《电路分析基础》各章习题参考答案第1章习题参考答案1-1(1)50W；(2)300V、25V，200V、75V；(3)R2=12.5Ω，R3=100Ω，R4=37.5Ω1-2VA=8.5V，Vm=6.5V，VB=0.5V，VC=-12V，VD=-19V，Vp=-21.5V，U AB=8V，U BC=12.5，U DA=-27.5V：C、D元件；电路满足功率平衡1-3电源（产生功率）：A、B元件；负载（吸收功率）条件。

1-4(1)VA=100V，VB=99V，VC=97V，VD=7V，VE=5V，VF=1V，UAF=99V，UCE=92V，U BE=94V，U BF=98V，U CA=-3V；(2)V C=90V，V B=92V，V A=93V，V E=-2V，V F=-6V，VG=-7V，U AF=99V，UCE=92V，U BE=94V，U BF=98V，U CA=-3V1-5I≈0.18A，6度，2.7元1-6I=4A，I1=11A，I2=19A1-7(a)U=6V，(b)U=24V，(c)R=5Ω，(d)I=23.5A1-8(1)i6=-1A；(2)u4=10V，u6=3V；(3)P1=-2W发出，P2=6W吸收，P3=16W吸收，P4=-10W发出，P5=-7W发出，P6=-3W发出1-9I=1A，U S=134V，R≈7.8Ω1-10S断开：U AB=-4.8V，UAO=-12V，UBO=-7.2V；S闭合：UAB=-12V，U AO=-12V，UBO=0V 1-11支路3，节点2，网孔2，回路31-12节点电流方程：(A)I1+I3-I6=0，(B)I6-I5-I7=0，(C)I5+I4-I3=0回路电压方程：①I6R6+U S5+I5R5-U S3+I3R3=0，②-I5R5-U S5+I7R7-U S4=0，③-I3R3+US3+US4+I1R2+I1R1=01-13U AB=11V，I2=0.5A，I3=4.5A，R3≈2.4Ω1-14V A=60V，V C=140V，V D=90V，U AC=-80V，U AD=-30V，U CD=50V1-15I1=-2A，I2=3A，I3=-5A，I4=7A，I5=2A第2章习题参考答案2-12.4Ω，5A2-2(1)4V，2V，1V；(2)40mA，20mA，10mA2-31.5Ω，2A，1/3A2-46Ω，36Ω2-52A，1A2-61A2-72A2-81A2-9I1=-1.4A，I2=1.6A，I3=0.2A2-10I1=0A，I2=-3A，P1=0W，P2=-18W2-11I1=-1mA，I2=-2mA，E3=10V2-12I1=6A，I2=-3A，I3=3A2-13I1=2A，I2=1A，I3=1A，I4=2A，I5=1A2-14Va=12V，I1=-1A，I2=2A2-15V a=6V，I1=1.5A，I2=-1A，I3=0.5A2-16V a=15V，I1=-1A，I2=2A，I3=3A2-17I1=-1A，I2=2A2-18I1=1.5A，I2=-1A，I3=0.5A2-19I1=0.8A，I2=-0.75A，I3=2A，I4=-2.75A，I5=1.55A2-20I3=0.5A2-21U0=2V，R0=4Ω，I0=0.1A2-22I5=-1A2-23(1)I5=0A，U ab=0V；(2)I5=1A，U ab=11V2-24IL=2A2-25I S=11A，R0=2Ω2-2618Ω，-2Ω，12Ω2-27U＝5V2-28I=1A2-29U＝5V2-30I=1A2-3110V，180Ω2-32U0=9V，R0=6Ω，U=15V第3章习题参考答案3-150Hz，314rad/s，0.02s，141V，100V，120°3-2200V，141.4V3-3u=14.1sin(314t-60°)V3-4(1)ψu1-ψu2＝120°；(2)ψ1＝-90°，ψ2＝-210°，ψu1-ψu2＝120°（不变）3-5(1)U150290V，U25020V；(2)u3=1002sin(ωt＋45°)V，u4=1002sin(ωt＋135°)V3-6(1)i1=14.1sin(ωt＋72°)A；(2)u2=300sin(ωt－60°)V3-7错误：(1)，(3)，(4)，(5)3-8(1)R；(2)L；(3)C；(4)R3-9i=2.82sin(10t-30°)A，Q≈40var3-10u=44.9sin(314t-135°)V，Q=3.18var3-11(1)I=20A；(2)P=4.4kW3-12(1)I≈1.4A，I1.430A；(3)Q≈308var，P=0W；(4)i≈0.98sin(628t-30°)A3-13(1)I=9.67A，I9.67150A，i=13.7sin(314t+150°)A；(3)Q=2127.4var，P=0W；(4)I C=0A3-14(1)C=20.3μF；(2)I L＝0.25A，I C＝16A第4章习题参考答案4-1(a)Z536.87，Y0.236.87S；(b)Z2.5245，Y0.2245S4-2Y=(0.06-j0.08)S，R≈16.67Ω，X L=12.5Ω，L≈0.04H4-3U