电工电子学课后习题答案目录电工电子学课后习题答案 (1)第一章电路的基本概念、定律与分析方法 (1)练习与思考 (1)习题 (4)第二章正弦交流电 (14)课后习题 (14)第三章电路的暂态分析 (29)第四章常用半导体器件 (41)第五章基本放大电路 (43)第六章集成运算放大器及其应用 (46)第七章数字集成电路及其应用 (54)第八章Multisim简介及其应用 (65)第九章波形的产生与变换 (65)第十章数据采集系统 (67)第十一章直流稳压电源 (69)第十二章变压器与电动机 (71)第十三章电气控制技术 (77)第十四章电力电子技术 (80)第一章电路的基本概念、定律与分析方法练习与思考1.4.2（b）a1.4.2(c)ab 1.4.3（a）b552155ababUVR=+⨯==Ω1.4.3 (b)ab666426ababU VR=+⨯==Ω1.4.3 (c)abR106510405ababU U VR=+=⨯+==Ω1.4.3 (d)ab124s su uI= I=912:23036absababKVL uuu VRI+- I==-6⨯=+1=3Ω3+61.4.4 (2)R242434311515155b bb bV V R R V V R R --I =I =-+I = I =12341243:b b b b b KCL V V V V R R R R V I =I +I +I +515-6- 5- = + +求方程中2121+9+9==50k 100k 9:=150k 100kb b b b b b b V V V V R R V V KCL V V 6-6-I =I = 6-+=b :650KI+100KI 9=01100KI=15 I=A10k 1=650k =1V10k KVL V -+--⨯习题1.1 （a ） 5427x A I =+-= （b ） 10.40.70.3x A I =-=- 20.30.20.20.1x A I =-++= (C) 40.230x ⨯I ==0.1A 6030.20.10.3x AI =+=2x 10⨯0.3+0.2⨯30I ==0.6A 1.510.30.60.9x A I =+=1.230.010.30.31A I =+=49.610.319.3A I =-=60.39.39.6AI =+=1.3114228P =-⨯=-ω发出功率211010P =⨯=ω 吸收功率 3428P =⨯=ω 吸收功率 4(110)10P =--⨯=ω 吸收功率=28=28P P ωω发吸=P P 吸发1.6612050606()12460120R R R mvV b V=== =⨯=+Ω（a) u u1.7（a ）144s u V =⨯=(b) 252209s s s I A u u V = -+-⨯= = 1.812221014102110s s u V I A=⨯+==-=-121428P =-⨯=-ω 210110P =-⨯(-)=ω1.91230.450.30.450.30.15I A I A I A= = =-=1233 6.341680.1510 6.34 6.3174.40.45x y u R I R ⨯===-⨯-==ΩΩ1.10(a): 2116u u V ==(b): 2516 1.6455u V =⨯=+ (c): 251.60.16455u V =⨯=+(d): 250.160.016455u V=⨯=+1.112211128.41p pR R u u VR R R +==++222112 5.64p R u u VR R R ==++1.12B A 630.563=0.51990.5199.5CD D D R R R ⨯==+=+=ΩΩΩ12342311055235 4.23.60.650.83.6I mA I mA I mA I mA I I =⨯= = =⨯==⨯==- 10199.5 1.995=15=510 1.9950.01995AD BD s u mV u mVP =⨯=⨯=-⨯=-ω1.13 (a)RAB(b)AB1.153Ω1.5Ω1.5611.53I A -==-+1.162Ω3Ω3I311302451010110532110202121621633311633s I A I I I I A I A I A I A+==+++=-=-==--=-=-+==⨯=+=⨯=+1.17Ω821222I A-==++1.181231113333222:00I I I KVL u I R I R I R I R u += -++= --+=12316622757575I I I ==0.213 ==0.08 ==0.2931.191321232123218:14020606041012n I I I KVL I I I I I A I A I A=+=+ -++= 5-== = =1122208066014045606018108u I Vu I VP P ==== =-⨯=-ω =-⨯=-ω 电压源发出功率电流源发出功率1.201212221232+10:0.81201160.400.4116408.759.37528.125n