Calculation for tower crane foundation 塔式起重机基础计算书Contents目录1. Design basis设计依据 (1)2. Stability calculation稳定性验算 (2)3. Forces and reinforcement calculation内力及钢筋计算 (4)1. Design basis设计依据1. Design rules for tower cranes(GB/T13752-1992)《塔式起重机设计规范》(GB/T13752-1992)2. Compilation and introduction of technical specification for concrete foundation engineering of tower crane(JGJ/T187-2009)《塔式起重机混凝土基础工程技术规程》(JGJ/T187-2009)3. Code for design of concrete structures(GB 50010-2010)《混凝土结构设计规范》(GB 50010-2010)4. Code for design of building foundation(GB 50007-2011)《建筑地基基础设计规范》(GB 50007-2011)5. Operation manual of Tower Crane《塔式起重机使用说明书》2. Stability calculation稳定性验算1.Contents计算内容Calculate foundation base on GB/T13752-1992:依据GB/T13752《塔式起重机设计规范》相关要求进行计算:1)Calculate on work status and non-work status respectively;按塔机工作状态和非工作状态载荷分别进行基础计算；2)Checking anti-overturning stability and ground compressive stress;抗倾覆稳定性验算及地面压应力验算；Calculation diagram计算简图Basic parameters基本参数Parameter参数Fk(kN) Mk(kN·m) Fkv(kN) Wind speed风速Work status工作状态1092 4147 39 (20m/s)Non-work status非工912 3856 137 作状态(42m/s)1.1.1 Anti-overturning stability calculation抗倾覆稳定性验算：e = (Mv + Fh × h) / (Fv + Fg) ≤ b / 4Where: e - eccentricity, distance from the ground reaction force to the foundation center. Unit: m式中:e--偏心距,即地面反力的合力到基础中心的距离.单位:mMv- tower bending moment acting on the foundation塔机作用在基础上的弯矩, Mv = 3856 × 1.2 = 4627KN.mFh- tower horizontal load acting on the foundation塔机作用在基础上的水平载荷, Fh = 137 × 1.2 = 164KNFv- tower vertical load acting on the foundation塔机作用在基础上的垂直载荷, Fv = 912 × 1.0 = 912KNFg- tower crane foundation weight塔机基础重量: Fg = 9 × 9 × 1.8 × 25 × 1.0 = 3645KNh- tower crane foundation thickness塔机基础厚度: h = 1.8mb- tower foundation side length塔机基础边长: b = 9mPut into the data, we have代入式中，得:e = (Mv + Fh × h) / (Fv + Fg) = (4627 +137 × 1.8) / (912 +3645) = 1.07 ≤ 9/4 = 2.25m,meet the anti-overturning stability requirement.满足抗倾覆验算。

1.1.2 Ground compressive stress checking calculation地面压应力验算:Pb = 2 (Fv + Fg) / 3 × b × LWhere: L-distance from ground reaction force to the edge of foundation式中：L-地面反力的合力到基础边缘的距离L = B/2-e = 9/2-1.07 = 3.43mFv, Fg values as above.Fv,Fg 数值同上.Put into the data, we have:代入数据,得:Pb = 2 (Fv + Fg) / 3 × b × L = 2 × (912 +3645) / (3 × 9 × 3.43) = 99 <130kPa, meet the capacity requirement满足要求。

1.2 Working status工作状态1.2.1 Anti-overturning stability calculation抗倾覆稳定性验算e = (Mv + Fh × h) / (Fv + Fg) ≤ b / 4Where: e - eccentricity, distance from the ground reaction force to the foundation center. Unit: m式中:e--偏心距,即地面反力的合力到基础中心的距离.单位:mMv- tower bending moment acting on the foundation塔机作用在基础上的弯矩, Mv = 4147 × 1.2 = 4976KN.mFh- tower horizontal load acting on the foundation塔机作用在基础上的水平载荷, Fh = 39 × 1.2 = 47KNFv- tower vertical load acting on the foundation塔机作用在基础上的垂直载荷, Fv = 1092 × 1.0 =1092KNFg- tower crane foundation weight塔机基础重量: Fg = 9 × 9 × 1.8 × 25 × 1.0 = 3645KNh- tower crane foundation thickness塔机基础厚度: h = 1.8mb- tower foundation side length塔机基础边长: b = 9mPut into the data, we have:e = (Mv + Fh × h) / (Fv + Fg) = (4976 +47 × 1.8) / (1092 +3645) = 1.07 ≤ 9/4 = 2.25m, meet the anti-overturning stability requirement满足抗倾覆验算。

