专题 集合 真题1. (19年北京卷理01)已知集合{}12A x x =−<<,{}1B x x =>,则AB =A.()1,1−B.()1,2C.()1,−+∞D.()1,+∞【答案】C2. (18年北京卷理01)已知集合{}||2A x x =<,{}2,0,1,2B =−,则A B =(A ){}0,1 (B ){}1,0,1− (C ){}2,0,1,2− (D ){}1,0,1,2−【答案】A3.(17年北京卷理01)若集合,或,则(A ) (B ) (C ) (D ) 【答案】A4.(17年北京卷文01)已知,集合或,则(A ) (B )(C ) (D )【答案】C5.(16年北京卷理01)已知集合,,则(A ) (B )(C )(D ){21}A x x =−<<{|–1B x x =<3}x >AB ={21}x x −<<−{23}x x −<<{11}x x −<<{13}x x <<U =R {|2A x x =<−2}x >UA =(2,2)−(,2)(2,)−∞−+∞[2,2]−(,2][2,)−∞−+∞={| ||<2}A x x {}10123B =−,,,,A B ={0,1}{0,1,2}{1,0,1}−{1,0,1,2}−【答案】A6.(16年北京卷文01)已知集合{|24},{|3A x x B x x =<<=<或5}x >,则A B = (A ){|25}x x << (B ){|4x x <或5}x >(C ){|23}x x <<(D ){|2x x <或5}x >【答案】C7.(15年北京卷文01)若集合{|52},A x x =−<<{|33},B x x =−<<则AB =(A ){|32}x x −<< (B ){|52}x x −<< (C ){|33}x x −<< (D ){|53}x x −<<【答案】A8.(15年北京卷理01)已知集合2{|20},{0,1,2}A x x x B =−==,则AB =(A ){0} (B ){0,1}(C ){0,2} (D ){0,1,2}【答案】C9.(14年北京卷文01)已知集合{0,1,2,4},{1,2,3}A B ==,则AB =(A ){0,1,2,3,4} (B ){0,4}(C ){1,2}(D ){3}【答案】C模拟一、选择题1. (2016-2017东城区高三一模理01)已知集合2{|20}A x x x =−−<,{|13}B x x =<<,则A B =(A ){|13}x x −<< (B ){|11}x x −<<(C ){|12}x x <<(D ){|23}x x <<【答案】A【解析】集合{|12}A x x =−<<,集合{|13}B x x =<< 则{|13}A B x x =−<<2. (2016-2017西城区高三一模理01)已知全集U =R ,集合{|2}A x x =<,{|0}B x x =<,那么UAB =(A ){|02}x x ≤< (B ){|02}x x <<(C ){|0}x x <(D ){|2}x x <【答案】本题选(A ) 【解析】本题考查集合的运算.{|0}UB x x =≥,从而{|02}UAB x x =≤<.3.(2016-2017海淀区高三一模理01)已知集合{}|(1)0A x x x =+≤,集合{}|0,B x x =>则AB =(A ){}|1x x ≥− (B ){}|1x x >− (C ){}|0x x ≥ (D ){}|0x x >【答案】本题选(A ) 【解析】本题考查集合的运算.集合{}|10A x x =−≤≤,从而{}|1A B x x =≥−.【解析】本题考察集合.{1,0,1}B =−,所以{1,0,1}A B =−. 【答案】D4.(2016-2017房山区高三一模理01)已知集合2{|4},{|0}A x x B x x =≤=≥,则A B =(A ){|02}x x ≤≤(B ){|2}x x ≥−(C ){0,1,2}(D ){1,2} 【答案】A5.(2016-2017东城区高三二模理01)已知集合{}2=|40A x x −<,则R C A =(A ){|2x x ≤−或}2x ≥(B ){|2x x <−或}2x > (C ){}|22x x −<<(D ){}|22x x −≤≤【答案】A 【解析】{}|22A x x =−<<{|2R C A x x ∴=≤或}2x ≥,所以选A .6.