I I IKVL I I I I I A I A I A=+= -+-= -+== = =22120:1209.3751125116:120160.75101510:10428.1251175:28.12543078.125L V P V P A P R P I R =-⨯=-ω=-⨯=-ω =-⨯⨯=-ω ==⨯=-ω1.21122212220.523133427I I V V I V I V +=----====1.22suR R212460.14020s u I AR R ===++R sI 2422240.10.10.2200.30.14020s I A R I I AR R =+==⨯=⨯=++1.2331110.250.50.5111I A=⨯=+++sI3231120.50.50.5120.250.50.75I AI A =⨯⨯=++=+=1.24 (a)1231223123:01:2130120202:21204015,10,25KCL I I I KVL I I KVL I I I A I A I A++= -+-= --== = =-(b)开关合在b 点时，求出20V 电压源单独作用时的各支路电流：2Ω''1'2'3204422442206224202222442I AI AI A=-⨯=-+//+==+//=-⨯=-+//+所以开关在b 点时，各支路电流为：123154111061625227I A I A I A=-==+==--=-1.25（b ）等效变换3AAAB(3 2.5)211ab U V=+⨯=（c ）等效变换abb4A(42) 1.59ab U V=+⨯=1.26 戴维宁:1220110225122110255015a ab L u V R I A=⨯===⨯=+Ω诺顿：22022505252225225255015ab ab L I A R I A ====⨯=+Ω1.28(1) 求二端网络的开路电压：10410242ab U I V ⨯=-=-=10410242ab U I V ⨯=-=-=(2)求二端网络的等效内阻（电压源短路、电流源开路）24ab R R Ω==(3)得到戴维南等效电路+1R abU abR1120.15413ab ab U I A A R R ∴==≈+1.32 （a ）1231235050105205050105201007A A AA A AA I I I V V VI I I V V V V V=+-+===-+=+=- 2.3.2(a) 取电源为参考向量2()tan 6031=232R=3c C cC C U I R U I jX IR RIX X X X fc fc ••••==-====π∴π又 （b ）2()tan 603=23R=32c R CL L U I jX U I RIRIX X X fL fL••••0==∴==∴= π∴π又第二章 正弦交流电课后习题 2.3.2(a) 取电源为参考向量60ο2U •RU •U •I•2()tan 6031=232R=3c C cC C U I R U I jX IR R IX X X X fc fc ••••==-====π∴π又（b ）RU •2U •1U •I •60ο2()tan 603=23R=32c R CL L U I jX U I RIRIX X X fL fL••••0==∴==∴= π∴π又习题2.2111122334455,10sin(100045)45554510sin(100045)5513510sin(1000135)5513510sin(1000135)I j I i t A I AI j Ai t A I j A i t A I j A i t A•00•00•00•00=+ =∴=+==-=-=-=-+==+=--=-=-2.3（1）1••12126306308arctan =536=+=10)U V U V U U U V u t V••00•••00=∠ =∠ϕ= ∠83=ω+83(2)1210301060arctan1=45(4530)7520sin(75)I A I A I A i t A••00•0000=∠- =∠ ϕ= ∴=-+=-=ω-2.4(a) 以电流I•为参考向量•RU •10arctan =451014.145U V U V•0ϕ= ===（b ）以电流I•为参考向量CRU ••22280C RC U U U U V=+∴==1122sin()sin(90)sin(45)u t i t A i t A 00=ω=ω+=ω-(c) 以电流I•为参考方向•C(200100)9010090100U V U V•00=-∠=∠=（d ）以电压U•为参考方向I••RI•LI •3L I I A =∴==（e ） 以电压U•为参考方向•RI I •7.07I A ===（f ）以电压U•为参考方向•I •18L CL C I I I I I I A =-∴=+=2.5 （1）3)70,2314/31.470314100219.80309.9sin()310C L L L C L I t AI A f