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高中数学历年集合高考题汇编(专题)

集合与常用逻辑用语一、选择题1.(2010浙江理)(1)设P={x ︱x <4},Q={x ︱2x <4},则 (A )p Q ⊆ (B )Q P ⊆ (C )R p Q C ⊆ (D )R Q P C ⊆2.(2010陕西文)1.集合A ={x -1≤x ≤2},B ={x x <1},则A ∩B =( )(A){x x <1}(B ){x-1≤x ≤2} (C) {x-1≤x ≤1}(D) {x-1≤x <1}3.(2010辽宁文)(1)已知集合{}1,3,5,7,9U =,{}1,5,7A =,则U C A =(A ){}1,3(B ){}3,7,9 (C ){}3,5,9(D ){}3,94.(2010辽宁理)1.已知A ,B 均为集合U={1,3,5,7,9}的子集,且A ∩B={3},u ðB ∩A={9},则A= (A ){1,3} (B){3,7,9} (C){3,5,9} (D){3,9} 6.(2010江西理)2.若集合{}A=|1x x x R ≤∈,,{}2B=|y y x x R =∈,,则A B ⋂=( )A. {}|11x x -≤≤B. {}|0x x ≥C.{}|01x x ≤≤ D. ∅8.(2010浙江文)设2{|1},{|4},P x x Q x x =<=<则P Q =I(A){|12}x x -<< (B){|31}x x -<<- (C){|14}x x <<-(D){|21}x x -<<9.(2010山东文)已知全集U R =,集合{}240M x x =-≤,则UCM=A.{}22x x -<< B. {}22x x -≤≤C .{}22x x x <->或 D. {}22x x x ≤-≥或11.集合2{03},{9}P x Zx M x Z x =∈≤<=∈≤,则P MI =(A) {1,2} (B) {0,1,2} (C){x|0≤x<3} (D) {x|0≤x ≤3} 12.(7)设集合{}{}A x||x-a|<1,x R ,|15,.A B B x x x R =∈=<<∈⋂=∅若,则实数a 的取值范{}0围是 (A){}a |0a 6≤≤ (B){}|2,a a ≤≥或a 4(C){}|0,6a a ≤≥或a (D){}|24a a ≤≤13.设集合A={}{}|||1,,|||2,.x x a x R B x x b x R -<∈=->∈若A ⊆B,则实数a,b 必满足(A )||3a b +≤ (B )||3a b +≥ (C )||3a b -≤ (D )||3a b -≥ 14.(2010广东理)1.若集合A={x -2<x <1},B={x 0<x <2}则集合A ∩ B=( )A. {x -1<x <1}B. {x -2<x <1}C. {x -2<x <2}D. {x 0<x <1} 16.(2010广东文)1.若集合{}3,2,1,0=A ,{}4,2,1=B 则集合=⋃B AA. {}4,3,2,1,0B. {}4,3,2,1C. {}2,1D..20.(2010湖北文)1.设集合M={1,2,4,8},N={x|x 是2的倍数},则M ∩N= A.{2,4}B.{1,2,4}C.{2,4,8}D{1,2,8}21.(2010山东理)1.已知全集U=R ,集合M={x||x-1|≤2},则U C M=(A ){x|-1<x<3} (B){x|-1≤x ≤3} (C){x|x<-1或x>3} (D){x|x ≤-1或x ≥3}22.(2010安徽理)2、若集合121log 2A x x ⎧⎫⎪⎪=≥⎨⎬⎪⎪⎩⎭,则A =R ðA、(,0]2⎛⎫-∞+∞⎪ ⎪⎝⎭U B、,2⎛⎫+∞ ⎪ ⎪⎝⎭C、(,0])-∞+∞U D、)+∞23.(2010湖南理)1.已知集合M={1,2,3},N={2,3,4},则 A .M N ⊆ B.N M⊆C .{2,3}MN ⋂= D.{1,4}M N ⋃24.(2010湖北理)2.设集合()22{,|1}416x y A x y =+=,{(,)|3}x B x y y ==,则A B ⋂的子集的个数是A .4B .3C .2D .1 答案 54.(2010重庆理)(12)设U={}0,1,2,3,A={}20x Ux mx ∈+=,若{}1,2UA =l,则实数m=_________. 【解析】Θ{}1,2U A =l ,∴A={0,3},故m= -35.(2010江苏卷)1、设集合A={-1,1,3},B={a+2,a 2+4},A ∩B={3},则实数a =___________. 答案 16.(2010重庆文)(11)设{}{}|10,|0A x x B x x =+>=<,则A B I =____________ .1.(2009年广东卷文)已知全集U R =,则正确表示集合{1,0,1}M =-和{}2|0N x x x =+=关系的韦恩(Venn )图是( )2.