1.2.2 Ground compressive stress checking calculation地面压应力验算:Pb = 2 (Fv + Fg) / 3 × b × Lwhere: L- distance from ground reaction force to the edge of foundation式中:L—地面反力的合力到基础边缘的距离L=B/2-e=9/2-1.247=3.43mFv, Fg value as above.Fv,Fg 数值同上Put into the data, we have:代入数据,得:Pb = 2 (Fv + Fg) / 3 × b × L = 2 × (1092 +3645) / (3 × 9 × 3.43) = 102Pa <130kPa, meet the capacity requirement满足要求。

3. Forces and reinforcement calculation内力及钢筋计算Calculation diagram计算简图Reinforcement钢筋符号：d - HPB300; D - HRB335; E - HRB400; F - RRB400; G - HRB500; P - HRBF335; Q - HRBF400; R - HRBF5001.Design data设计资料:1.1 known conditions已知条件:Type: ladder-shaped类型：阶梯形Number of columns: Single Column柱数：单柱Number of steps: 1阶数：1Foundation dimensions (Unit mm):基础尺寸(单位mm):b1 = 9000, b11 = 4500, a1 = 9000, a11 = 4500, h1 = 1800Column: square columns, A = 2000mm, B = 2000mm柱:方柱, A=2000mm, B=2000mmDesign values设计值: N = 1094.40kN, Mx = 4627.20kN.m, Vx = 0.00kN, My = 0.00kN.m, Vy = 164.40kNStandard value标准值: Nk = 912.00kN, Mxk = 3856.00kN.m, Vxk = 0.00kN, Myk = 0.00kN.m, Vyk = 137.00kNConcrete strength grade混凝土强度等级: C35, fc = 16.70N/mm2Rebar grade钢筋级别: HRB400, fy = 360N/mm2Foundation concrete cover thickness基础混凝土保护层厚度: 50mmThe average bulk density of soil and foundation基础与覆土的平均容重: 20.00kN/m3 Modified bearing capacity characteristic value修正后的地基承载力特征值: 130kPa Foundation depth基础埋深: 1.80mImpact position elevation作用力位置标高: 0.000mAdditional moment of shear force M '= V × h (arm of force h = 1.800m):剪力作用附加弯矩M'=V*h(力臂h=1.800m)：Mx '=-295.92kN.mMxk '=-246.60kN.m1.2 Calculation requirements计算要求:(1) Anti-shering calculation of foundation基础抗剪计算(2) Anti-punching calculation of foundation基础抗冲切验算(3) Anti-bending calculation of foundation基础抗弯计算Unit Description单位说明:Force: kN, torque: kN.m, stress: kPa力：kN, 力矩：kN.m, 应力：kPa2 Calculation process and calculation results计算过程和计算结果2.1 Anti-shearing checking calculation基础抗剪验算:Shear checking formula抗剪验算公式V <= 0.7 × βh × ft × Ac [GB50010-2010 clause 7.5.3 ](Calculate V according to the maximum net reaction force剪力V根据最大净反力pmax计算) Stage 1 (kN): V Down = 1548.52, V Rignt = 1548.52, V Up = 1548.52, V Left = 1548.52第1阶(kN): V下=1548.52, V右=1548.52, V上=1548.52, V左=1548.52Concrete shear area (m2): Ac Down = 15.70, Ac Rignt = 15.70, Ac Up = 15.70, Ac Left = 15.70砼抗剪面积(m2): Ac下=15.70, Ac右=15.70, Ac上=15.70, Ac左=15.70Meet anti-shearing requirement抗剪满足。