rad s X L U I j L V Vu t V•0••0-000=ω=∠ ω=π==ω=Ω=ω=∠⨯⨯⨯10∠90=∠9=ω+90（2）3309.9sin()3101274314100L L L Lu t V U I AL X 0-=ω+90===ω⨯⨯102.6 (1)6220022011796.22 3.1402200.28796.20.280.39sin()c c C c C c C c U V U VX C U I AX I i t A•0-•0=∠ ====Ωω⨯⨯5⨯4⨯10 ====∠90=ω+90(2)0.10796.279.6c U V•000=∠-6⨯∠-90⨯=∠-1502.9 (1))22002314/)100u t V U Vf rad s i t A I A0•00•0=ω+30=∠3ω=π==ω-30=∠-3（2）22002201110060.7250L UZ I X L mH•00•0∠3===∠6=+Ω∠-3∴===ωπ⨯（3）00220102200cos 22010cos601100sin 2200sin 601905varS UI V AP UI W ==⨯=•=ϕ=⨯⨯=ϕ=ϕ=⨯=2.10(1)2u电容两端f=HZ |Z |=2000Ω 1000以1I•为参考向量=-601cos 212sin 217072110.1c c cR k K X k X c uF c X ϕ=|Z |ϕ=⨯=Ω=-|Z |ϕ=-⨯(-=Ω=∴==ωω（2）电阻两端1U •U 2R U U ••=1I•c =-30cos =2k 1X =sin =-2K =210.16R c uFc ϕ=|Z |ϕΩ|Z |ϕΩ==ω—（—）10002.12CLCZ=R+(X )10VL C R X j U -=Ω=∣Z∣I =10⨯1=102.1300000006V 1002020)3000.47sin(100020)10000.4400100200.25400900.35sin(100070)11500C 100021010020R L L L L C c C U U Vu t i R t X L U I A jX i t A X U I jX •••-••=∣Z∣I =10⨯1=10=∠+===+=ω=⨯=Ω∠===∠-70∠=-===Ωω⨯⨯∠==-0000.20500900.28sin(1000110)c A i t A =∠11∠-=+000001111111()300400500.0030.00050.003991000.33300L cZ R jX jX j j j U I AZ ••=++- =+-+ =-=∠-∴Z =300∠∠20∴===∠11∠92.14U •以为参考向量I •LI •13022101010101045C L C LC L R RR C C C R C X X I I I I I I I UI A U RVRU RI I AX X I I I A I ••••••••=∴=∴=++=== ======+=∠∴=2.15(1)601301000251030405053CZ R jX j j -=- =-⨯⨯⨯ =-Ω=∠-Ω(2)000000000001000t-30V 1030()103040304090400120120)103050535008383)R S s C s C C s u i R I AU I jX Vu t VU I Z Vu t V •••••===∠-=-=∠-⨯∠-⨯∠- =∠-=-==∠-⨯∠-=∠-=-（）（3）00300103000400104000500105000cos -53=3009sin -53=-3993VarR S C C S S P U I WQ Q U I Var S UI V A P S W Q S ==⨯===-=-⨯=-==⨯=•==（）（）2.18U •U •222824123430.3108(12)(12)10681.5111=X 0.067=0.022C 10 1.510 4.5R L R L C C C C CC C U R I U L I L HU U U U U jU U V VU X I C F F ••••===Ωω===Ω===++ =+-∴8+-=∴= == 4.5Ω ==ω⨯⨯或1或或2.19 (a) (1)(2)10361823691243537j j Z j j j jj j j j ⨯-===Ω+Z =4-4-+ =-=∠-Ω0000010002000300040041000420100237537237483723749085323719025323729041274127 1.3337339041270.67376690U I A Z U V U V U V U V U I A j U I Aj ••••••••••∠===∠∠-=∠⨯=∠=∠⨯∠-=∠-=∠⨯∠-=∠-=∠⨯∠=∠∠===∠∠∠===∠∠(3)0cos 102cos(37)16P UI W =ϕ=⨯⨯-=(b) (1)10(4)(6)242.436102 2.443537j j Z j j j j j j j j ---===-Ω---Z =3.4+4+- =+=∠Ω(2)0000001002000300040041000420100237537237490237237483723790453237 2.490 4.81274.8127 1.2374904.81270.8376690U I A Z U V U V U V U V U I A j U I A j ••••••••••∠===∠-∠=∠-⨯3.