多排脚手架计算书计算依据：1、《建筑施工脚手架安全技术统一标准》GB51210-20162、《建筑施工扣件式钢管脚手架安全技术规范》JGJ130-20113、《建筑结构荷载规范》GB50009-20124、《钢结构设计规范》GB50017-20035、《建筑地基基础设计规范》GB50007-2011一、脚手架参数二、荷载设计脚手架设计类型结构脚手架脚手板类型木脚手板脚手板自重标准值G kjb(kN/m2)0.35 脚手板铺设方式2步1设密目式安全立网自重标准值G kmw(kN/m2)0.01 挡脚板类型木挡脚板栏杆与挡脚板自重标准值G kdb(kN/m)0.17 挡脚板铺设方式2步1设每米立杆承受结构自重标准值g k(kN/m) 0.129 结构脚手架作业层数n jj1结构脚手架荷载标准值G kjj(kN/m2) 3 地区内蒙古锡林浩特市安全网设置全封闭基本风压ω0(kN/m2) 0.4风荷载体型系数μs 1 风压高度变化系数μz(连墙件、单立杆、双立杆稳定性) 1.06，0.796，0.65风荷载标准值ωk(kN/m2)(连墙件、0.424，0.318，0.26计算简图：立面图侧面图三、横向水平杆验算纵、横向水平杆布置取多排架中最大横距段作为最不利计算承载能力极限状态q=1.2×(0.04+G kjb×l a/(n+1))+1.4×G k×l a/(n+1)=1.2×(0 .04+0.35×1.2/(2+1))+1.4×3×1.2/(2+1)=1.896kN/m 正常使用极限状态q'=(0.04+G kjb×l a/(n+1))=(0.04+0.35×1.2/(2+1))=0.18k N/m计算简图如下：取前后立杆横距最大的那跨计算，并考虑在顶端处有横向水平杆外伸1、抗弯验算M max=max[ql b2/8，qa12/2]=max[1.896×1.22/8，1.896×0.152/2]=0.341kN·mσ=γ0M max/W=1×0.341×106/5260=64.87N/mm2≤[f]=205N/mm2满足要求！2、挠度验算νmax=max[5q'l b4/(384EI)，q'a14/(8EI)]=max[5×0.18×12004/(384×206000×127100)，0.18×1504/(8×206000×127100)]=0.185mmνmax＝0.185mm≤[ν]＝min[l b/150，10]＝min[1200/150，10]＝8mm满足要求！3、支座反力计算承载能力极限状态R max=q(l b+a1)2/(2l b)=1.896×(1.2+0.15)2/(2×1.2)=1.44kN 正常使用极限状态R max'=q'(l b+a1)2/(2l b)=0.18×(1.2+0.15)2/(2×1.2)=0.136 kN四、纵向水平杆验算承载能力极限状态由上节可知F1=R max=1.44kNq=1.2×0.04=0.048kN/m正常使用极限状态由上节可知F1'=R max'=0.136kNq'=0.04kN/m1、抗弯验算计算简图如下：弯矩图(kN·m)σ=γ0M max/W=1×0.467×106/5260=88.875N/mm2≤[f]=205N/ mm2满足要求！2、挠度验算计算简图如下：变形图(mm)νmax＝0.193mm≤[ν]＝min[l a/150，10]＝min[1200/150，10]＝8mm满足要求！3、支座反力计算承载能力极限状态R max=3.327kN五、扣件抗滑承载力验算扣件抗滑承载力验算：横向水平杆：R max=1×1.44kN≤R c=0.85×12=10.2kN纵向水平杆：R max=1×3.327kN≤R c=0.85×12=10.2kN 满足要求！六、荷载计算立杆静荷载计算1、立杆承受的结构自重标准值N G1k立杆一:N G1k=(gk+l b×n/2×0.04/h)×H=(0.129+1.2×2/2×0.04 /1.23)×10.7=1.795kN立杆二:单立杆N G1k=(gk+l b×n/2×0.04/h)×(H-h1)=(0.129+1.2×2/2×0.04/1.23)×(25-14)=1.845kN 双立杆N Gs1k=(gk+l b×n/2×0.04/h)×h1=(0.129+1.2×2/2×0.04/1 .23)×14=2.348kN立杆三:单立杆N G1k=(gk+l b×n/2×0.04/h)×(H-h1)=(0.129+1.2×2/2×0.04/1.23)×(25-14)=1.845kN 双立杆N Gs1k=(gk+l b×n/2×0.04/h)×h1=(0.129+1.2×2/2×0.04/1 .23)×14=2.348kN立杆四:单立杆N G1k=(gk+l