R600V，U L8090V，U S10053.13V4-4I2036.87A4-5Z100245，I10A，U R1000V，U L12590V，UC2590V 4-6Y0.25245S，U420V，I R20A，I L0.2290A，IC1.2290A4-7I10245，AU S10090V4-8(a)30V；(b)2.24A4-9(a)10V；(b)10A4-10(a)10V；(b)10V4-11U=14.1V4-12U L1=15V，U C2=8V，U S=15.65V4-13U X1=100V，U2=600V，X1=10Ω，X2=20Ω，X3=30Ω4-14Z20245，I245A，I120A，I2290A，a b0VU4-15(1)I2A，Z RC52，Z510；(2)R10，X C104-16P=774.4W，Q=580.8var，S=968VA·4-17I1=5A，I2=4A4-18I1=1A，I2=2A，I526.565A，S44.7226.565VA4-19Z10，I190A，U R252135V，P10W4-20ω0=5×106rad/s，ρ=1000Ω，Q=100，I=2mA，U R=20mV，UL=U C=2V4-21ω0=104rad/s，ρ=100Ω，Q=100，U=10V，IR=1mA，I L=I C=100mA4-22L1=1H，L2≈0.33H第5章习题参考答案5-3M=35.5mH5-4ω01=1000rad/s，ω02=2236rad/s5-5Z1=j31.4Ω，Z2=j6.28Ω5-6Zr=3+7.5Ω5-7M=130mH5-8I2245A5-9U1=44.8V5-10M12=20mH，I1=4A5-11U2=220V，I1=4A5-12n=1.95-13N2=254匝，N3=72匝5-14n=10，P2=31.25mW第6章习题参考答案6-1(1)A相灯泡电压为零，B、C相各位为220V6-3IL=Ip=4.4A，U p=220V，UL=380V，P=2.3kW6-4(2)Ip=7.62A，IL=13.2A6-5A、C相各为2.2A，B相为3.8A6-6U L=404V6-7U AN20247V6-8cosφ=0.961，Q=5.75kvar6-9Z33.428.46-10(1)Ip=11.26A，Z=19.53∠42.3°Ω；(2)Ip=Il=11.26A，P=5.5kW 6-11U l=391V6-12i A222sin(t53.13)Ai B222sin(t173.13)Ai C222sin(t66.87)A6-13U V=160V6-14(1)负载以三角形方式接入三相电源(2)I AB3.8215A，I BC3.82135A，I CA3.82105AI A3.8645A，I B3.86165A，I C3.8675A6-15L=110mH，C=91.9mF第7章习题参考答案7-1P=240W，Q=360var7-2P=10.84W7-3(1)i(t)4.7sin(t100)3sin3tA(2)I≈3.94A，U≈58.84V，P≈93.02W7-4MUπLm1u(t)sin(tarctan)V2z2R，22zR(L)17-5直流电源中有交流，交流电源中无直流7-6U1=54.3V，R=1Ω，L=11.4mH；约为8%，（L’=12.33mH）7-7使总阻抗或总导纳为实数（虚部为0）的条件为R1R2R X L/C7-8C19.39μF，C275.13μF7-9L1=1H，L2=66.7mH7-10C1=10μF，C2=1.25μF第8章习题参考答案8-6iL(0+)＝1.5mA，uL(0+)＝-15V8-7i1(0+)＝4A，i2(0+)＝1A，u L(0+)＝2V，i1(∞)＝3A，i2(∞)＝0，u L(∞)＝0 8-8i1(0+)＝75mA，i2(0+)＝75mA，i3(0+)＝0，uL1(0+)＝0，uL2(0+)＝2.25V8-9 6 110ti C(t)2eA 8-10 4tu L (t)6eV8-11 6 110t u C (t)10(1e)V ， 6110t i C (t)5eA*8-12 500tu C (t)115esin(86660)V8-13 10t u L (t)12eV ， 10ti L(t)2(1e)A8-14 1 t RC u R (t)U S eV ， 23u R (3)U SeV 8-15(1)τ＝0.1s ，(2) 10tu C (t)10eV ，(3)t ＝0.1s8-16 5 10tu C (t)109eV8-17 10ti L (t)5eA8-18(a)f(t)1(tt 0)1(t2t 0)；(b)f(t)1(t)1(tt 0)[1(tt 0)1(t2t 0)]1(t)21(tt 0)1(t2t 0)8-19 0.5t0.5(t1)u C (t)[5(1e)1(t)5(1e)1(t-1)]V8-20u o 为三角波，峰值为±0.05V*8-21临界阻尼R=2 L C ，欠阻尼R<2 L C ，过阻尼R>2 LC*8-22 t1t2666 ti L (t)[(1e)1(t)(1e)1(t1)2(1e)1(t2)]。