0. 2 4 6
0,25 0.137 0.076 0.052
0 23.49 26.27 21.68
=2 p0
c1
z
c1
8
2
1
0.205
52.28
9
3.4
3.33
m
z = 2 .0 m
3.4
(a) A adgf aemb fhmb mcgh
c2
4 l =1 b
c1
z =1 b
= 0.175 175
c3
k = 5 10−2 mm/s
ab Q k = 5 10−5 mm/s Q=
v
3 i0 =0.005
2
1 2
i=
h1 − h2 2 23.50 3.50 − 23.20 2 = = 0.015 20 L
v = ki = 5 * 10−2 * 0.015 = 7.5 * 10 −4 mm / s
Q = rst = 7.5 * 10−4 * 3600 *1* 106 = 2.7 * 10 −3 m 3 / h * m2
ms = d s vs
w
= ds
w
100% 1 00%
mw = wm wms = wd s
w
m = ms + mw = d s ( (1 1 + w) 1
d d
=
ms v
=
ds w 1+ e sr = vw vv
2
100% 10
sr =
wd s ⇒ wd s = sr e e
w
r= g=
m d (1 + w) g= s v 1+ e n=
wL =48%
wP =35.4%
5
1 2 2.10 20m 1 2
I p = wL − wp = 48 − 35.4 = 12.6 10< I p <17 2.35 ab h 1m
2
IL =
w − wp Ip
=
36.4 − 35.4 = 0.08 12.6
0< I L =0.08<0.25 a.b i 23.50m 23.20m
w(%) P(g/cm)
17.2 2.06
ds
15.2 2.10 =2.65
12.2 2.16
10.0 2.13
w op
8.8 2.03
7.4 1.89
d d
2.06 = = = 1.758 1 + w 1 + 0.172
d
=1.823 =1.925 =1.936 =
2.03 =1.881 1 + 0.088
32.0%
Байду номын сангаас
w = 32.0% 32.0% 0%
w= v mw v v *100%= 100%= w w = v w ⇒ ms = v w ms ms ms w
sr =
vw *100%=100% ⇒ vw = vv vv ms ⇒ ms = d s vs vs w ∴
ds =
w
vv w = d s vs w
3 v = k (i − ib ) = 5 * 10−5 * 0.015-0.005
=0.05 * 10 −5 mm / s = 5 * 10 −7 mm / s
= 1.8 * 10−6 m/h
Q = vst = 1.8 ∗10−6 ∗1 ∗1 = 1.8 ∗10−6 m3 / h.m2 2.11 180g 18% 25%
rsat
r' v = 72cm3 m=129.5g
d s = 2.7
=
m 129.5 = = 1.799 g / cm3 72 v
(1) w =
mw 129.5 − 121.5 m − ms * 100% = * 100% = * 100% =6.6% ms ms 121.5
3
ds =
ms m 121.5 ⇒ vs = s = = 45 vs w ds 2.7
mm % 1 2 3 4 1 50% 2
>2 9.4
2
0.5
0 0.5 .5 21
0.25 0 .25 0
0.2 0.2
0.075 0 .075 37.5
<0.075 13.5
18.6 8.6
3m 0.075mm 75mm d s (1 1 + w)
N=14 9.4%+18.6%+21.0%+37.5%=86.9%
p0 = 100kpa
z2
2 z = = 1.333 b 1.5
c1
= 0.098
=2
0.098
(3) p0 = 100kpa
z3 c1
= 0.170
=2
0.170 100=34kpa
(4) p0 = 100kpa
z4 c1
=0.072
=2
0.072 100=14.42kpa
z
= 136.24+19.62+34+14.42=204.2 .62 2+3 +34 4+14 2 . k kpa p b = 2m d = 1m
vv = v − vs = 72 − 45 = 27
2
e=
m vv 27 129.5 − 121.5 = 0.60 vw = w = = =8 vs 45 1 w
3 4 5 6
sr =
vw 8 * 100% =29.6 = vv 27
r = g = 1.799 *10=18.0kN/ m3 rsat = ms + vv v
' w
g =
121.5 + 27 *10=20.6kN/ m3 72
r'= rd =
g= g=
r
ms − vs v
w
g=
121.5 − 45 *10 72
10.6Kn/ m3
d
ms 121.5 *10=16.9kN/ m3 g= v 72 rd r
r'
rsat 2.5 e
2.68 2 68 sr = 100% d s = 2.68
c
= r0 d=17 d=17.5*1=17.5kpa 7.5 5*1=1
c
p0 = p − 0-3 Z(m) 0 1 2 3 4-7 Z(m) 4 5 6 7 5-5 0 2 4 6 0 2 4 6 z/b(aefc)
c1
= 145 145 − 17.5 = 127.5 kpa
z z/b / /b
g=
d s (1 + w)rw d s wrw + d s rw sr erw + d s rw = = 1+ e 1+ e 1+ e sr = vw vv
3 2.3
n=
vv v
100%
e n ⇒e= 1+ e 1− n
100% =
wd s vd s (1 − n) = e n
vs = 1 =32.2% 2.50 vs = 1 , d s = 2.70 , w=32.2%, =1.91 g / cm3 6
6
m1 = 180 g
∴ ms =152.54g
w1 = 18%
mw1 =27.46g
w2 = 25 % Q w1 =
mw1 ms
*100%=18%
ms + mw1 =180
m2 = 2.12
mw2 ms
*100%=25% ⇒ mw2 = 0.25 *152.54=38.135g
38.135-27.46=10.7g
∴
Q 0.67> Dr >0.33
2.7 40%
d
=1.66g/ cm3 ,
d s =2.69 w e= ds
d w
? −1 = 2.69 ∗ 1 − 1 = 0.620 1.66
= 1.66 g / cm3 d s = 2.69 sr = 40%
w= 2.8
sr e 0.40 ∗ 0.62 *100%=9.2% = ds 2.69 w=28.5%, r=19kN/ m3 , d s = 2.68 ,
F = 600 kN z = 2.0m M = 100 kN ⋅ m
3.5 = 18.0kN / m3
3.5 G=rgAd=20 2 2 1 1=80Kn = 1 1 8 4 2 2= = w = bl 2 = 6 6 6 3 pmax = F + G M 600 + 80 100 + = =245kpa + 4 A W 2∗ 2 3
《土力学与基础工程》第三版（赵明华）课后习题答案
2
2.2 1
d
=
ds w (2) 1+ e
=
sr erw + d s rw wd S (1 − n) (3) sr = 1+ e n
vs = 1
e=
vv vs w=
vv = e mw ms
w
v = vs + vv = 1 + e
ds =
ms vs
1 pw
0.1 = 0.175 175
: edcm
c4
:
l =2 b
z1
z =2 b
= A
= 0.120 120
=2
z =1 b z =1 b
0.175+0.120
200=118kpa
B
l = 2.5 b l meil: =1 b
emqj:
c1
= 0.202
= 0.175