(16-17北京市朝阳区一模文 01)已知集合{}{}2|13,|4,A x x B x x =−≤<=∈<Z 则A B =(A ){0,1} (B ){1,0,1,2}−(C ){1,0,1}−(D ){2,1,0,1,2}−−【答案】本题选C.【解析】本题考查集合的运算.集合{}2|4B x x =∈<Z ,即{}1,0,1B =−,因此{}1,0,1A B =−.7.(16-17北京市东城区一模文 01)如果{|0}A x x =∈>R ,{0,1,2,3}B =,那么集合A B =(A )空集 (B ){0} (C ){0,1} (D ){1,2,3}【答案】本题选D.【解析】本题考查集合的运算.在B 集合中,大于0的数有1,2,3,所以{1,2,3}A B =.8.(16-17北京市房山区一模文 01)已知集合2{|230},{|22}A x x x B x x =−−≥=−≤≤,则A B =A .{|12}x x ≤≤B .{|12}x x −≤≤C .{|11}x x −≤≤D .{|21}x x −≤≤− 【答案】本题选D.9.(16-17北京市丰台区一模文 01)如果集合{}21A x x =∈−≤<Z ,{}101B =−,,,那么AB =(A ){}2101−−,,, (B ){}101−,,(C ){}01,(D ){}10−,【答案】本题选D.10.(16-17北京市海淀区一模文 01)设集合{}|13A x x =<<,集合2{|4}B x x =>,则集合A B 等于(A ){}|23x x << (B ){}|1x x >(C ){}|12x x <<(D ){}|2x x >【答案】本题选A.【解析】本题考查集合.因为{|13},{|2,2}A x x B x x x =<<=<−>,所以{}|23A B x x =<<.11.(16-17北京市西城区一模文 01)已知全集{1,2,3,4,5,6}U =,集合{1,3,5}A =,{1,4}B =,那么UAB =(A ){3,5}(B ){2,4,6}(C ){1,2,4,6} (D ){1,2,3,5,6}【答案】本题选A.【解析】本题考查集合的运算.因为{2,3,5,6}UB =,所以{3,5}UAB =.12.(16-17北京市东城区二模文 01)已知全集U 是实数集R .右边的韦恩图表示集合{|2}M x x =>与{|13}N x x =<<的关系,那么阴影部分所表示的集合可能为(A ){|2}x x < (B ){|12}x x <<(C ){|3}x x >(D ){|1}x x ≤【答案】本题选D.【解析】本题考查集合的运算.由图象可知阴影表示的是集合U()MN ,{|1}MN x x => ,所以U(){|1}MN x x =≤,故选D.13.(16-17北京市房山区二模文 01)集合{}30Z A x x =∈−<<,集合{}29Z B x x =∈<,则A B =(A ){}2,1−−(B ){}2,1,0,1,2−−(C ){}03x x <<(D ){}33x x −<<【答案】本题选B.14.(16-17北京市丰台区二模文 01)已知集合,那么(A ) B )] (C )[ (D )【答案】本题选C15.(16-17北京市海淀区二模文 01)若集合{}=2,0,1A −,{}=|1B x x <−或0x >则=AB.A {}2−.B {}1.C {}21−,.D {}2,0,1−{}{}142,A x xB x x =≤≤=>A B =(24),(24,1+),∞(2),+∞【答案】C 【解析】21,10−<−>,{}21A B ∴=−,所以选C .16.(16-17北京市西城区二模文01)已知集合{|11}A x x =∈−<<R ,{|(2)0}B x x x =∈⋅−<R ,那么A B =(A ){|01}x x ∈<<R (B ){|02}x x ∈<<R(C ){|10}x x ∈−<<R (D ){|12}x x ∈−<<R【答案】A【解析】{}A |11x R x =∈−<<,集合{}B |02x R x =∈<<,所以{}A B |01x R x ⋂=∈<<,故选择A17.(17-18丰台区高三一模理01)设全集5{|}x U x <=,集合20{|}x A x −≤=,则UA =(A )2{|}x x ≤(B )2}{|x x >(C )25}{|x x << (D )25}{|x x ≤<【答案】C18.