15
5.23.2
40
0
0
16.64
16.64
23.36
5.796526
2.898263
7.477519
16.87226
24.34978
15.65022
3.88343
16
8
0
2.08
2.08
-2.08
-0.51613
-0.25806
-0.66581
8.539355
2.08
-2.08
-0.51613
17
时段净雨量分析的道德单位线作为第一次嘉定的单位线q(t)，求出最大的时段精油量以外的各时段得净雨量的部分地面径流过程，把他们错时段叠加，与总的地面径流相减，其差值就是最大时段的净雨量所产生的部分地面径流过程，把他乘以10/rdmax,就得带一条试算的单位线q1（t）若与第一次假定的单位线接近。即为所求，否则将两个单位线的纵坐标平均，求出平均值，作为第二次假设，重复上述步骤。结果如下表所示。
569.92
1034.32
1125.68
279.3251
229.6625
592.5293
643.3497
1235.879
924.121
229.3104
7
5.21.2
1340
124
319.92
343.2
663.12
676.88
167.9603
145.9801
376.6288
479.9923
856.621
40.77419
38.3871
99.03871
70.90839
169.9471
160.0529
39.71536
12
8
230
18
46.44
45.76
92.2
137.8
34.19355
26.09677
67.32968
55.32387
122.6535
107.3465
26.63684
13
14
145
16
41.28
(15)
(16)
1
5.19.14
60
25.8
75
193.5
0
193.5
-133.5
-33.1266
20.93672
54.01675
0
54.01675
5.983251
1.484678
2
20
950
40.3
316
815.28
0
815.28
134.72
33.42928
174.7146
450.7638
0
450.7638
单位线分析计算表（科林法）
时序
月日时
Qt
r
q1
r1*qi
r3*qi
(5)+(6)
(2)-(7)
q2=(8)/r2
((4)+(9))/2
qi*r1
qi*r3
(11)+(13)
(2)-(14)
q3=(15)/r2
(0)
(1)
(2)
(3)
(4)
(5)
(6)
(7)
(8)
(9)
(10)
(11)
(13)
(14)
151.8194
327.7267
249.2733
61.85442
10
20
444Leabharlann 44113.5279.04
192.56
251.44
62.39206
53.19603
137.2458
97.16129
234.407
209.593
52.00818
11
5.22.2
330
36
92.88
72.8
165.68
164.32
37.44
78.72
66.28
16.44665
16.22333
41.85618
39.92258
81.77876
63.22124
15.68765
14
20
82
2
5.16
18.72
23.88
58.12
14.42184
8.210918
21.18417
27.14065
48.32481
33.67519
8.356126
499.2362
123.88
3
5.20.2
3150
10.4
614
1584.12
78
1662.12
1487.88
369.201
491.6005
1268.329
21.77419
1290.103
1859.897
461.5128
4
8
4520
548
1413.84
328.64
1742.48
2777.52
689.2109
14
0
0
0
0
0
0
0
3.014194
3.014194
-3.01419
-0.74794
483.379
119.9452
8
8
830
76
196.08
187.2
383.28
446.72
110.8486
93.42432
241.0347
238.849
479.8838
350.1162
86.87748
9
14
577
70
180.6
128.96
309.56
267.44
66.36228
68.18114
175.9073
618.6055
1596.002
181.7032
1777.705
2742.295
680.4701
5
14
3880
330
851.4
638.56
1489.96
2390.04
593.062
461.531
1190.75
511.2645
1702.015
2177.985
540.443
6
20
2160
180
464.4