b×n/2×0.04/h)×(H-h1)=(0.129+1.2×2/2×0.04/1.23)×(25-14)=1.845kN 双立杆N Gs1k=(gk+l b×n/2×0.04/h)×h1=(0.129+1.2×2/2×0.04/1 .23)×14=2.348kN立杆五:单立杆N G1k=(gk+l b×n/2×0.04/h)×(H-h1)=(0.129+1.2×2/2×0.04/1.23)×(25-14)=1.845kN双立杆N Gs1k=(gk+l b×n/2×0.04/h)×h1=(0.129+1.2×2/2×0.04/1 .23)×14=2.348kN立杆六:单立杆N G1k=(gk+l b×n/2×0.04/h)×(H-h1)=(0.129+1.2×2/2×0.04/1.23)×(25-14)=1.845kN 双立杆N Gs1k=(gk+l b×n/2×0.04/h)×h1=(0.129+1.2×2/2×0.04/1 .23)×14=2.348kN立杆七:单立杆N G1k=(gk+l b×n/2×0.04/h)×(H-h1)=(0.129+1.2×2/2×0.04/1.23)×(25-14)=1.845kN 双立杆N Gs1k=(gk+l b×n/2×0.04/h)×h1=(0.129+1.2×2/2×0.04/1 .23)×14=2.348kN立杆八:单立杆N G1k=(gk+l b×n/2×0.04/h)×(H-h1)=(0.129+1.2×2/2×0.04/1.23)×(25-14)=1.845kN 双立杆N Gs1k=(gk+l b×n/2×0.04/h)×h1=(0.129+1.2×2/2×0.04/1 .23)×14=2.348kN立杆九:单立杆N G1k=(gk+l b×n/2×0.04/h)×(H-h1)=(0.129+1.2×2/2×0.04/1.23)×(25-14)=1.845kN 双立杆N Gs1k=(gk+l b×n/2×0.04/h)×h1=(0.129+1.2×2/2×0.04/1 .23)×14=2.348kN立杆十:单立杆N G1k=(gk+l b×n/2×0.04/h)×(H-h1)=(0.129+1.2×2/2×0.04/1.23)×(25-14)=1.845kN 双立杆N Gs1k=(gk+l b×n/2×0.04/h)×h1=(0.129+1.2×2/2×0.04/1 .23)×14=2.348kN立杆十一:单立杆N G1k=(gk+l b×n/2×0.04/h)×(H-h1)=(0.129+1.2×2/2×0.04/1.23)×(25-14)=1.845kN 双立杆N Gs1k=(gk+l b×n/2×0.04/h)×h1=(0.129+1.2×2/2×0.04/1 .23)×14=2.348kN立杆十二:单立杆N G1k=(gk+l b×n/2×0.04/h)×(H-h1)=(0.129+1.2×2/2×0.04/1.23)×(25-14)=1.845kNN Gs1k=(gk+l b×n/2×0.04/h)×h1=(0.129+1.2×2/2×0.04/1 .23)×14=2.348kN立杆十三:单立杆N G1k=(gk+l b×n/2×0.04/h)×(H-h1)=(0.129+1.2×2/2×0.04/1.23)×(25-14)=1.845kN 双立杆N Gs1k=(gk+l b×n/2×0.04/h)×h1=(0.129+1.2×2/2×0.04/1 .23)×14=2.348kN2、脚手板的自重标准值N G2k1立杆一:N G2k1=(H/h+1)×l a×l b×G kjb×1/2/2=(10.7/1.23+1)×1.2×1.2×0.35×1/2/2=1.222kN立杆二:单立杆N G2k1=((H-h1)/h+1)×l a×l b×G kjb×1/2/1=((25-14)/1.23+1)×1.2×1.2×0.35×1/2/1=2.506kN双立杆N Gs2k1=(h1/h+1)×l a×l b×G kjb×1/2/1=(14/1.23+1)×1.2×1. 2×0.35×1/2/1=3.12kN立杆三:单立杆N G2k1=((H-h1)/h+1)×l a×l b×G kjb×1/2/1=((25-14)/1.23+1)×1.2×1.2×0.35×1/2/1=2.506kNN Gs2k1=(h1/h+1)×l a×l b×G kjb×1/2/1=(14/1.23+1)×1.2×1. 2×0.35×1/2/1=3.12kN立杆四:单立杆N G2k1=((H-h1)/h+1)×l a×l b×G kjb×1/2/1=((25-14)/1.23+1)×1.2×1.2×0.35×1/2/1=2.506kN双立杆N Gs2k1=(h1/h+1)×l a×l b×G kjb×1/2/1=(14/1.23+1)×1.2×1. 