(17-18房山区高三一模理01)若集合{1,0,1,2}M =−,{|21,}N y y x x M ==+∈,则集合N M等于(A ){1,1}− (B ){1,2} (C ){1,1,3,5}− (D ){1,0,1,2}−【答案】A19.(17-18东城区高三二模理01)若集合{|12}A x x =−<<,{|2B x x =<−或1}x >,则A B =(A ){|2x x <−或1}x >(B ){|2x x <−或1}x >−(C ){|22}x x −<<(D ){|12}x x <<【答案】B【解析】集合{|12}A x x =−<<,{|2B x x =<−或1}x >所以A B ={|2x x <−或1}x >−.故选B .20.(17-18朝阳区高三二模理01)已知集合2{|log 1},{|1}A x x B x x =>=≥,则A B =(A )(1,2] (B )(1,)+∞ (C )(1,2) (D )[1,)+∞【答案】D【考点】本题考查对数不等式与集合运算. 【解析】由2log 1x >,得2x >. 所以A B =[1,)+∞ 故选D21.(17-18丰台区高三二模理01)已知{|1}A x x =>,2{|230}B x x x =−−<,则A B =(A ){|1x x <−或1}x ≥ (B ){|13}x x << (C ){|3}x x > (D ){|1}x x >−【答案】D22.(17-18北京市朝阳区一模文 01)已知全集为实数集R ,集合22{|30},{|log 0}A x x x B x x =−<=> ,则()R A B =(A )(,0](1,)−∞+∞ (B )(0,1] (C )[3,)+∞ (D )∅【答案】C【解析】本题考查集合的运算.集合2{|30}{|(3)0}{|03}A x x x x x x x x =−<=−<=<<,集合222{|log 0}{|log log 1}{|1}B x x x x x x =>=>=>. 所以{|0RA x x =≤或3}x ≥,所以(){|3}R AB x x =≥,故选C .23.(17-18北京市东城区一模文 01)若集合{|31}A x x =−<<,{1B x x =<−或2}x >,则A B =(A){|31}x x−<<−(B){|32}x x−<<(C){|11}x x−<<(D){|12}x x<<【答案】A【解析】由题易知,{|31}A B x x=−<<−,故选A24.(17-18北京市房山区一模文01)若集合{1,0,1,2}M=−,{|21,}N y y x x M==+∈,则集合NM等于(A){1,1}−(B){1,2}(C){1,1,3,5}−(D){1,0,1,2}−【答案】A25.(17-18北京市海淀区一模文01)已知集合{0,},{|12}A aB x x==−<<,且A B⊆,则a可以是(A)1−(B)0(C)1(D)2【答案】C【考点】本题考查集合之间的关系及集合中元素的互异性.【解析】{0,},A a=由集合中元素的互异性得:0a≠,又{0,},{|12}A aB x x==−<<,且A B⊆,12a∴−<<且0a≠1a∴=故选C26.(17-18北京市西城区一模文01)若集合{|320}RA x x=∈+>,2{|230}RB x x x=∈−−>,则A B=(A){|1}Rx x∈<−(B)2 {|1}3Rx x∈−<<−(C)2{|3}3Rx x∈−<<(D){|3}Rx x∈>【答案】D{|3}R A B x x =∈>,故选D .27.(17-18北京市朝阳区二模文 01)已知集合2{|320},{|1}A x x x B x x =−+<=≥,则A B =(A )(,2]−∞ (B )(1,)+∞(C )(1,2) (D )[1,)+∞【答案】D【考点】本题考查一元二次不等式解法与集合运算 【解析】由2320x x −+<,得(2)(1)0x x −−<,所以12x <<, 所以A B =[1,)+∞ 故选D28.(17-18北京市东城区二模文 01)已知全集R U =,集合{10}A x x =+<,{40}B x x =−≤,则()UA B =(A ){|1x x ≤−或4}x >(B ){|1x x ≥−或4}x < (C ){|1}x x ≥−(D ){|4}x x >【答案】C【解析】集合{|1}A x x =<−,{|4}B x x =≤,所以{|1}A B x x =<−,(){|1}UA B x x =≥−,故选C .29.