引子#include "stdio.h"main(){ int i=1;for(i=1;i<=10000;i++)printf(“%d\t”,i);}题型1 输入输出多个数据eg1、输出1~10000之间所有的整数#include "stdio.h"main(){ int i=1;while(i<=1000){printf(“%d\t”,i);i++;}}拓展：1、换成所有的奇数2、换成所有的偶数题型2 有限个数连加和连乘eg2.1、求1+2+3+4+………+100的值#include "stdio.h"main(){ int i=1,s=0;while(i<=100){s=s+i;i++;}printf(“%d\n”,s);}拓展：1、求1+2+3+4+………+n的值2、求12+22+32+………+n2的值3、求1+1/2+1/3+………+1/n的值eg2.2、求n!的值#include "stdio.h"main(){ int i=1,n,p=1;scanf(“%d”,&n);while(i<=n){p=p*i;i++;}printf(“%d\n”,p);}拓展：求1!+2!+3!+………+n!的值#include "stdio.h"main(){ int i=1,n,p=1,s;scanf(“%d”,&n);while(i<=n){p=p*i;s=s+p;i++;}printf(“%d\n”,s);}题型3 无限个数连加eg3、求1-1/3+1/5-1/7+………的近似值，要求精度要达到10-4#include "stdio.h"#include "math.h"main(){ float n=1,s=0,f=1,t=1;while(fabs(t)>=1e-4){t=f/(2*n-1);s=s+t;f=-f;n++;}printf(“%f\n”,s);}拓展：求1-1/2+1/4-1/6+………的近似值，要求精度要达到10-4题型4 统计eg4.1、输入20个数，统计其中正数、负数和零的个数。

#include "stdio.h"main(){ int i=1,n,p,z;float x;p=n=z=0;while(i<=20){ scanf(“%f”,&x);if(x>0)p++;elseif(x<0)n++;elsez++;i++;}printf(“%d\t%d\t %d\n”,p,n,z);}拓展：统计各类字符的个数eg4.2 个位为6且能被3整除的五位数有多少？方法1#include "stdio.h"main(){ long i=10000,c=0;while(i<=99999){if((i%3==0)&& (i%10==6))c++;i++;}printf(“%d \n”,c);}方法2#include "stdio.h"main(){ long i=10006,c=0;while(i<=99999){if(i%3==0)c++;i=i+10;}printf(“%d \n”,c);}题型5 数列eg5 输出fibo数列的第20位数字#include "stdio.h"main(){ int f1=1,f2=1, f3,i=3;while(i<=20){ f3=f1+f2;f1=f2;f2=f3;i++;}printf(“%d \n”,f3);}拓展：输出fibo数列前20位数字#include "stdio.h"main(){ int f1=1,f2=1, f3,i=3;printf(“%d \t%d \t”,f1,f2);while(i<=20){ f3=f1+f2;f1=f2;f2=f3;printf(“%d \t”,f3);i++;}}题型6 数据的逆序输出eg6 任意给定一个正整数，个位数字逆序输出。

#include "stdio.h"main(){ long x,t;scanf(“%ld”,&x);while(x!=0){ t=x%10;x=x/10;printf(“%d”,t); }}题型7 公约数与公倍数eg7 任意输入两个正整数，求其最大公约数和最小公倍数。

#include "stdio.h"main(){ int m,n,a,b,r,t;scanf(“%d%d”,&m, &n);if(m>n) {a=m;b=n;}else {a=n;b=m;}while(b!=0){ r=a%b;a=b;b=r;}printf(“zuida gongyushu shi:%d\n”,a);printf(“zuixiao gongbeishu shi:%d\n”,m*n/a);}题型8 素数问题eg8 从键盘上任意输入一个正整数，判断其是否为素数。