∠=∠-=∠-⨯=∠-=∠-⨯2∠=∠=∠-⨯∠-=∠-∠-===∠--4∠-∠-===∠--∠-(3)0cos 102cos(37)16P UI W=ϕ=⨯⨯=2.2001221201115545(55)105-5)10100==10AZ 10A 10AZ=10+1045Z 141.4Z j j j Z j j U I j U I V V=-=-Ω-⨯10==Ω+∴=||∴=Ω∴=||==（读数为读数为2.23426014411111010101()11451()1222101011 1.50.5C L X C j j Z jj j X L Z j Z j-===Ωω⨯⨯⨯--===-=-+--=ω=⨯=Ω=++=-2.240000000100.5229010110.5110.5 1.1(10.5)22+2(10.5)2211+2212123 3.61c c c c R c R R L R L c U I A j U I AR I I I j A A U I R j j VU I j j j j j VU U U U j j j V P UI •••••••••••••••∠===∠90-∠-∠===∠0=+=∠90+∠0=+ =∠26.6==+⨯= ==+=-=- =++=+-++=+=∠56.3 =00os 3.61 1.1cos(W ϕ=⨯⨯56.3 -26.6)=3.452.29110012122 1.21cos cos =0.5112206024.5(tan -tan 1.21(1.7320.456)=10222 3.14502201 4.54220380 4.541727.3sin 177.3-=-VarR P KP UI UI PC U K uFP K I A U S UI V A S =ϕϕ==⨯∴ϕ=ϕ==ϕϕω- =⨯⨯⨯=====⨯=•ϕ=ϕ=⨯0.821408 ，，）（）2.30161212.5617.3712.671131.58250100102206.9131.85=25.15220==8.75A25.15cos=220cosRLRLCccRL CRL CRL cZ R j L jUIZZ jj cUI AZZ ZZ ZZ ZUIZP UI-=+ω=+=∠46.3Ω===Ω∣∣==-⨯=-Ωω⨯π⨯⨯⨯===∣∣//Z==∠14.4Ω+==ϕ⨯8.75⨯14.4总总=1864.5wcos=220sin=478.73wS=UI=220.75=1925V Acos0.9686Q UI=ϕ⨯8.75⨯14.4⨯8•ϕ=2.312202.22201002.2arccos0.837100378060PP LPPU VI I AUIZ j====|Z|===Ωϕ===∠=+ Ω2.32(1)861037220220221022PPPL PZ jU VUI AI I A=+=∠ Ω======|Z|==(2)220220220221038L P L P P L P U V U U V U I A I A= =====|Z |==(3)380380380381066L P L P P L P U V U U V U I A I A= =====|Z |==(4)220,380,Y 220N L L U V U V U V == =∆ 行，形2.33C0000000000038022022002200220022002201022002201002200220100220220220L P A B C A A B B C C N A B B U V U V U V U V U V U I AR U I AR U I A R I I I I •••••••••••••= =∣Z∣=10Ω=∠ =∠-12 =∠12 ∠===∠∠-12===∠-3∠-9∠12===∠3∠9=++=∠+∠-3+∠3设002260.1022104840A A P I R W=∠==⨯=2.34000312238380,2202205.838cos cos35.63054sin sin35.6=2290Var 3817cos 0.8L P P L P L L L L L L Z j U V U V U I I A Z P I W I S I V A =+=∠35.6======∣∣∴=ϕ==ϕ=ϕ==•ϕ=2.35380,1122L A B C U V R R R ==Ω==Ω，(1)00000000022222222002200220022002201122001002222010010010022111088A B C A A A B B B N A B B A A A B C