(2009全国卷Ⅰ理)设集合A={4,5,7,9},B={3,4,7,8,9},全集U=A U B ,则 集合[()u A B I中的元素共有( )A. 3个 B. 4个 C. 5个 D. 6个3.(2009浙江理)设U =R ,{|0}A x x =>,{|1}B x x =>,则U A B =I ð( )A .{|01}x x ≤< B .{|01}x x <≤ C .{|0}x x < D .{|1}x x >5.(2009浙江文)设U =R,{|0}A x x =>,{|1}B x x =>,则U A B =I ð( )A .{|01}x x ≤< B .{|01}x x <≤ C .{|0}x x < D .{|1}x x >6.(2009北京文)设集合21{|2},{1}2A x xB x x =-<<=≤,则A B =U ( ) A .{12}x x -≤< B .1{|1}2x x -<≤C .{|2}x x <D .{|12}x x ≤<7.(2009山东卷理)集合{}0,2,A a =,{}21,B a =,若{}0,1,2,4,16A B =U ,则a 的值为( )A.0B.1C.2D.49.(2009全国卷Ⅱ文)已知全集U ={1,2,3,4,5,6,7,8},M ={1,3,5,7},N ={5,6,7},则C u ( M U N )=( )A.{5,7}B.{2,4}C. {2.4.8}D. {1,3,5,6,7}11.(2009安徽卷理)若集合{}21|21|3,0,3x A x x B x x ⎧+⎫=-<=<⎨⎬-⎩⎭则A ∩B 是 A.11232x x x ⎧⎫-<<-<<⎨⎬⎩⎭或 B.{}23x x << C.122x x ⎧⎫-<<⎨⎬⎩⎭D.112x x ⎧⎫-<<-⎨⎬⎩⎭答案 D 解析 集合1{|12},{|3}2A x x B x x x =-<<=<->或,∴1{|1}2A B x x =-<<-I选D12.(2009安徽卷文)若集合,则是A .{1,2,3} B. {1,2}C. {4,5}D. {1,2,3,4,5}16.(2009全国卷Ⅱ理)设集合{}1|3,|04x A x x B x x -⎧⎫=>=<⎨⎬-⎩⎭,则A B I =18.(2009辽宁卷文)已知集合M =﹛x|-3<x ≤5﹜,N =﹛x|x <-5或x >5﹜,则M U N =( )A.﹛x|x <-5或x >-3﹜B.﹛x|-5<x <5﹜C.﹛x|-3<x <5﹜D.﹛x|x <-3或x >5﹜20.(2009陕西卷文)设不等式20x x -≤的解集为M ,函数()ln(1||)f x x =-的定义域为N 则M N ⋂为( )A.[0,1)B.(0,1)C.[0,1]D.(-1,0] 21.(2009四川卷文)设集合S ={x |5<x },T ={x |0)3)(7(<-+x x }.则T S ⋂ =( )A.{x |-7<x <-5 }B.{x | 3<x <5 }C.{x | -5 <x <3}D.{x | -7<x <5 } 24.(2009四川卷理)设集合{}{}2|5,|4210,Sx x T x x x =<=+-<则S T =IA.{}|75x x -<<-B.{}|35x x <<C.{}|53x x -<<D.{}|75x x -<<25.(2009福建卷文)若集合{}{}|0.|3A x x B x x =>=<,则A B I等于26.(2009年上海卷理)已知集合{}|1A x x =≤,{}|B x x a =≥,且A B R ⋃=,则实数a 的取值范围是______________________ . 27.(2009重庆卷文)若{Un n =是小于9的正整数},{A n U n =∈是奇数},{B n U n =∈是3的倍数},则()U A B =U ð .28..(2009重庆卷理)若{}3A x R x =∈<,{}21x B x R =∈>,则A B =I .29..(2009上海卷文) 已知集体A={x|x ≤1},B={x|≥a},且A ∪B=R ,则实数a 的取值范围是__________________. 33.(2009湖北卷文)设集合A=(x ∣log 2x<1), B=(X ∣21+-X X <1), 则A B I = .答案{}|01x x <<解析 易得A={}|02x x << B={}|21x x -<< ∴A ∩B={}|01x x <<.34..(2009湖南卷理)某班共30人,其中15人喜爱篮球运动,10人喜爱兵乓球运动,8人对这两项运动都不喜爱,则喜爱篮球运动但不喜爱乒乓球运动的人数为_12__ 答案 :12解析 设两者都喜欢的人数为x 人,则只喜爱篮球的有(15)x -人,只喜爱乒乓球的有(10)x -人,由此可得(15)(10)830x x x -+-++=,解得3x =,所以1512x -=,即 所求人数为12人。

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