2×0.35×1/2/1=3.12kN立杆五:单立杆N G2k1=((H-h1)/h+1)×l a×l b×G kjb×1/2/1=((25-14)/1.23+1)×1.2×1.2×0.35×1/2/1=2.506kN双立杆N Gs2k1=(h1/h+1)×l a×l b×G kjb×1/2/1=(14/1.23+1)×1.2×1. 2×0.35×1/2/1=3.12kN立杆六:单立杆N G2k1=((H-h1)/h+1)×l a×l b×G kjb×1/2/1=((25-14)/1.23+1)×1.2×1.2×0.35×1/2/1=2.506kN双立杆N Gs2k1=(h1/h+1)×l a×l b×G kjb×1/2/1=(14/1.23+1)×1.2×1. 2×0.35×1/2/1=3.12kN立杆七:单立杆N G2k1=((H-h1)/h+1)×l a×l b×G kjb×1/2/1=((25-14)/1.23+1)×1.2×1.2×0.35×1/2/1=2.506kN双立杆N Gs2k1=(h1/h+1)×l a×l b×G kjb×1/2/1=(14/1.23+1)×1.2×1. 2×0.35×1/2/1=3.12kN立杆八:单立杆N G2k1=((H-h1)/h+1)×l a×l b×G kjb×1/2/1=((25-14)/1.23+1)×1.2×1.2×0.35×1/2/1=2.506kN双立杆N Gs2k1=(h1/h+1)×l a×l b×G kjb×1/2/1=(14/1.23+1)×1.2×1. 2×0.35×1/2/1=3.12kN立杆九:单立杆N G2k1=((H-h1)/h+1)×l a×l b×G kjb×1/2/1=((25-14)/1.23+1)×1.2×1.2×0.35×1/2/1=2.506kN双立杆N Gs2k1=(h1/h+1)×l a×l b×G kjb×1/2/1=(14/1.23+1)×1.2×1. 2×0.35×1/2/1=3.12kN立杆十:单立杆N G2k1=((H-h1)/h+1)×l a×l b×G kjb×1/2/1=((25-14)/1.23+1)×1.2×1.2×0.35×1/2/1=2.506kN双立杆N Gs2k1=(h1/h+1)×l a×l b×G kjb×1/2/1=(14/1.23+1)×1.2×1. 2×0.35×1/2/1=3.12kN立杆十一:单立杆N G2k1=((H-h1)/h+1)×l a×l b×G kjb×1/2/1=((25-14)/1.23+1)×1.2×1.2×0.35×1/2/1=2.506kN双立杆N Gs2k1=(h1/h+1)×l a×l b×G kjb×1/2/1=(14/1.23+1)×1.2×1. 2×0.35×1/2/1=3.12kN立杆十二:单立杆N G2k1=((H-h1)/h+1)×l a×l b×G kjb×1/2/1=((25-14)/1.23+1)×1.2×1.2×0.35×1/2/1=2.506kN双立杆N Gs2k1=(h1/h+1)×l a×l b×G kjb×1/2/1=(14/1.23+1)×1.2×1. 2×0.35×1/2/1=3.12kN立杆十三:单立杆N G2k1=((H-h1)/h+1)×l a×l b×G kjb×1/2/2=((25-14)/1.23+1)×1.2×1.2×0.35×1/2/2=1.253kN双立杆N Gs2k1=(h1/h+1)×l a×l b×G kjb×1/2/2=(14/1.23+1)×1.2×1. 2×0.35×1/2/2=1.56kN1/2表示脚手板2步1设3、栏杆与挡脚板自重标准值N G2k2立杆十三:单立杆N G2k2=((H-h1)/h+1)×l a×G kdb×1/2=((25-14)/1.23+1)×1.2×0.17×1/2=1.014kN双立杆N Gs2k2=(h1/h+1)×l a×G kdb×1/2=(14/1.23+1)×1.2×0.17×1 /2=1.263kN1/2表示挡脚板2步1设4、围护材料的自重标准值N G2k3立杆十三:单立杆N G2k3=G kmw×l a×(H-h1)=0.01×1.2×(25-14)=0.132kN双立杆N Gs2k3=G kmw×l a×h1=0.01×1.2×14=0.168kN5、立杆自重标准值N Gk总计立杆一:N Gk=N G1k+N G2k1=1.795+1.222=3.017kN立杆二:单立杆N Gk=N G1k+N G2k1=1.845+2.506=4.351kN双立杆N Gsk=N Gs1k+N Gs2k1=2.348+3.12=5.469kN立杆三:单立杆N Gk=N G1k+N