C U V U V U V U I AR U I AR I I I I A P I R I R I R •••••••••••=∠ =∠-12 =∠12 ∠∴===∠∠12 ===∠12=++=∠+∠-12+∠12=∠=++=⨯+⨯22+10⨯22=设00W(2)0000000000017.3022017.3022017.30017.3017.30300AB AB B CA CAC B AB C CA A AB CA U I A R U I A R I I A I I AI I I A•••••••••••∠3===∠3∠15===∠15=-=-=∠-15===-=∠3-∠15=∠(3)0000008.6022228.60N A BC B C B C C I I U I I AR R I A••••••==⨯∠-9=-===∠-9++=∠9，2.3605.57760cos ==1018.3 5.59700320.7320.737256.6192.4L L L L I A P W U VS I V A Z = = ϕ0.8==⨯=•∣Z∣===Ω=∠=+ Ω2.3732.919380380L P P P L P I AI AU I V U U V=====|Z |====2.380000000000380=2200220022010100000220039.3039.3L A A A AB ABA A A A U V U V U I A R U I A R I A I I I AI A••'•'•'•''''•'''•••=∠∠∴===∠===∠3=⨯∠-3=∴=+=∠+=∠∴=设第三章电路的暂态分析3.1 (1)Uc22212111120(0)1000(0)(0)100(0)100100100(0) 1.0199(0)(0)1001000(0)0(0) 1.01c c c R R R R c t u U V t u u U V u V i A R u U u V u i A R i i i A--+-+++++++= == = === =====-=-=∴===-=-(2)+-Uci cu12121112222100()()1199()()1()()99()0()()99R R c c R U i i AR R u i R V u i R V i Au u V∞=∞===++∞=∞=∞=∞=∞=∞=∞=3.2 （1）换路前：0t-=434342341234123442123(0) 1.52(0) 1.51 1.5L c L R R R K R K R R R K i uA Ku i R uA K V --=+=Ω=Ω=+=Ω====⨯= （2）换路后0t +=(0)(0) 1.5(0)(0) 1.5L L c c i i mA u u V+-+-====412146 1.5(0) 2.2511(0)0(0)(0)(0) 2.25 1.50.75(0) 1.5 1.5 1.510c L L L i mAK Ki A i i i mA mA mA u i R mA K V++++++-==+==-=-==-=-⨯Ω=(2)t =∝R 4121236232c L L c L u Vi mAKi i mA i i u V(∝)=6⨯=(∝)==(∝)=(∝)=(∝)=0A (∝)=0A (∝)=03.3(1)求()c u +0 0(0)00(0)(0)0c c c t u V t u u V --+-+= ,= = ==(2)求()c u ∞()20c t u U V =∞,∞==（3）求τ2121212121661:112)22060.12R R K C C Z Z j cZ Z Z j c j c C C C C uF RC K s-==Ω//==ω=//==ωω(2∴=//==∴τ==Ω⨯20⨯10=(4)8.330.12()20(020)2020t t c u t ee V --=+-=-s/3.4t -=13K ΩR 60V(0)10660(0)(0)60c c c u m k V u u V-+-=⨯===0t +=13K ΩR c u36=5366060(0)125C K K R K K Ki mAR K +⨯=Ω+--===-Ω总总t =∝10mAR()0()0C Ci u ∝=∝=1R 3K ΩR[]20622100105521010()()(0)()060060()tc c c c t t R K RC K s u t u u u e ee V ----+--=Ωτ==Ω⨯⨯=⎡⎤∴=∝+-∝⎣⎦ =+-=[]210010()012012()t t c i t mA ee mA ---=+--=-60cu V/t s/t s/ci mA/-123.5（1）求(0),()c ci u++3131210(0)1005020(0)(0)505010050(0) 6.2544cc ccRt u U VR Rt u u VUi AR R--+-++= ,=⨯=⨯=+= ==--===++(2)求()()c ci u∞,∞,()0,()100c ct i A u U