混凝土$*MAT_ELASTIC_PLASTIC_HYDRO$1,2.3,0.13,3.2E-4,,-5.E-5,1.$,,32,2.4,0.126,2.5E-4,,-5.E-5,0.4,,3.*EOS_GRUNEISEN2,0.2500,1.0,0.,0.,1.9,0.00.,1.$$国际单位*MAT_ELASTIC_PLASTIC_HYDRO_SPALL$1,2.3,0.13,3.2E-4,,-5.E-5,1.$,,32,2.4E+03,0.126E+11,2.5E+7,,-5.E+6,0.4E+11,,3.*EOS_GRUNEISEN2,0.2500E+4,1.0,0.,0.,1.9,0.00.,1.$混凝土参数密度2.4g/cm剪切模量12.6Cpa屈服应力25Mpa抗拉强度5Mpa失效应变0.4 GRUNEISEN状态方程参数C=2500m/s S1=1.0 S2=0 S3=0 ω=1.9 A=0 E0=0 V0=1sdyyds混凝土随动硬化模型*mat_plastic_kinematic3 2100 3.00e+10 0.18 2.0e+07 0 00.002*mat_plastic_kinematic2 2600 4.75e+10 0.18 6.0e+07 4.75e+09 099.3 1.94 0.004取自龚自明防护工程混凝土靶体尺寸及边界约束对侵彻深度影响的数值模拟*MAT_JOHNSON_HOLMQUIST_CONCRETE4,2.4,0.123,0.79,1.60,0.007,0.61,2.4E-42.7e-5,1.0e-6,0.01,7.0,8.0e-5,5.6e-4,1.05e-2,0.10.04,1.0,0.174,0.388,0.298取自龚自明防护工程BLU-109B侵彻厚混凝土靶体的计算与分析*MAT_JOHNSON_HOLMQUIST_CONCRETE4,2.4,0.132,0.79,1.60,0.007,0.61,3.22E-43.15e-5,1.0e-6,0.01,7.0,1.08e-4,7.18e-4,1.05e-2,0.10.04,1.0,0.174,0.388,0.298取自蔡清裕国防科技大学学报模拟刚性动能弹丸侵彻混凝土的FE-SPH方法*MAT_JOHNSON_HOLMQUIST_CONCRETEmid RO G A B C N FC1, 2.2,0.164,0.75,1.65,0.007,0.61,4.4e-4T EPS0 EFMIN SFMAX PC UC PL UL2.4e-5,1.0e-6,0.01,11.7,1.36e-4,5.8e-4,1.05e-2,0.1D1 D2 K1 K2 K3 FS0.03,1.0,0.174,0.388,0.298取自张凤国爆炸与冲击《大应变。

高应变率及高压下混凝土的计算模型〉*MAT_JOHNSON_HOLMQUIST_CONCRETE2,2.44,0.1486,0.79,1.60,0.007,0.61,4.8E-44.0e-5,1.0e-6,0.01,7.0,1.6E-4,0.001,8.0E-3,0.10.04,1.0,0.85,-1.71,2.08取自宋顺成爆炸与冲击弹丸侵彻混凝土的SPH算法*MAT_JOHNSON_HOLMQUIST_CONCRETE1，2.4，0.1486，0.79，1.60，0.007，0.61，1.4e-44.0e-5，1.0e-6，0.01，7.0，1.6e-4，0.001，8.0E-3，0.10.04，1.0，0.174，0.388，0.298*Mat_johnson_holmquist_concrete$ 材料数据取自1998 年Johnson-Holmquist 会议论文, 失效采用拉伸失效============$ MID RO G A B C N FC1 2.25E-3 1.64E+04 0.75 1.65 -0.007 0.76 48.0 $ T EPS0 EFMIN SFMAX PC UC PL UL2.4 1.0 0.01 11.7 13.6 5.8E-4 1.05E+3 0.1 $ D1 D2 K1 K2 K3 FS0.03 1.0 1.74E+4 3.88E+04 2.98E+04钢纤维混凝土*MAT_JOHNSON_HOLMQUIST_CONCRETE1,2.452,0.279,0.75,1.6,0.007,0.61,5.6e-48.2e-5,1.0e-6,0.015,10.5,2.3e-4,7.4e-4,1.05e-2,0.0680.045,1.0,*MAT_JOHNSON_HOLMQUIST_CONCRETE1,2.551,0.332,0.79,1.6,0.007,0.61,7.17e-411.4e-5,1.0e-6,0.020,12.5,3.0e-4,8.8e-4,1.15e-2,0.0700.050,1.0,jzbaiH-J-C模型该模型主要应用于高应变率、大变形下的混凝土模拟。

在DYNA中H-J-C模型的定义方式为：*MAT_JOHNSON_HOLMGUIST_CONCRETE，材料编号为111。

H-J-C模型综合考虑了大应变、高应变率、高压效应，其等效屈服强度是压力、应变率及损伤的函数，而压力是体积应变（包括永久压垮状态）的函数，损伤积累是塑性体积应变、等效塑性应变及压力的函数。