G2k1=1.845+2.506=4.351kN双立杆N Gsk=N Gs1k+N Gs2k1=2.348+3.12=5.469kN立杆四:单立杆N Gk=N G1k+N G2k1=1.845+2.506=4.351kN 双立杆N Gsk=N Gs1k+N Gs2k1=2.348+3.12=5.469kN 立杆五:单立杆N Gk=N G1k+N G2k1=1.845+2.506=4.351kN 双立杆N Gsk=N Gs1k+N Gs2k1=2.348+3.12=5.469kN 立杆六:单立杆N Gk=N G1k+N G2k1=1.845+2.506=4.351kN 双立杆N Gsk=N Gs1k+N Gs2k1=2.348+3.12=5.469kN 立杆七:单立杆N Gk=N G1k+N G2k1=1.845+2.506=4.351kN 双立杆N Gsk=N Gs1k+N Gs2k1=2.348+3.12=5.469kN 立杆八:单立杆N Gk=N G1k+N G2k1=1.845+2.506=4.351kN 双立杆N Gsk=N Gs1k+N Gs2k1=2.348+3.12=5.469kN 立杆九:单立杆N Gk=N G1k+N G2k1=1.845+2.506=4.351kN 双立杆N Gsk=N Gs1k+N Gs2k1=2.348+3.12=5.469kN 立杆十:单立杆N Gk=N G1k+N G2k1=1.845+2.506=4.351kN 双立杆N Gsk=N Gs1k+N Gs2k1=2.348+3.12=5.469kN立杆十一:单立杆N Gk=N G1k+N G2k1=1.845+2.506=4.351kN双立杆N Gsk=N Gs1k+N Gs2k1=2.348+3.12=5.469kN立杆十二:单立杆N Gk=N G1k+N G2k1=1.845+2.506=4.351kN双立杆N Gsk=N Gs1k+N Gs2k1=2.348+3.12=5.469kN立杆十三:单立杆N Gk=N G1k+N G2k1+N G2k2+N G2k3=1.845+1.253+1.014+0.132=4.244kN 双立杆N Gsk=N Gs1k+N Gs2k1+N Gs2k2+N Gs2k3=2.348+1.56+1.263+0.168=5.339kN 6、立杆施工活荷载计算立杆一：N Q1k=l a×l b×(n jj×G kjj)/2=1.2×1.2×(1×3)/2=2.16kN 立杆二：N Q1k=l a×l b×(n jj×G kjj)/1=1.2×1.2×(1×3)/1=4.32kN 立杆三：N Q1k=l a×l b×(n jj×G kjj)/1=1.2×1.2×(1×3)/1=4.32kN 立杆四：N Q1k=l a×l b×(n jj×G kjj)/1=1.2×1.2×(1×3)/1=4.32kNN Q1k=l a×l b×(n jj×G kjj)/1=1.2×1.2×(1×3)/1=4.32kN 立杆六：N Q1k=l a×l b×(n jj×G kjj)/1=1.2×1.2×(1×3)/1=4.32kN 立杆七：N Q1k=l a×l b×(n jj×G kjj)/1=1.2×1.2×(1×3)/1=4.32kN 立杆八：N Q1k=l a×l b×(n jj×G kjj)/1=1.2×1.2×(1×3)/1=4.32kN 立杆九：N Q1k=l a×l b×(n jj×G kjj)/1=1.2×1.2×(1×3)/1=4.32kN 立杆十：N Q1k=l a×l b×(n jj×G kjj)/1=1.2×1.2×(1×3)/1=4.32kN 立杆十一：N Q1k=l a×l b×(n jj×G kjj)/1=1.2×1.2×(1×3)/1=4.32kN 立杆十二：N Q1k=l a×l b×(n jj×G kjj)/1=1.2×1.2×(1×3)/1=4.32kN 立杆十三：N Q1k=l a×l b×(n jj×G kjj)/2=1.2×1.2×(1×3)/2=2.16kN 组合风荷载作用下单立杆轴向力：立杆一:N=1.2×N Gk+1.4×N Q1k=1.2×3.017+1.4×2.16=6.644kN单立杆N单=1.2×N Gk+1.4×N Q1k=1.2×4.351+1.4×4.32=11.269kN 双立杆N双=1.2×N Gk+1.4×N Q1k=1.2×5.469+1.4×4.32=12.61kN 立杆三:单立杆N单=1.2×N Gk+1.4×N Q1k=1.2×4.351+1.4×4.32=11.269kN 双立杆N双=1.2×N Gk+1.4×N Q1k=1.2×5.469+1.4×4.32=12.61kN 立杆四:单立杆N单=1.2×N