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工程热力学 课后习题答案 可打印 第三版 第八章


A2 =
qm v2 313 × 10−4 kg/s × 0.0538m3 /kg = = 2.8 ×10−6 m 2 601.0m/s cf 2
F = qm cf2 + ∆pA2 = qm cf 2 + ( p2 − p0 ) A2 = 0.0313kg/s × 601m/s + (0.72864 − 0.1) ×106 Pa × 2.8 ×10−6 m 2 = 20.6N
p Tcr = T1 cr p1 vcr = RgTcr pcr =
κ −1 κ
= T1ν cr
κ −1 κ
= (43.3 + 273.15)K × 0.528 1.4 = 263.67K
1.4 −1
287J/(kg ⋅ K) × 263.67K = 0.0104m3 / kg 6 7.2864 × 10 Pa
当 背压 pb = 1MPa 时
p2 = pcr = 1.056MPa
1.4 −1
T2 = T1ν cr v2 = RgT2 p2
κ −1 κ
= 300.15K × 0.528 1.4 = 250.09K ; t2 = −23.06 o C 287J/(kg ⋅ K) × 250.09K = 0.0680m 3 / kg 1.05 ×106 Pa
cf = 2 ×1005J/(kg ⋅ K) × (350 − 326.5)K = 217.34m/s Acf 2.6 ×10−3 m 2 × 217.34m/s qm = = = 3.07kg/s v 0.1839m3 / kg
pcr = ν cr p* = 0.528 × 0.65MPa = 0.3432MPa > pb
8-5 内燃机排出的废气压力为 0.2MPa ,温度为 550℃,流速为 110m / s ,若将之引入渐缩喷 管, 试确定当背压为 0.1MPa 时废气通过喷管出口截面的流速并分析若忽略进口流速时引起的 误差。 解:
T * p* = p1 T1
κ κ −1
829.17K 1.4 −1 = 0.2MPa = 0.205MPa 823.15K
ccr = c = κ RgTc = 1.4 × 287J/(kg ⋅ K) × 263.67K = 325.49m/s
103
第八章 气体和蒸气的流动
qm =
Acr ccr 1× 10−6 m 2 × 325.49m/s = = 0.0313kg/s 0.0104m3 / kg vcr
pcr : p2 = 10 :1,p2 = 0.72864MPa p T2 = T1 2 p1
t1 = 750°C
pr1 = 126.984
pr 2 = pr1
h1 = 1074.28kJ/kg
p1 p = r1 p2 pr 2
p2 0.5MPa = 126.984 × = 90.703 p1 0.7MPa
查附表 T2 = 939.73K ,
t2 = 666.58°C
h2 = 979.56kJ/kg
104
第八章 气体和蒸气的流动
8-6 滞止压力为 0.65MPa ,滞止温度为 350K 的空气可逆绝热流经收缩喷管,在截面积为
2.6 × 10−3 m 2 处气流马赫数为 0.6。若喷管背压力为 0.28MPa ,试求喷管出口截面积。
解:
Ma =
c p (T * −T ) cf = c κ RgT
cf 2 = 2(h1 − h2 ) = 2 × (1074.28kJ/kgK − 976.56kJ/kgK) ×103 = 435.25m/s v2 = RgT2 p2 = 287J/(kg ⋅ K) × 939.73K = 0.5394m 3 / kg 0.5 × 106 Pa
qm v2 0.6kg/s × 0.5394m3 / kg = = 7.44 ×10−4 m 2 A2 = 435.25m/s cf 2
T * κ −1 447.85K 1.4 −1 p* = p1 = 0.617MPa = 0.58MPa × 440K T1 pcr = p喉 = ν cr p* = 0.528 × 0.617MPa = 0.3258MPa Tcr = T喉 = T *ν cr vcr = v喉 = RgTcr pcr
8-3 燃气经过燃气轮机中渐缩喷管形的通道绝热膨胀,燃气的初参数为 p1=0.7MPa、t1=75℃, 燃气在通道出口截面上的压力 p2 = 0.5MPa ,经过通道的流量 qm = 0.6kg/s ,若通道进口处 流速及通道中的磨擦损失均可忽略不计,求燃气外射速度及通道出口截面积。 (燃气比热容按 变值计算,设燃气的热力性质近似地和空气相同,其热焓可查附表) 解: 查附表
Acr = A喉 =

qm vcr 1.5kg/s × 0.3287m3 /kg = = 1.27 ×10−3 m 2 387.21m/s ccr
