = 0.96, U = 0.69 KVPw=*U*I* cosΦ, the Pw=*0.69*1400*0.96=1606KwFrom 0.8 to 0.96, the coefficient is F = 0.458The amount of reactive capacity that needs to be compensated for isQc= Pw×F =1606*0.458=736KvarWhen the voltage is 690V, the rated voltage is 815V, and the resistance rate is 7%The installed capacity of the reduced capacity is approximately 955KvarCompensation before: the total currentI总1===1680A，Power consumption P1=U*I总1=0.69*1680=1159 Kw·hAfter the compensation: total currentI总2===1400A，Power consumption P2=U*I总2=0.69*1400=966 Kw·hI差= I总1- I总2=1680-1400=280ASaving electricity per hour P差=P1 -P2=1159-966=193Kw·hThe annual cost of saving the electric bill is the same as the P差*24*365*0.52=879153.6 yuan计算：cosΦ1=0.8，cosΦ2=0.96，U=0.69KVPw=*U*I* cosΦ，则Pw=*0.69*1400*0.96=1606Kw则由0.8至0.96从上表中查出系数为F=0.458则需补偿的无功容量Qc= Pw×F =1606*0.458=736Kvar而当系统电压为690V，采用额定电压为815V，电抗率为7%时，需要考虑降容那么降容后的安装容量Qn约为955Kvar==1680A，耗电P1=U*I总1=0.69*1680=1159 Kw·h 补偿前：总电流I总1=θ补偿后：总电流I总2===1400A，耗电P2=U*I总2=0.69*1400=966 Kw·hθI差= I总1- I总2=1680-1400=280A每小时节电：P差=P1 -P2=1159-966=193Kw·h每年节约电费：P差*24*365*0.52=879153.6元The compensation plan is as follows:System voltage 690 v, rated voltage 815 v, the reactance rate was 7%, the actual installation capacity of 955 kvar (by 1000 kvar to compensation), points to two cabinet, 500 kvar respectively, single tank points 11 loop, 25 kvar * 2 + 50 kvar *9, the configuration list as follows:补偿方案如下：系统电压690V，采用额定电压815V，电抗率为7%，则实际安装容量955kvar（按1000kvar 来补偿），分2个柜子，分别为500kvar，单柜分11个回路，25kvar*2+50kvar*9，配置清Rated current compensation I===708A, draw out the switch capacity to choose 5 to 7 times the rated current, size in 3540 A(or two 1770 A separate control cabinet) above!Summary: (911AE03)10、The installed reactive capacity is 1000kvar11、The current is reduced by 280A after the reactive power compensation cabinet is installed12、The cost of saving energy is 879153.6 yuan ($0.52) per year after installing the reactive tank.补偿柜额定电流I===708A，抽屉式开关容量选择额定电流的5-7倍来计算，大小在3540A（或者2个1770A分别控制2个柜子）以上！总结：（911AE03区域）10、安装无功补偿容量为1000kvar11、安装无功补偿柜之后，电流减少了280A12、安装无功补偿柜后，每年节约电费是879153.6元（电费每度0.52元）。