Gk+1.4×N Q1k=1.2×4.351+1.4×4.32=11.269kN 双立杆N双=1.2×N Gk+1.4×N Q1k=1.2×5.469+1.4×4.32=12.61kN 立杆五:单立杆N单=1.2×N Gk+1.4×N Q1k=1.2×4.351+1.4×4.32=11.269kN 双立杆N双=1.2×N Gk+1.4×N Q1k=1.2×5.469+1.4×4.32=12.61kN 立杆六:=1.2×N Gk+1.4×N Q1k=1.2×4.351+1.4×4.32=11.269kN 双立杆N双=1.2×N Gk+1.4×N Q1k=1.2×5.469+1.4×4.32=12.61kN 立杆七:单立杆N单=1.2×N Gk+1.4×N Q1k=1.2×4.351+1.4×4.32=11.269kN 双立杆N双=1.2×N Gk+1.4×N Q1k=1.2×5.469+1.4×4.32=12.61kN 立杆八:单立杆N单=1.2×N Gk+1.4×N Q1k=1.2×4.351+1.4×4.32=11.269kN 双立杆N双=1.2×N Gk+1.4×N Q1k=1.2×5.469+1.4×4.32=12.61kN 立杆九:单立杆N单=1.2×N Gk+1.4×N Q1k=1.2×4.351+1.4×4.32=11.269kN 双立杆N双=1.2×N Gk+1.4×N Q1k=1.2×5.469+1.4×4.32=12.61kN 立杆十:=1.2×N Gk+1.4×N Q1k=1.2×4.351+1.4×4.32=11.269kN 双立杆N双=1.2×N Gk+1.4×N Q1k=1.2×5.469+1.4×4.32=12.61kN 立杆十一:单立杆N单=1.2×N Gk+1.4×N Q1k=1.2×4.351+1.4×4.32=11.269kN 双立杆N双=1.2×N Gk+1.4×N Q1k=1.2×5.469+1.4×4.32=12.61kN 立杆十二:单立杆N单=1.2×N Gk+1.4×N Q1k=1.2×4.351+1.4×4.32=11.269kN 双立杆N双=1.2×N Gk+1.4×N Q1k=1.2×5.469+1.4×4.32=12.61kN 立杆十三:单立杆N单=1.2×N Gk+1.4×N Q1k=1.2×4.244+1.4×2.16=8.117kN 双立杆N双=1.2×N Gk+1.4×N Q1k=1.2×5.339+1.4×2.16=9.431kN 七、立杆稳定性验算1、立杆长细比验算立杆计算长度l0=Kμh=1×1.5×1.23=1.845m长细比λ=l0/i=1.845×103/15.9=116.038≤250满足要求！轴心受压构件的稳定系数计算：立杆稳定性系数计算计算长度附加系数k 计算长度l i=k iμh(m)λ=l i/i φi值1 1.155 2.131 134.024 0.3762 1.191 2.197 138.201 0.3573 1.191 2.197 138.201 0.3574 1.191 2.197 138.201 0.3575 1.191 2.197 138.201 0.3576 1.191 2.197 138.201 0.3577 1.191 2.197 138.201 0.3578 1.191 2.197 138.201 0.3579 1.191 2.197 138.201 0.35710 1.191 2.197 138.201 0.35711 1.191 2.197 138.201 0.35712 1.191 2.197 138.201 0.35713 1.191 2.197 138.201 0.3572、立杆稳定性验算组合风荷载作用由上计算可知各排立杆轴向力N立杆一:N=1.2×N Gk+1.4×N Q1k=1.2×3.017+1.4×2.16=6.644kNM wd=φwγQ M wk=φwγQ(0.05ζ1w k l a H12)=0.6×1.4×(0.05×0.6×0.318×1.2×2.462)=0.058kN·mσ=γ0[N/(φA)+M wd/w]=1×[6644.192/(0.376×506)+58194 .122/5260]=45.986N/mm2≤[f]=205N/mm2满足要求！立杆二:单立杆N单=1.2×N Gk+1.4×N Q1k=1.2×4.351+1.4×4.32=11.269kNM wd=φwγQ M wk=φwγQ(0.05ζ1w k l a H12)=0.6×1.4×(0.05×0.6×0.318×1.2×2.462)=0.058kN·mσ=γ0[N/(φA)+M wd/w]=1×[11268.849/(0.357×506)+5819 4.122/5260]=73.446N/mm2≤[f]=205N/mm2满足要求！