产5万吨乙二醇工艺流程成人高等教育毕业设计（论文）年产5万吨乙二醇工艺流程设计题目_________________________________学号_________________________________学生_________________________________联系电话_________________________________指导教师_________________________________教学站点_________________________________专业_________________________________完成日期_________________________________乙二醇在经济中有着极其重要的地位。
用于生产聚酯纤维、薄膜、容器瓶类等系列产品和汽车防冻剂，还可用于除冰剂、表面涂料、表面活性剂、增塑剂等化工产品的原料。
因此，发展和技术改造乙二醇工艺设计对我国经济发展有着重要的意义。
在本设计中，进行对原料、产品的说明，生产方法的选择，工艺流程介绍，根据反应原理进行原料配比。
其中，整个工艺流程及原料的投入量是本设计的核心部分，关系着乙二醇的产品的质量和产量，因此本设计以工艺流程和原料投入量为中心和重点，经过原料投入量的严密的计算和论证，得到了肯定的结果。
关键词乙二醇环氧乙烷精制温度压力AbstractThe glycol has the extremely important status in the economy. For producing polyester fiber, thin film and vessel bottle kind and other serial products and automobile antifreeze, but may also be used in the de-icing agent, superficial coating, surface active agent, plasticizer and other product of chemical industry of the raw materials. Therefore, the development and technical transformation glycol technological design has the vital significance to our country economic development. In this design, carries on to the explanation of raw material and product, the choice of production method, the technical process introduced that carries on the molar ratio of raw materials according to the reaction principal. And, the inputs of entire technical process and raw material are the core component of design, is relating glycol the quality and output of product, therefore this design centers on the technical process and raw material inputs the center, after the strict computation and proof of raw material inputs, obtained the affirmative result.Key word :Glycol oxirane Purification Temperature Pressure目录乙二醇在经济中有着极其重要的地位。
用于生产聚酯纤维、薄膜、容器瓶类等系列产品和汽车防冻剂，还可用于除冰剂、表面涂料、表面活性剂、增塑剂等化工产品的原料。
因此，发展和技术改造乙二醇工艺设计对我国经济发展有着重要的意义。
在本设计中，进行对原料、产品的说明，生产方法的选择，工艺流程介绍，根据反应原理进行原料配比。
其中，整个工艺流程及原料的投入量是本设计的核心部分，关系着乙二醇的产品的质量和产量，因此本设计以工艺流程和原料投入量为中心和重点，经过原料投入量的严密的计算和论证，得到了肯定的结果。
................................................. ５一、乙二醇工业的发展 ......................................................................................................................... ９二、国外乙二醇工业的概况 ............................................................................................................. １０三、国内乙二醇工业的概况 ............................................................................................................. １０第二章生产工艺..................................................................................................................................... １０一、产品说明..................................................................................................................................... １０二、生产乙二醇的原料说明 ............................................................................................................. １１表1环氧乙烷质量指标..................................................................................................................... １１三、乙二醇的生产方法介绍及方法的选择 ..................................................................................... １１四、生产乙二醇的反应原理 ............................................................................................................. １２五、生产乙二醇的工艺条件 ............................................................................................................. １２六、生产乙二醇的设备及反应器的选择 ......................................................................................... １３第三章生产乙二醇的工艺流程 ......................................................................................................... １３反应器的物料衡算： ............................................................................................................................ １６反应器进料中环氧乙烷和水的摩尔比为1︰18，因为环氧乙烷在反应器中基本达到全部转换，故可设为98%，乙二醇年产量为5万吨。
.............................................................................................. １６由于原料为环氧乙烷和水，设环氧乙烷的质量为M环氧乙烷,水的质量为M水 ............................ １６所以，依据已知条件N环氧乙烷︰N水=1︰18；环氧乙烷转换率为98%；乙二醇年产量为5万吨;M 环氧乙烷=44G/MOL,M水=18G/MOL........................................................................................................... １６由此可计算M环氧乙烷和M水.............................................................................................................. １６因为N环氧乙烷︰N水=1︰18 ........................................................................................................... １６M环氧乙烷︰M环氧乙烷=M水︰M水=1/18（1） .............................................................. １６M环氧乙烷︰M水×M环氧乙烷︰M水=1/18..................................................................................... １６M环氧乙烷︰M水×18/44=1/18 ........................................................................................................ １６M环氧乙烷︰M水=1/18×44/18 ........................................................................................................ １６=0.1358１６由于环氧乙烷转换率为98%，乙二醇年产量为5万吨，可计算得M环氧乙烷和M水： ............... １６M环氧乙烷+M水=5×107/98%(2) ................................................................ １６=5×109/98 ............................................................................................................................................ １６=5.1×107（KG） ................................................................................................................................... １６由（1）、（2）式可知： .................................................................................................................... １６M环氧乙烷=0.1358M水（3）..................................................................... １６M环氧乙烷+M水=5.0×107（KG）（4）.................................................................. １６把（3）式代入（4）式可计算得： .................................................................................................... １６0.1358 M水+ M水=5.1×107（5）.................................................................... １６1.1358 M水=5.1×107 .......................................................................................................................... １６M水=4.49×107（KG）........................................................................................................................... １６由（4）、（5）式联立可得： ............................................................................................................ １６M环氧乙烷+4.49×107=5.1×107 ........................................................................................................ １６M环氧乙烷=0.61×107（KG） ............................................................................................................. １６第六章乙二醇生产技术的展望及发展建议 ......................................................................................... １７通过这次设计让我知道了知识是综合能力的体现，不是独立的学科。