连连看核心算法转：最近参考一个JAVA的版本写了一个AS3版的连连看游戏算法, 欢迎大家拍砖指正,里面用到了as3ds类库, 还有一些粉简单的辅助类就不贴出来了, 各位闭着眼睛也能想象出来, 看主要的逻辑吧：package ponents{import de.polygonal.ds.Array2;import de.polygonal.ds.DLinkedList;import de.polygonal.ds.Iterator;import flash.geom.Point;import utils.*;/*** 连连看算法* @author Luan (verycss-ok@)*/public class Map{private var _level:uint; //游戏关卡对应的项目数量private var _map:Array2; //二维数组private var _array:Array; //辅助的一维数组private var _restBlock:uint = 0; //剩余的项目数量private var _vector:DLinkedList; //保存符合条件线段的地方private var _countOfPerItem:uint; //每个项目出现的次数(偶数)private var _result:MatchResult; //暂存符合条件的结果public function Map(level:uint = 16){//加2是为了加一圈0_map = new Array2( Setting.COLUMN+2, Setting.ROW+2 );_array = new Array(_map.size - 2*_map.width - 2*_map.height + 4);_vector = null;_result = new MatchResult();//调用setterthis.level = level;}/********************** getter & setter **********************/public function set level(value:uint):void{_level = value;//取得一个尽量大的偶数值_countOfPerItem = NumberUtil.getFloorEven(_map.size / _level);_restBlock = _level * _countOfPerItem;_initMap();}public function get count():uint{return _restBlock <= 0?0:_restBlock;}public function get map():Array2{return _map;}public function get result():MatchResult{return _result;}/********************** 私有方法**********************/private function _initMap():void{//一维数组初始化和乱序for (var n:uint = 0; n < _array.length; n++)_array[n] = 0;for (var i:uint = 0; i < _level; i++){for (var j:uint = 0; j < _countOfPerItem; j++){_array[i * _countOfPerItem + j] = i + 1;}}_array = ArrayUtil.random(_array);ArrayUtil.drawWrappedMap(_array, _map);}/*** 横向检查* @param a* @param b* @return*/private function _hTest(a:Point, b:Point):MatchResult {if (a.x == b.x || a.y != b.y ) return null;var x_start:uint = Math.min(a.x, b.x);var x_end:uint = Math.max(a.x, b.x);for (var x:uint = x_start + 1; x < x_end; x++)if ( _map.get(x, a.y) != 0 )return null;return _result.fill(a.clone(), b.clone());}/*** 纵向检查* @param a* @param b* @return*/private function _vTest(a:Point, b:Point):MatchResult {if (a.y == b.y || a.x != b.x) return null;var y_start:uint = Math.min(a.y, b.y);var y_end:uint = Math.max(a.y, b.y);for (var y:uint = y_start + 1; y < y_end; y++)if ( _map.get(a.x, y) != 0 )return null;return _result.fill(a.clone(), b.clone());}/*** A 、B 之间有一个拐点* @param a* @param b* @return*/private function _oneCorner(a:Point, b:Point):MatchResult {var c:Point = new Point(a.x, b.y);var d:Point = new Point(b.x, a.y);var isMatch:Boolean = false;if (_map.get(c.x, c.y) == 0) //C 点上必须没有障碍{isMatch = _vTest(a, c) && _hTest(b, c);if (isMatch){_result.clear();return _result.fill(a.clone(), b.clone(), c.clone());}}if (_map.get(d.x, d.y) == 0) //D 点上必须没有障碍{isMatch = _hTest(a, d) && _vTest(b, d);if (isMatch){_result.clear();return _result.fill(a.clone(), b.clone(), d.clone());}}return null;}/*** 扫描两点决定的矩形范围内有没有完整的空白线段* @param a* @param b* @return*/private function _scanLine(a:Point, b:Point):DLinkedList {var v:DLinkedList = new DLinkedList();// 从a, c 连线向b 扫描，扫描竖线// 扫描A 点左边的所有线for (var x1:Number = a.x; x1 >= 0; x1--){var c1:Point = new Point(x1, a.y);var d1:Point = new Point(x1, b.y);// 存在完整路线-- c,d点为零且纵向连通if ( _map.get(x1, a.y) == 0 && _map.get(x1, b.y) ==0 && _vTest(c1, d1) )v.append( new Line(Line.VERTICAL, c1, d1) );}// 扫描A 点右边的所有线for (var x2:Number = a.x; x2 < _map.width; x2++) {var c2:Point = new Point(x2, a.y);var d2:Point = new Point(x2, b.y);if ( _map.get(x2, a.y) == 0 && _map.get(x2, b.y) ==0 && _vTest(c2, d2) )v.append( new Line(Line.VERTICAL, c2, d2) );}// 从a, d 连线向b 扫描，扫描横线// 扫描A 点上面的所有线for (var y1:Number = a.y; y1 >= 0; y1--){var c3:Point = new Point(a.x, y1);var d3:Point = new Point(b.x, y1);if ( _map.get(a.x, y1) == 0 && _map.get(b.x, y1) ==0 && _hTest(c3, d3) )v.append( new Line(Line.HORIZONTAL, c3, d3) ); }// 扫描A 点下面的所有线for (var y2:Number = a.y; y2 < _map.height; y2++) {var c4:Point = new Point(a.x, y2);var d4:Point = new Point(b.x, y2);if ( _map.get(a.x, y2) == 0 && _map.get(b.x, y2) ==0 && _hTest(c4, d4) )v.append( new Line(Line.HORIZONTAL, c4, d4) );}return v;}/*** 对所有找到的符合线进行判断，看看AC 、DB 是否同样也可以消除* @param a* @param b* @return*/private function _twoCorner(a:Point, b:Point):MatchResult{_vector = _scanLine(a, b);if (_vector.isEmpty()) return null; //没有完整的空白线段，无解var itr:Iterator = _vector.getIterator();while (itr.hasNext()){var ln:Line = itr.next() as Line;switch (ln.direct){case Line.HORIZONTAL:if ( _vTest(a, ln.a) && _vTest(b, ln.b) ){_result.clear();return _result.fill(a.clone(), b.clone(),ln.a.clone(), ln.b.clone());}break;case Line.VERTICAL:if ( _hTest(a, ln.a) && _hTest(b, ln.b) ){_result.clear();return _result.fill(a.clone(), b.clone(),ln.a.clone(), ln.b.clone());}break;}}return null;}private function _findRestPointA(map:Array2 = null):Point {var m:Array2 = map || _map;if (m.width >= m.height){for (var col:Number = 0; col < m.width; col++){var max_y:Number = Math.min(col + 1, m.height);for (var y1:Number = 0; y1 < max_y; y1++){if (m.get(col, y1) != 0)return new Point(col, y1);}for (var x1:Number = 0; x1 < col; x1++){if (m.get(x1, max_y-1) != 0)return new Point(x1, max_y-1);}}}else{for (var row:Number = 0; row < m.height; row++){var max_x:Number = Math.min(row + 1, m.width);for (var x2:Number = 0; x2 < max_x; x2++){if (m.get(x2, row) != 0)return new Point(x2, row);}for (var y2:Number = 0; y2 < row; y2++){if (m.get(max_x-1, y2) != 0)return new Point(max_x-1, y2);}}}return null;}private function _findRestPointB(a:Point, ignore_b_arr:Array= null):Point{if (!a) return null;var tempMap:Array2 = ArrayUtil.cloneArray2(_map);tempMap.set(a.x, a.y, 0);if (ignore_b_arr && ignore_b_arr.length){for each (var bb:Point in ignore_b_arr)tempMap.set(bb.x, bb.y, 0);}var b:Point = _findRestPointA(tempMap);if (!b) return null;while ( _map.get(a.x, a.y) != _map.get(b.x, b.y) ){tempMap.set(b.x, b.y, 0);b = _findRestPointA(tempMap);if (!b) return null;}return b;}/********************** 公开方法**********************//*** 测试两点是否可以连通* @param a* @param b* @usage 判断两点的值相同并且满足连通条件* @return*/public function test(a:Point, b:Point):Boolean{_result = new MatchResult();if (_map.get(a.x, a.y) != _map.get(b.x, b.y))return false;if ( _hTest(a, b) || _vTest(a, b) || _oneCorner(a, b) ||_twoCorner(a, b) )return true;elsereturn false;}/*** 自动寻找一条可连通的路径* @return*/public function autoFindLine():MatchResult{var a:Point = _findRestPointA(); if (!a) return null;var b:Point = _findRestPointB(a); if (!b) return null;var ignoreA:Array = [];var ignoreB:Array = [];while ( !this.test(a, b) ){ignoreB.push(b);b = _findRestPointB(a, ignoreB);//基于A没有可以连通的点了, 换一个A试试if (!b){ignoreB = [];ignoreA.push(a);var tempMap:Array2 = ArrayUtil.cloneArray2(_map);tempMap.set(a.x, a.y, 0);if (ignoreA.length)for each (var p:Point in ignoreA)tempMap.set(p.x, p.y, 0);a = _findRestPointA(tempMap);b = _findRestPointB(a);}}//找不到可以连通的B点if (!b) return null;return _result.clone();}/*** 清除两点* @param a* @param b*/public function earse(a:Point, b:Point):void{_map.set(a.x, a.y, 0);_map.set(b.x, b.y, 0);_restBlock -= 2;}/*** 刷新*/public function refresh():void{var num:uint = this.count;if (num <= 0) return;_array = ArrayUtil.random( ArrayUtil.getWarppedMapArray(_map) );ArrayUtil.drawWrappedMap(_array, _map);}} }。