双立杆N s=1.2×N Gk+N单=1.2×5.469+11.269=17.831kNM wd=φwγQ M wk=φwγQ(0.05ζ1w k l a H12)=0.6×1.4×(0.05×0.6×0.26×1.2×2.462)=0.048kN·mσ=γ0K s[N/(φA)+M wd/w]=1×0.6×[17831.093/(0.357×50 6)+47580.1/5260]=64.653N/mm2≤[f]=205N/mm2满足要求！立杆三:单立杆N单=1.2×N Gk+1.4×N Q1k=1.2×4.351+1.4×4.32=11.269kNM wd=φwγQ M wk=φwγQ(0.05ζ1w k l a H12)=0.6×1.4×(0.05×0.6×0.318×1.2×2.462)=0.058kN·mσ=γ0[N/(φA)+M wd/w]=1×[11268.849/(0.357×506)+5819 4.122/5260]=73.446N/mm2≤[f]=205N/mm2满足要求！双立杆N s=1.2×N Gk+N单=1.2×5.469+11.269=17.831kNM wd=φwγQ M wk=φwγQ(0.05ζ1w k l a H12)=0.6×1.4×(0.05×0.6×0.26×1.2×2.462)=0.048kN·mσ=γ0K s[N/(φA)+M wd/w]=1×0.6×[17831.093/(0.357×50 6)+47580.1/5260]=64.653N/mm2≤[f]=205N/mm2满足要求！立杆四:单立杆N单=1.2×N Gk+1.4×N Q1k=1.2×4.351+1.4×4.32=11.269kNM wd=φwγQ M wk=φwγQ(0.05ζ1w k l a H12)=0.6×1.4×(0.05×0.6×0.318×1.2×2.462)=0.058kN·mσ=γ0[N/(φA)+M wd/w]=1×[11268.849/(0.357×506)+5819 4.122/5260]=73.446N/mm2≤[f]=205N/mm2满足要求！双立杆N s=1.2×N Gk+N单=1.2×5.469+11.269=17.831kNM wd=φwγQ M wk=φwγQ(0.05ζ1w k l a H12)=0.6×1.4×(0.05×0.6×0.26×1.2×2.462)=0.048kN·mσ=γ0K s[N/(φA)+M wd/w]=1×0.6×[17831.093/(0.357×50 6)+47580.1/5260]=64.653N/mm2≤[f]=205N/mm2满足要求！立杆五:单立杆N单=1.2×N Gk+1.4×N Q1k=1.2×4.351+1.4×4.32=11.269kNM wd=φwγQ M wk=φwγQ(0.05ζ1w k l a H12)=0.6×1.4×(0.05×0.6×0.318×1.2×2.462)=0.058kN·mσ=γ0[N/(φA)+M wd/w]=1×[11268.849/(0.357×506)+5819 4.122/5260]=73.446N/mm2≤[f]=205N/mm2满足要求！双立杆N s=1.2×N Gk+N单=1.2×5.469+11.269=17.831kNM wd=φwγQ M wk=φwγQ(0.05ζ1w k l a H12)=0.6×1.4×(0.05×0.6×0.26×1.2×2.462)=0.048kN·mσ=γ0K s[N/(φA)+M wd/w]=1×0.6×[17831.093/(0.357×50 6)+47580.1/5260]=64.653N/mm2≤[f]=205N/mm2满足要求！立杆六:单立杆N单=1.2×N Gk+1.4×N Q1k=1.2×4.351+1.4×4.32=11.269kNM wd=φwγQ M wk=φwγQ(0.05ζ1w k l a H12)=0.6×1.4×(0.05×0.6×0.318×1.2×2.462)=0.058kN·mσ=γ0[N/(φA)+M wd/w]=1×[11268.849/(0.357×506)+5819 4.122/5260]=73.446N/mm2≤[f]=205N/mm2满足要求！双立杆N s=1.2×N Gk+N单=1.2×5.469+11.269=17.831kNM wd=φwγQ M wk=φwγQ(0.05ζ1w k l a H12)=0.6×1.4×(0.05×0.6×0.26×1.2×2.462)=0.048kN·mσ=γ0K s[N/(φA)+M wd/w]=1×0.6×[17831.093/(0.357×50 6)+47580.1/5260]=64.653N/mm2≤[f]=205N/mm2满足要求！