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钢结构习题答案第六章


最大弯矩设计值: M max =
1 1 ( g + q )l 2 = × 56.4 × 5.52 = 213.26KN ⋅ m 8 8
最大剪力设计值: Vmax =
1 1 ( g + q)l = × 56.4 × 5.5 = 155.1KN 2 2
①截面选择: 由 Wnx ≥
(2)当采用工字型截面时:
4 2 5 g k l 4 ( 5n + 2n + 1) p k l 3 νT = + 384 EI x 384n3 EI x
③腹板局部承压计算:由于在支座反力作用处设置了支承加劲肋,因而不必验算腹板的局部承压强度。
④刚度:梁跨中的最大绕度为:
4
νQ
(5n =
(5 × 54 + 2 × 52 +1) 5 × 3.06 × 18000 + × 119.61× 103 × 180003 3 1 18000 5 = × = 22.3mm ≤ [ν T ] = = 45mm 3 4 384 206 × 10 × 1097352 × 10 400
《钢结构》第六章
习题答案
1 解: (1)荷载统计: 图1 由板传给次梁的荷载(先不考虑工字梁的自重) : 则:次梁上的线荷载标准值为: 可变荷载效应控制的组合:
g k = 2.0 × 3 = 6KN / m, qk = 4.5 × 3 = 13.5KN / m
g k + q k = 6 + 13.5 = 19.5KN / m
主梁的自重: g k = 1.1× 7850 × 354 × 10 = 3.06KN/m (1.1 表示考虑加劲肋等的重量而采用的构造系数)
-6
1 M max = 2047.032 + 1.2 × × 3.06 × 182 = 2195.748KN ⋅ m 8 ;
Vmax = 379.08 + 1.2 × 0.5 × 3.06 ×18 = 412.13KN
③抗剪强度: V = (g + q)l =
查得:
1
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则:
τ =
VS x 75.816 × 10 3 × 289 × 10 3 = = 36.3N/mm 2 < f v = 180 N/mm 2 4 I xt w 7110 × 10 × 8.5
(3)截面验算: ① 强度:
M max 113.724 × 10 6 = = 213.2N/mm 2 ≤ f = 310 N/mm 2 γ xWnx 1.05 × 508 × 10 3
5 ( g k + qk )l 4 5 19.94 × 60004 6000 ②刚度: ν T = = × = 23mm ≤ [ν T ] = = 24mm 3 4 384 384 206 × 10 × 7110 × 10 250 EI x νQ = 5 qk l 4 5 13.5 × 60004 6000 = × = 15.55mm ≤ νQ = = 20mm 3 4 384 EI x 384 206 × 10 × 7110 × 10 300 1 2 1 × 25.27 × 6 = 75.816KN 2 S x = 289cm 3 , t w = 8.5mm
R = 2.5F = 2.5 ×151.632 = 379.08KN M max = (379.08 × 9)-151.632 × (6 + 3) = 2047.032KN ⋅ m
M x 2047.032 × 10 6 = = 6289cm 3 1.05 × 310 γx f
Wx =
②主梁高度:
主梁的最小高度:
(4)截面验算: ①强度:对于工字型截面 γ x = 1.05 ,故
M max 2195.748 × 10 6 = = 169.79N/mm 2 ≤ f = 295N/mm 2 满足要求。 3 γ xWnx 1.05 × 12316 × 10 ;
由于壁厚大于 16mm,故 f = 295N/mm
2
②抗剪强度:梁支座截面中性轴以上毛截面对中性轴的面积矩为:
5 ( g k + qk )l 3 5 19.5 × 60003 5 ( g k + qk )l 4 l IБайду номын сангаас≥ × 250 = × × 250 = 6656cm4 则: x 由ν T = ≤ [ν T ] = 3 384 E 384 384 EI x 250 ; 206 × 10
由此查附录 16,选择截面 I28a,自重 43.492kg / m = 0.44KN / m
hmin ≥
fl l 310 ×18000 = × 400 = 1736mm 1285440 [ν T ] 1285440
主梁的经济高度:
h e = 7 3 Wx − 30 = 7 3 6289 − 30 = 99.21cm = 992.1mm
h e = 2Wx0.4 = 2 × 6289000 0.4 = 1048mm ;因此取腹板的高度为 hw = 1750mm Vmax 379.08 × 10 3 1 . 2 1 . 2 t ≥ = × = 1.44mm ③腹板的厚度: w 1750 × 180 h f
取 t=18mm ;
(3)根据以上的条件,初步确定梁的截面尺寸,其截面特征:
A = 40 ×1.8 × 2 + 175 ×1.2 = 354cm2
1 1 2 × 40 × 1.8 3 × 2 + 40 × 1.8 × (0.8 + 175/2) × 2 + × 1.2 × 175 3 = 1097352cm 4 12 12 Ix 1097352 Wx = = = 12316cm 3 18 + 175/2 18 + 175/2 Ix =
④整体稳定性:由于铺板为与之钢筋混凝土板,且焊接于次梁上,故整体稳定性满足要求。 因此,次梁的强度,刚度,抗剪强度整体稳定性均满足要求。
2.解:简支梁的挠度容许值(附表9) : 按照最小高度选取主梁梁高和腹板高度
[ν T ] =
l l νQ = 400 , 500 。钢材的弹性模量: E = 206 × 103 N/mm 2 。
M max 213.26 × 10 6 = = 944.7cm 3 1.05 × 215 γx f
选择 I40a,自重 67.598kg / m = 0.67598KN / m ;
I x = 21700cm 4 ,Wnx = 1090cm 3,S x = 636cm 3,t w = 10.5mm
考虑自重后荷载标准值:
②截面验算:
Vmax =
2
由于16mm < t = 16.5mm < 40mm, 故取 f = 205N/mm
强度:
σ=
M max 216.33 × 10 6 = = 189.02N/mm 2 ≤ f = 205N/mm 2 γ xWnx 1.05 × 1090 × 10 3
τ=
VS x 157.33 × 10 3 × 636 × 10 3 = = 43.92 N/mm 2 < f v = 120 N/mm 2 4 I xt w 21700 × 10 × 10.5 5500 5 ( g k + qk )l 4 5 42.68 × 55004 = 11.36mm ≤ [ν T ] = = 22mm = × 3 4 250 384 384 206 × 10 × 21700 × 10 EI x