V=∞∞=∞==(3)求τ565612651021051021088210()0(6.250) 6.25()100(50100)10050t t c t t c R R R RC s i t ee A u t ee V -----⨯⨯--⨯⨯=+=Ωτ==⨯0.25=⨯∴=+-==+-=-3.60t -=+-2R 31i 2i c u +-1U11124(0)10544c R u u VR R -=⨯=⨯=++0t +=(0)(0)5c c u u V +-==+-2R 3R 1R cuci 2i U2212232250cc i i i U iR i R i R i R =+=++-= (0)0.625(0)0.3125c i mA i mA ++∴= =t =∝R 2R120312602244100100.4R R R R K K K R R R C K s-=+=Ω+Ω=Ω+τ==Ω⨯⨯=22122120.40.50.52.5 2.51()5 2.52()05()0.62544() 2.5(5 2.5)2.5 2.5()0(0.6250)()0.625(0.31250.625)c c t c t t c t t R u U VR R i U i mAR R K K u t e e Vi t e V e mAi t e -----∝=⨯=⨯=+∝=∝===+Ω+Ω∴=+- =+ =+-- =-0.625=+- 2.50.6250.3125t e mA- =-3.7650.250.10(0)0()2050100.2()20(020)2020(0.1)0.1(0.1)20207.870.1(0.1)7.87c c tt c c c t u t u U V RC K s u t ee V t s t u e V t u V++----⨯--++= = =∝ ∝==τ==Ω⨯4⨯=∴=+-=- ≤= =-== =U(0.1)(0.1)207.8712.13R c u U u V ++=-=-=()0R t u =∝ ∝=0600.11010.11010.10.1()0252254100.1()0(12.130)12.13(0.1)()20()()12.13(0.1)()20(7.8720)R t t R c t R c t c t u RR K R C K su t e e V t t u t U Vu t U u t e V t u t eV----+-+-=∝ ∝===Ωτ==Ω⨯⨯==+-= ≥=∝ ===-= ≥=+-3.836000.2100(0.2)0.0100.2,11010100.01(0.2)(0.2)100.2,(0.2)(0.2)10(0.2)(0.2)(0.2)01010,()0()0(100)10,0.20,(0)(0)0c i c i i c t t c i t RC s u u V t u u Vu u u V t u V u t ee V t t u u V ----++-+++-------=τ==⨯⨯⨯======∴=-=-=-=∞∞=∴=+--=-≥===001000.0100,(0)(0)0(0)(0)10,()0()0(100)10,00.2c i i t t t u u V u u V t u V u t ee V t +++++-======∞∞=∴=+-=≤≤u V/t s/3.9求(0)c u + ，(0),(0)BA V V ++0(6)0,(0)515250,(0)(0)1:10(0)125(0)660(0)0.31(0)6100.31 2.9(0)(0)1 1.9c c c B A B t u Vt u u VKVL i i i mA V V V V V-+++-++++++--==⨯=+===⨯++⨯--= =∴=-⨯= =-=求(),(),()cB A u V V ∞∞∞ 67127 2.3104.375106(6)()50.35 1.510525()6100.33()()()3 1.5 1.55(1025) 4.3754.37510010 4.37510() 1.5(1 1.5) 1.50.5() 1.5(1.9 1.5c B A B c t t c A u VV V V V u V R K RC s u t ee VV t -----⨯⨯--∞=⨯=⨯=++∞=-⨯=∞=∞-∞=-==//+=Ωτ==⨯⨯=⨯∴=+-=- =+-66662.310 2.3102.310 2.310) 1.50.4()3(2.93)30.1t t t t B e e V V t e e V-⨯-⨯-⨯-⨯=+ =+-=-3.10U L求(0)L i +31312331210.531040,(0)0.25150,(0)(0)0.24()0.3257.5()0.16215 3.7518.75100.5218.75()0.16(0.20.16)0.160.04L L L L t L U t i AR R t i i A U t i AR R R ii A R R R R L ms R i t ee ---++---⨯====++====∞,∞===+//+ ∞===+//=+=Ωτ===∴ =+-=+875t A3.11 (1)121212121212121212121)0.010.020.03(0),(0)0,(0)00,(0)(0)0(0)=(0)=0(),()6,()()2210.033,0.013()2(0L L L Z Z Z j L j L j L L L L L H i i t i A t i i A L i i A i i U t i i AR R L R R R sR i t ++--++-++=+=ω+ω=ω(+∴=+=+======∞∞=∞∞=∞===++=+=Ωτ===∴=+求断开：求1000.0110012)22()22t t t ee Ai t e A----=- =-（2）1010011112000.00512202020222500.022:()2()()26()320.010.0052()3(23)3:()2()()2()00.020.021()0(20)2tt tt L i t A i t i t A U i A R L s R i t e e AL i t A i t i t Ai A L s R i t ee A-+----+---= ==∞===τ====+-=- = ==∞=τ====+-=3.12100.1220(0),(0)101201(0)(0)10220(),()110110.20.111()110(10110)110100()30,0.02L c L L t t U i i AR R R i i A U i t i A R R L s R R i t e e Ai t A t s+-+---===++++==∞=∞,∞===++τ===++∴=+-=- ==求求3.131(40')400'1000,(0) 2.5400,(0)(0) 2.5(0) 2.5'(0),'80,()0,()0140'40'5%:()0(2.50) 2.5ln 0.05'40600.0360't R tR t i A t i i A u R V u V R t i A u VL sR R t i t ee R R --++-++--++=======- ⎢⎢≤200≤Ω=∞∞=∞=τ==++=+-=≥--=Ω∴Ω≤≤80Ω求对应+00,(0)0,0(0)06()1225014.425014.40,0.057625014.4250,0.0288500L L L L t t i A t i A t i mAL R R R s R s--+==>===∞∞==τ==+=τ===Ωτ==设时，开关闭合时，时，0.05760.05760.02880.02880,() 2.4(0 2.4) 2.4 2.4250,()2(012)12126()6,0.0288ln 0.0212:02500.02t t L t t L L R i t e e R i t e ei t mA t ms R ms----==+-=-==+-=-==-=∴~Ω~延时：0.0166第四章常用半导体器件4.2 (1)∴⨯∴去掉得优先导通则V 截止,,10,0,9109,19A B DADB A F B D D U V U V D V D(2)∴⨯∴∴∴∴ 去掉得优先导通则V 导通,,6, 5.8,96 5.4,191196 5.81195.596 5.595.85.590.410.21110.62A B DA DB A FB AFBFF FFF F ABAB D D U V U V D V D V V V V V V V V V V I mA I mAII I mA(3)∴ ∴∴∴ 去掉得 优先导通,,5,5,551194.735 4.730.270.2710.54A B DA DB A B FFF F ABAB D D U V U VD D V V V V V I mA I mAII I mA4.4LR ->反向击穿241228,LZRLZLZ R UU U VR R U VRL-IU∴>80.08100:0.160.080.0880IZ RLZ R RLZ ZmU U I A RKCL I I I AmA I I4.5LR -IU > ∴>2反向击穿=2100L IZ IL Z I R U U U R R U V U VL R-IU ∴∴∴⨯≤≤⨯∴⨯≤≤⨯∴≤≤3333:1010050050020500510301020510301050022.535R Z RL I Z Z ZLI ZI ZZ I I KCL I I I U U U I R R U I U I I U V U V4.6 (1)∆β∆∆β∆11122220500.80.410500.80.6C B C B I I II(2)ββ1218 4.50.43847.50.8第五章 基本放大电路5.2输出端等效电路-2U 0Ω∴∞ ∴Ω'00'0'001,11111.1100L L LLR K U VR U U r R U r R U Vr5.4(1)β125024026CC B B C B CECCC C V I uA R I I mA U V I R V（2）∴ ∴β12432640CC CCE C BV