下面是一个例子：$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$ $$H-J-C g-cm-us*MAT_JOHNSON_HOLMQUIST_CONCRETE2,2.4,0.1486,0.79,1.60,0.007,0.61,0.000484e-5,1e-6,0.01,7.0,0.00016,0.001,0.0080,0.100.04,1.0,0.85,-1.71,2.08 $$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$ $sdyydsEPS0采用千克，米，秒是为1，采用克，微秒，厘米是1.0e-6.爬格子的人*MAT_JOHNSON_HOLMQUIST_CONCRETE2,2.4,0.1486,0.79,1.60,-0.007,0.61,0.00048-4e-5,1e-6,0.01,7.0,0.00016,0.001,0.0080,0.100.04,1.0,0.85,-1.71,2.08，0.1*MAT_ADD_EROSION1，1234.0-4e-5 ，234.0，1234.0，1234.0 ，1234.01234.0，1234.0duanmengsun我后来试试了，改*MAT_ADD_EROSION的第一参数对结果影响不大，但是如果设定第一主应力为失效变量（第二个参数），会产生径向裂缝的，但是很怪异，也不知对不对。

casio24第一主应力取负值吗？取负值我的模型除炸药外其他材料单元全部失效了。

没有了。

还有说主应力的时候是拉正压负吧？爬格子的人为什么添加拉伸破坏准则后，看不到结构的拉伸破坏，只是看到单元被拉长，但是不能删除单元呢？相反取掉拉伸破坏准则，则能看到断裂现象；如果定义拉伸不定义压缩破坏，则看到单元被拉长，但是没有提示单元被删除的信息！不知道是什么原因呢？同时定义了拉伸以后察看拉伸单元的信息，其应力值仍然是Fc，而不是T的值，由此可见，mat-111在960中并不完善，欢迎不吝指教！lieut2003看你有这么雄心壮志，我在提供一些资料，出成果记得共享一下，To the best of my knowledge, Material Model 72 Mat_Concrete_Damage is an extension of Material Model 16 Mat_Pseudo_TENSOR due to Malvar, Crawford, Wesevich, and Simons, 'A Plasticity Concrete Material Model for DYNA3D,' Int J of Impact Engineering, V ol 19, Nos 9-10, pp 847-873, 199716 model：*MAT_PSEUDO_TENSOR$ Mode II Concrete Model Option with automatic EOS2,2.247E-04,,0.2205000, -13.000E+07,0.200,6.000E+04,4.031E+06,0.000E+00,0.000E+00$ 3rd example concrete that requires an equation-of-state (EOS)*MAT_PSEUDO_TENSOR3,2.247E-04,,0.220500.,1.250E+03,0.333,6.667E-05,500.,1.50, 1.25,0.7703.000E+07,0.200,6.000E+04,4.031E+06,0.000E+00,0.000E+000.000E+00,8.620E-06,2 .150E-05,3.140E-05,3.950E-04,5.170E-04,6.380E-04,7.980E-049.670E-04,1.410E-03,1.970E-03, 2.590E-03,3.270E-03,4.000E-03,4.790E-03,0.9090.309,0.543,0.840,0.975,1.00,0.790,0.630,0.469 0.383,0.247,0.173,0.136,0.114,8.600E-02,5.600E-02,0.000E+00lucyhulu*MAT_CONCRETE_DAMAGE4 2.6000000 0.25000005.5E-04 0.100E-04 0.0000000 0.10000000.0000000 0.0000000 0.0000000 0.0000000 0.0000000 0.0000000 0.0000000 0.00000000.20 2.1000000 0.3000000 3.350E-03 0.0000000 0 00.0000000 0.0000001 0.0000002 0.0000003 0.0000004 0.0000005 0.0000006 0.00000070.0000008 0.0000009 0.0000010 0.0000011 0.00000120.0000000 0.0000000 0.0000000 0.0000000 0.0000000 0.0000000 0.0000000 0.00000000.0000000 0.0000000 0.0000000 0.0000000 0.0000000 0.0000000 0.0000000 0.0000000 huangfei这段话的意思是可以与*MAT_CONCRETE_DAMAGE配合使用的状态方程只能是eos 8, eos 9 and eos 11 这几种suiyuerufeng*MAT_BRITTLE_DAMAGE1 0.250E+04 3.000E+10 1.67E-01 6.00e+06 1.400e+07 1.40E+02 0.037.2389e+5 0.004E+00 2.100E+11 3.00E+06 1.00e+10 0.750e+00 3.20E+07geneone*MAT_JOHNSON_HOLMQUIST_CONCRETE$H-J-C g-cm-us$* mid ro g a c n fc2 2.400000 0.148600 0.790000 0.007000 0.6100004.8000e-04$* t eps0 efmin sfmax pc uc pl ul4.0000e-051.0000e-06 0.010000 7.0000001.6000e-04 0.001000 0.008000 0.100000$* d1 d2 k1 k2 k3 fs0.040000 1.000000 0.850000 -1.710000 2.080000 -0.10000sjy张贴一种＃72材料模型，＃CONCRETE DAMAGE MODEL，该材料模型是我将近一年的研究成果，但还需要试验验证，有兴趣的朋友可以讨论一下。