κ −1 κ
p2 = pcr
= 829.17K × 0.528 1.4 = 690.88K
1.4 −1
cf 2 = κ RgTcr = 1.4 × 287J/(kg ⋅ K) × 690.88K = 526.87m/s
若忽略初流速,则
′ = ν cr p1 = 0.528 × 0.2MPa = 0.105MPa > pb pcr ′ = T1ν cr T2′ = Tcr
T=
2cpT * 2 ×1005J/(kg ⋅ K) × 350K = = 326.50K 2 κ Rg Ma + 2c p 1.4 × 287J/(kg ⋅ K) × 0.62 + 2 ×1005J/(kg ⋅ K)
κ
1.4
T κ −1 326.50K 1.4 −1 p = p * = 0.510MPa = 0.65MPa × T * 350K v= RgT p = 287J/(kg ⋅ K) × 326.50K = 0.1839m3 / kg 0.51× 106 Pa
v1 =
RgT1 p1
=
287J/(kg ⋅ K) × 440K = 0.2177m3 / kg 0.58 ×106 Pa
105
第八章 气体和蒸气的流动
cf 1 =
qm v1 1.5kg/s × 0.2177m3 / kg = = 125.61m/s 2.6 ×10−3 m 2 A1
cf21 125.61(m/s) 2 T * = T1 + = 440K + = 447.85K 2c p 2 × 1005J/(kg ⋅ K)
p T2 = T1 2 p1 t2 = 3.32°C v2 = RgT2 p2 =
κ −1 κ
1.5MPa 1.4 = (27 + 273.15)K × = 276.47K 2MPa
1.4 −1
287J/(kg ⋅ K) × 276.47K = 0.0529m3 / kg 6 1.5 × 10 Pa
1.4
2 cf1 (110m/s) 2 T * = T1 + = (550 + 273.15)K + = 829.17K 2cp 2 × 1005J/(kg ⋅ K)
pcr = ν cr p* = 0.528 × 0.205MPa = 0.108MPa > pb、 T2 = Tcr = T *ν cr
第八章 气体和蒸气的流动
第八章 气体和蒸汽的流动
8-1 空气以 cf = 180m/s 的流速在风洞中流动,用水银温度计测量空气的温度,温度计上的读 数定是 70℃,假定气流通在温度计周围得到完全滞止,求空气的实际温度(即所谓热力学温 度) 。 解: T * = T1 +
cf2 2c p
T1 = T * −
κ −1 κ
0.72864MPa 1.4 = 316.45K × = 136.57K 13.8MPa
1.4 −1
v2 =
RgT 2 p2
=
287J/(kg ⋅ K) ×136.57K = 0.0538m3 / kg 6 0.72864 × 10 Pa
cf 2 = 2c p (T1 − T2 ) = 2 ×1004J/(kg ⋅ K) × (316.45 − 136.57)K = 601.0m/s
κ −1 κ
κ
1.4
= 447.85K × 0.528 1.4 = 373.15K
1.4 −1
=
287J/(kg ⋅ K) × 373.15K = 0.3287m3 / kg 6 0.3258 ×10 Pa
ccr = c = κ RgTcr 1.4 × 287J/(kg ⋅ K) × 373.15K = 387.21m/s
cf2 (180m/s)2 = (70 + 273.15)K − = 327.03K 2c p 2 × 1005J/(kg ⋅ K) × 103
t1 = 53.88 o C
8-2 进入出口截面积 A2 = 10cm 的渐缩喷管的空气初参数为 p1 = 2 × 10 Pa、t1 = 27 C ,初
2 6 o
κ −1 κ
p2 = pcr
= 823.15K × 0.528 1.4 = 685.86K
1.4 −1
′ = 1.4 × 287J/(kg ⋅ K) × 685.86K = 524.96m/s cf′ 2 = κ RgTcr
cf 2 − cf′ 2 526.87m/s − 524.96m/s = = 0.36% cf 2 526.87m/s
=
102
第八章 气体和蒸气的流动
cf 2 = 2(h1 − h2 ) = 2cp (T1 − T2 ) = 2 × 1005J/(kg ⋅ K) × (300.15 − 250.09)K = 317.2m/s qm = A2 cf 2 10 ×10−4 m 2 × 317.2m/s = = 4.66kg/s v2 0.0680m 3 / kg
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