mA R I mA U V I I(3)1206C BE C CEU U U U V5.6R-•+••（1）•••••ββββ⨯⨯011(1)(1)10020.98(1.41012)b cc u beEi b be b EU I R R A r R U I r I R（2）•••••ββββ⨯⨯02211(1)(1)10120.9(1.41012)b EEu beEi b be b EI R R U A r R U I r I R（3）•••••∠0⨯∠0∠180ω⨯∠0∠0ω 00011001000220210.9810.981.39sin(180)0.9910.991.4sin iu i u i U U A U u tmVU A U u t mV5.7ΩΩβ⨯Ωβ⨯∴Ωβ∴⨯01200,20lg 20046512100,20lg10040510.0520122400052626200(1)200(120)74611007463.7320121 3.738.2uLi m C B CC B B be E Cubeu beC CECC C C A dBmA U R K A dB I uA I I mAB V R K I mAr I R A r A r R K U V I R 7V5.8分压偏置共射极放大电路（1）⨯⨯β212201236020301.52()12 1.5(32)4.51.52560B B CCB B B BEC E E CE CC C C E CBR U V VR R V V I I mA R U V I R R VI I uA(2)βΩ//⨯ΩΩ'026300(160) 1.361.5366088.21.361.363Lu be be u i beR A r r K A r r K r RCK5.9 (1)β⨯β⨯⨯⨯1295.2(1)755115095.2 4.7612(150)95.217.14CCB B EC B CECC E E V I uAR R I I mA U V I R V(2)β⨯//⨯//ββΩ//β//⨯//1Ω//Ωβ''''0(1)51(11)0.98472.8451(11)(1)(1) 4.8626200(150)472.844.86(1)75472.84(150)(1)19.3472.84757510.741150L u be LE B be iB be L be SR A r R I I mAr r R r R K r R r第六章 集成运算放大器及其应用6.2（1）∴ ∴ ∴0000:i f f if L i LL iiiu u u u u u u u u u KCL R Ru u R R u R Aufu R（2）∴ ∴∴∴∴A 11''1'10''001000:(1)(1)iiiifE E EfF F I E E F E iEFc cc E EF EEc EF cF iEi i u uu u u u i R R KCL i i u R i i R R u R i R R R R u i R u i R i i i i i R u R i R u R R ufAu R R（3）00001i i ii i i u u uu uu u u u u u Auf u（4）∴∴∴∴11''0033'''0301303100:ii i ffi fi iii u u u u u uu i R R u u u i R R u u u u u i R KCL i i u u R R u R Aufu R 6.3(1)∴±±⨯±55520lg 100101313100.1310opp dmu AuAuU u VmVA(2)±⨯±5max 13100.0652dm idu I mA r6.4∴0201222102212222122112211111fix A x A F A A x A F A A A x A A F A A F A F A F6.5∴∴∴~Ω Ω∴~0101110066:6(1):01010:612FFF F i i u Vu u V uu uKCL R R R R u uuR R R K R K u V6.6(a)∴改变对无影响00,0i i RiL uu u u u u u i iR Ru i RR i(b)改变对无影响00,0i iRL uu u i u i i RR i6.7改变对无影响00000L iR L i R iiL u i R u u u i i u i R u i RR u i R R i 6.8作用时12,i i u u'0u 4u i u∴∴⨯'12012'12012000123()1()222i i F i i F i i u u u u u R R R u u u R V R R作用时34,i i u u''04R||∴∴∴34343434343434''012''0''034'''00:0()2:2347375.52i i i i i i Fi i ii u uu u KCL R R R R u u u u u R R R R uu u KCL R R R u u uu u u u V u u u V6.9。