可变荷载效应控制的组合: q = γ Gσ GK + γ Q1σ Q1 K = g + q = 1.2 × 12 + 1.4 × 30 = 56.4KN / m 永久荷载效应控制的组合: q = γ Gσ GK +
∑γ
i =1
n
Qi
ψ ciσ QiK = 1.35 × 12 + 1.4 × 0.7 × 30 = 45.6kN/m
g k + q k = 42 + 0.68 = 42.68KN / m

g + q = 56.4 + 1.2 × 0.68 = 57.22KN / m
1 1 ( g + q )l = × 57.22 × 5.5 = 157.33KN 2 2
1 1 M max = ( g + q)l 2 = × 57.22 × 5.52 = 216.33KN ⋅ m 8 8
(1)内力计算:由次梁传递给主梁的集中力大小为:
1 1 F = 2 × (g + q)l = 2 × × 25.272 × 6 = 151.632KN 2 2
1 1 Fk = 2 × (g k + q k)l = 2 × × 19.935 × 6 = 119.61KN 2 2
则主梁的支座反力为: 最大的弯矩设计值: (2)初估主梁截面 ①对于工字型截面 γ x = 1.05 ,故需要的净截面模量为
I x = 7110cm 4 ,Wnx = 508cm 3
考虑自重后荷载标准值:
g k + qk = 6 + 13.5 + 0.44 = 19.94KN / m
1 g + q = 24.75 + 1.2 × 0.44 = 25.27KN / m ; M max = 111.375 + 1.2 × × 0.44 × 62 = 113.724KN ⋅ m 8
4
+ 2n 2 + 1) p k l 3
384n3
(5 × 54 + 2 × 52 +1) 13.5 × 6 ×103 × 180003 18000 == × = 13.8mm ≤ νQ = = 36mm 3 3 4 EI x 384 × 5 206 × 10 × 1097352 × 10 500 ;
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