立杆七:单立杆N单=1.2×N Gk+1.4×N Q1k=1.2×4.351+1.4×4.32=11.269kNM wd=φwγQ M wk=φwγQ(0.05ζ1w k l a H12)=0.6×1.4×(0.05×0.6×0.318×1.2×2.462)=0.058kN·mσ=γ0[N/(φA)+M wd/w]=1×[11268.849/(0.357×506)+5819 4.122/5260]=73.446N/mm2≤[f]=205N/mm2满足要求！双立杆N s=1.2×N Gk+N单=1.2×5.469+11.269=17.831kNM wd=φwγQ M wk=φwγQ(0.05ζ1w k l a H12)=0.6×1.4×(0.05×0.6×0.26×1.2×2.462)=0.048kN·mσ=γ0K s[N/(φA)+M wd/w]=1×0.6×[17831.093/(0.357×50 6)+47580.1/5260]=64.653N/mm2≤[f]=205N/mm2满足要求！立杆八:单立杆N单=1.2×N Gk+1.4×N Q1k=1.2×4.351+1.4×4.32=11.269kNM wd=φwγQ M wk=φwγQ(0.05ζ1w k l a H12)=0.6×1.4×(0.05×0.6×0.318×1.2×2.462)=0.058kN·mσ=γ0[N/(φA)+M wd/w]=1×[11268.849/(0.357×506)+5819 4.122/5260]=73.446N/mm2≤[f]=205N/mm2满足要求！双立杆N s=1.2×N Gk+N单=1.2×5.469+11.269=17.831kNM wd=φwγQ M wk=φwγQ(0.05ζ1w k l a H12)=0.6×1.4×(0.05×0.6×0.26×1.2×2.462)=0.048kN·mσ=γ0K s[N/(φA)+M wd/w]=1×0.6×[17831.093/(0.357×50 6)+47580.1/5260]=64.653N/mm2≤[f]=205N/mm2满足要求！立杆九:单立杆N单=1.2×N Gk+1.4×N Q1k=1.2×4.351+1.4×4.32=11.269kNM wd=φwγQ M wk=φwγQ(0.05ζ1w k l a H12)=0.6×1.4×(0.05×0.6×0.318×1.2×2.462)=0.058kN·mσ=γ0[N/(φA)+M wd/w]=1×[11268.849/(0.357×506)+5819 4.122/5260]=73.446N/mm2≤[f]=205N/mm2满足要求！双立杆N s=1.2×N Gk+N单=1.2×5.469+11.269=17.831kNM wd=φwγQ M wk=φwγQ(0.05ζ1w k l a H12)=0.6×1.4×(0.05×0.6×0.26×1.2×2.462)=0.048kN·mσ=γ0K s[N/(φA)+M wd/w]=1×0.6×[17831.093/(0.357×50 6)+47580.1/5260]=64.653N/mm2≤[f]=205N/mm2满足要求！立杆十:单立杆N单=1.2×N Gk+1.4×N Q1k=1.2×4.351+1.4×4.32=11.269kNM wd=φwγQ M wk=φwγQ(0.05ζ1w k l a H12)=0.6×1.4×(0.05×0.6×0.318×1.2×2.462)=0.058kN·mσ=γ0[N/(φA)+M wd/w]=1×[11268.849/(0.357×506)+5819 4.122/5260]=73.446N/mm2≤[f]=205N/mm2满足要求！双立杆N s=1.2×N Gk+N单=1.2×5.469+11.269=17.831kNM wd=φwγQ M wk=φwγQ(0.05ζ1w k l a H12)=0.6×1.4×(0.05×0.6×0.26×1.2×2.462)=0.048kN·mσ=γ0K s[N/(φA)+M wd/w]=1×0.6×[17831.093/(0.357×50 6)+47580.1/5260]=64.653N/mm2≤[f]=205N/mm2满足要求！立杆十一:单立杆N单=1.2×N Gk+1.4×N Q1k=1.2×4.351+1.4×4.32=11.269kNM wd=φwγQ M wk=φwγQ(0.05ζ1w k l a H12)=0.6×1.4×(0.05×0.6×0.318×1.2×2.462)=0.058kN·mσ=γ0[N/(φA)+M wd/w]=1×[11268.849/(0.357×506)+5819 4.122/5260]=73.446N/mm2≤[f]=205N/mm2满足要求！