#include "stdio.h"main(){ int x,i=2;scanf(“%d”,&x);while(x%i!=0) i++;if(x==i) printf(“shi!”);else printf(“fou!”);}题型9 高次方程的根eg9.1 用二分迭代法求解方程y=2x3-4x2+3x-6=0在(-10,10)之间的根，要求精度10-5#include "stdio.h"#include "math.h"main(){float x1=10,x2=-10,x, y ,y1;x=(x1+x2)/2;y=2*x*x*x-4*x*x+3*x-6;while(fabs(y)>1e-5){y1=2*x1*x1*x1-4*x1*x1+3*x1-6;if(y*y1>0)x1=x;elsex2=x;x=(x1+x2)/2;y=2*x*x*x-4*x*x+3*x-6;}printf("the root is %f\n",x);}eg9.2 用牛顿迭代法求解方程2x3+ 4x2-7x-6=0在x=1.5附近的根，要求精度10-5 #include "stdio.h"#include "math.h"main(){float x,x0, y ,y1;x=1.5;while(fabs(x-x0)>1e-5){ x0=x;y=2*x0*x0*x0+4*x0*x0-7*x0-6;y1=6*x0*x0+8*x0-7;x=x0-y/y1;}printf("the root is %f\n",x);}牛顿迭代公式：x n+1=x n-f(x n)/f’(x n)do-while循环结构举例#include "stdio.h"main(){ int i=1,s=0;do{s=s+i;i++;} while(i<=100);printf(“%d\n”,s);}for循环结构举例f1#include "stdio.h"main(){ int i=1,s=0;for(i=1;i<=100;i++)s=s+i;printf(“%d\n”,s);}f2#include "stdio.h"main( ){int i,f1,f2,f3;f1=1;f2=1;printf("%d,%d",f1,f2);for(i=3;i<=20;i++){f3=f1+f2;f1=f2;f2=f3;printf(",%d",f3);}}f3#include "stdio.h"main( )int i;float a,max;scanf("%f ",&a);max=a;for(i=1;i<=9;i++){ scanf("%f ",&a);if(max<a)max=a;}printf("%f\n",max); }f4#include "stdio.h"main( ){int i,s=1;for(i=9;i<=1;i--)s=2*(s+1);printf("%d\n",s);}#include "stdio.h"main(){int x,n=0,s=0;while (n<10){scanf("%d",&x);if (x<0) break;s+=x;n++;}printf("s=%d\n",s);}#include "stdio.h"main( ){int x,n=0,s=0;while (n<10){scanf("%d",&x);if (x<0) continue;s+=x;n++;}printf("s=%d\n",s);}#include "stdio.h"main( ){int x,n=0,s=0;while (n<10){scanf("%d",&x);n++;if (x<0) continue;s+=x;}printf("s=%d\n",s);}#include "stdio.h"main(){int i=2,m;scanf("%d",&m);while(m%i!=0)i++;if(i==m)printf("%d shi sushu!\n",m); elseprintf("%d bu shi sushu!\n",m); }#include "stdio.h"main(){int i,m;scanf("%d",&m);for(i=2;m%i!=0;i++) ;if(i==m)printf("%d shi sushu!\n",m);elseprintf("%d bu shi sushu!\n",m); }#include "stdio.h"main( ){ int i,m;scanf("%d",&m);for (i=2; i<=m; i++)if (m%i==0) break;if(i==m)printf("%d shi sushu!\n",m);elseprintf("%d bu shi sushu!\n",m); }#include "stdio.h"#include "math.h"main( ){ int i,m,s;scanf("%d",&m);s=sqrt(m);for (i=2; i<=s; i++)if (m%i==0) break;if(i==s+1)printf("%d shi sushu!\n",m);elseprintf("%d bu shi sushu!\n",m); }#include "stdio.h"#include "math.h"main(){int i,j;for(i=100;i<=200;i++){for(j=2;j<=i;j++)if (i%j==0) break;if(j==i)printf("%-10d",i);}}#include "stdio.h"#include "math.h"main(){int i,j,s;for(i=100;i<=200;i++){ s=sqrt(i);for(j=2;j<=s;j++)if (i%j==0) break;if(j==s+1)printf("%-10d",i); } }#include <include.h> main( ){ int i,j,s;for (i=2; i<=10000; i++){ s=0;for (j=1; j<i; j++)if (i%j==0)s+=j;if (i==s)printf("%6d\n",s);}}#include "stdio.h"main(){int i,j,k;for(i=0;i<=35;i++)for(j=0;j<=35;j++)if((i+j==35)&&(2*i+4*j==94))printf("\ni=%-10dj=%-10d",i,j); }#include "stdio.h"main(){ int i,j,k;for(i=0;i<=19;i++)for(j=0;j<=33;j++)for(k=0;k<=100;k++)if((i+j+k==100)&&(5*i+3*j+k/3==300)) printf("\ni=%-10dj=%-10dk=%-10d",i,j,k); }#include "stdio.h"main(){ int i,j,k;for(i=0;i<=19;i++)for(j=0;j<=33;j++){k=100-i-j;if(15*i+9*j+k==300)printf("\ni=%-10dj=%-10dk=%-10d",i,j,k);}}#include "stdio.h"main(){int i,j,k;for(i=0;i<=19;i++)for(j=0;j<=33;j++){k=100-i-j;if(5*i+3*j+k/3==100)printf("\ni=%-10dj=%-10dk=%-10d",i,j,k); } }#include "stdio.h"main(){ int m,n,k;for (m=1;m<=9;m++){ for(n=1;n<=m;n++)printf("%d*%d=%-5d",n,m,n*m);printf("\n"); }}#include "stdio.h" main(){int i;for(i=1;i<=5;i++) printf("********\n"); }#include "stdio.h"main(){int i,j;for(i=1;i<=5;i++){for(j=1;j<=5-i;j++)printf(" ");printf("********\n");}}#include "stdio.h"main( ){int i,j;for (i=1; i<=5; i++){ for (j=1; j<=20-i; j++)printf(" ");for (j=1;j<=i;j++)printf("*");printf("\n");}}#include "stdio.h"main(){int i,j;for (i=1;i<=5;i++){ for (j=1;j<=20-i;j++)printf(" ");for (j=1;j<=2*i-1;j++)printf("*");printf("\n");}}#include "stdio.h"main( ){ int i,j;for (i=1; i<=5; i++){ for (j=1; j<=i-1; j++)printf(" ");for (j=1;j<=11-2*i;j++)printf("*");printf("\n");}}#include "stdio.h"main( ){ int i,j;for (i=1; i<=4; i++){ for (j=1; j<=4-i; j++)printf(" ");for (j=1;j<=2*i-1;j++)printf("*");printf("\n");}for (i=1; i<=3; i++){ for (j=1; j<=i; j++)printf(" ");for (j=1;j<=7-2*i;j++)printf("*");printf("\n");}}#include "stdio.h"main(){int i,j,k,m,n,s=0;for(i=0;i<=2;i++)for(j=0;j<=9;j++)for(k=1;k<=9;k++){m=100*i+10*j+k;n=100*k+10*j+i;if((n>2*m)&&(n<3*m)){ s++;printf("%d ",m);if(s%8==0)printf("\n");}}}。