双立杆N s=1.2×N Gk+N单=1.2×5.469+11.269=17.831kNM wd=φwγQ M wk=φwγQ(0.05ζ1w k l a H12)=0.6×1.4×(0.05×0.6×0.26×1.2×2.462)=0.048kN·mσ=γ0K s[N/(φA)+M wd/w]=1×0.6×[17831.093/(0.357×50 6)+47580.1/5260]=64.653N/mm2≤[f]=205N/mm2满足要求！立杆十二:单立杆N单=1.2×N Gk+1.4×N Q1k=1.2×4.351+1.4×4.32=11.269kNM wd=φwγQ M wk=φwγQ(0.05ζ1w k l a H12)=0.6×1.4×(0.05×0.6×0.318×1.2×2.462)=0.058kN·mσ=γ0[N/(φA)+M wd/w]=1×[11268.849/(0.357×506)+5819 4.122/5260]=73.446N/mm2≤[f]=205N/mm2满足要求！双立杆N s=1.2×N Gk+N单=1.2×5.469+11.269=17.831kNM wd=φwγQ M wk=φwγQ(0.05ζ1w k l a H12)=0.6×1.4×(0.05×0.6×0.26×1.2×2.462)=0.048kN·mσ=γ0K s[N/(φA)+M wd/w]=1×0.6×[17831.093/(0.357×50 6)+47580.1/5260]=64.653N/mm2≤[f]=205N/mm2满足要求！立杆十三:单立杆N单=1.2×N Gk+1.4×N Q1k=1.2×4.244+1.4×2.16=8.117kNM wd=φwγQ M wk=φwγQ(0.05ζ1w k l a H12)=0.6×1.4×(0.05×0.6×0.318×1.2×2.462)=0.058kN·mσ=γ0[N/(φA)+M wd/w]=1×[8116.888/(0.357×506)+58194 .122/5260]=55.997N/mm2≤[f]=205N/mm2满足要求！双立杆N s=1.2×N Gk+N单=1.2×5.339+8.117=14.524kNM wd=φwγQ M wk=φwγQ(0.05ζ1w k l a H12)=0.6×1.4×(0.05×0.6×0.26×1.2×2.462)=0.048kN·mσ=γ0K s[N/(φA)+M wd/w]=1×0.6×[14524.127/(0.357×50 6)+47580.1/5260]=53.669N/mm2≤[f]=205N/mm2满足要求！3、立杆底部轴力标准值计算立杆一：恒载标准值F G1=3.017kN，活载标准值F Q1=2.16kN立杆二：恒载标准值F G2=9.819kN，活载标准值F Q2=4.32kN立杆三：恒载标准值F G3=9.819kN，活载标准值F Q3=4.32kN立杆四：恒载标准值F G4=9.819kN，活载标准值F Q4=4.32kN立杆五：恒载标准值F G5=9.819kN，活载标准值F Q5=4.32kN立杆六：恒载标准值F G6=9.819kN，活载标准值F Q6=4.32kN立杆七：恒载标准值F G7=9.819kN，活载标准值F Q7=4.32kN立杆八：恒载标准值F G8=9.819kN，活载标准值F Q8=4.32kN立杆九：恒载标准值F G9=9.819kN，活载标准值F Q9=4.32kN立杆十：恒载标准值F G10=9.819kN，活载标准值F Q10=4.32kN立杆十一：恒载标准值F G11=9.819kN，活载标准值F Q11=4.32kN立杆十二：恒载标准值F G12=9.819kN，活载标准值F Q12=4.32kN立杆十三：恒载标准值F G13=9.583kN，活载标准值F Q13=2.16kN八、连墙件承载力验算N lw=1.4×ωk×2×h×2×l a=1.4×0.424×2×1.23×2×1.2 =3.505kN长细比λ=l0/i=600/15.9=37.736，查《规范》表A.0.6得，φ=0.896(N lw+N0)/(φAc)=(3.505+3)×103/(0.896×506)=14.348N/m m2≤0.85×[f]=0.85×205N/mm2=174.25N/mm2满足要求！扣件抗滑承载力验算：N lw+N0=3.505+3=6.505kN≤0.85×12=10.2kN满足要求！九、立杆地基承载力验算立柱底垫板的底面平均压力p＝N/(m f A)＝17.831/(0.4×0.25)＝178.311kPa≤γu f g＝1.254×300 =376.2kPa满足要求！。