(17-18北京市房山区二模文 01)设集合{|2},{|03}A x x B x x =≤=<<,则A B =(A ){|2}x x ≤ (B ){|3}x x < (C ){|23}x x << (D ){|23}x x ≤<【答案】B30.(17-18北京市丰台区二模文 01)已知R U =,2{|230}A x x x =−−<,则UA =(A ){|1x x ≤−或3}x ≥(B ){|3x x ≤−或1}x ≥(C ){|1x x <−或3}x > (D ){|3x x <−或1}x >【答案】A31.(17-18北京市海淀区二模文 01)已知全集{1,2,3,4,5,6}U =,集合{1,2,4},{1,3,5}A B ==,则()U A B =(A ){1} (B ){3,5} (C ){1,6}(D ){1,3,5,6}【答案】B【考点】本题考查集合的运算. 【解析】{1,2,3,4,5,6}U =,{1,2,4}A =, 所以{3,5,6}UA =,又因为{1,3,5}B =, 所以(){3,5}U A B =,故选B32.(17-18北京市西城区二模文 01)若集合{|01}A x x =<<,2{|20}B x x x =−<,则下列结论中正确的是(A ) A B =∅ (B ) R A B =(C ) A B ⊆ (D ) B A ⊆【答案】C【解析】2{|20}{|02}B x x x x x =−<=<<,{|01}A B x x A =<<=,{|02}A B x x B =<<=,所以A B ⊆.故选C .33.(18-19朝阳区高三一模理01)已知集合{|1}A x x =>,集合2{|4}B x x =<,则A B =(A ){|2}x x >−(B ){|12}x x <<(C ){|12}x x ≤<(D )R【答案】B34.(18-19东城区高三一模理01)已知集合2{20},{210},A x x x B x x =+>=+>则AB =(A )1{|}2x x >−(B )1{|}2x x >(C ){0}x x >(D )R【答案】C35.(18-19丰台区高三一模理02)已知集合,集合.若,则实数的取值集合为 (A )(B )(C )(D )【答案】C36.(18-19海淀区高三一模理01)已知集合{}04P x x =<<,且M P ⊆,则M P ⊆可以是(A){1,2} (B){2,4}(C){1,2}−(D){0,5}【答案】A37.(18-19怀柔区高三一模理01)若集合{|12}A x x =−<<,{|13}B x x =≤≤,则AB =(A )(1,2)− (B )[1,2)(C )[1,3](D )(1,3]−【答案】B38.(18-19门头沟区高三一模理01)已知集合2{|230},{|A x x x B x y =−−<==,则A B 等于(A )1,3)−((B )[0,3)(C )(1,0]−(D )(1,2]−【答案】B39.(18-19顺义区高三二模理01)已知全集U {0,1,2}=,集合2{|0}A x x x =−=,则UA =(A ){2}) (B ){0,1} (C ){0,2} (D ){1,2}【答案】C40.(18-19西城区高三一模理01)设全集U =R ,集合{|0}2A x x =<<,{3,1,1,3}B =−−,则集合()U A B =(A ){3,1}−− (B ){3,1,3}−−(C ){1,3}(D ){1,1}−【答案】B41.(18-19延庆区高三一模理01)已知集合(){}10A x x x =+≤,集合{}11B x x =−<<,则=A B{2,3,1}A =−2{3,}B m =B A ⊆m{1}{1,1}−(A ){}-11x x ≤≤ (B ){}-10x x <≤ (C ){}-11x x ≤< (D ){}01x x <<【答案】C42.(18-19北京市朝阳区一模文 03)已知集合{1,2,3,4,5}A =,且A B A =,则集合B 可以是(A ){|21}xx >(B )2{|1}x x >(C )2{|log 1}x x >(D ){1,2,3}【答案】A43.(18-19北京市海淀区一模文 01)已知集合{}02P x x =≤≤,且M P ⊆,则M 可以是(A ){}0,1 (B ){}13, (C ){}1,1− (D ){}0,5【答案】A44.(18-19北京市丰台区一模文 01)已知全集U =R ,{|1}A x x =>,2{|1}B x x =>,那么()UA B 等于(A ){|11}x x −<≤ (B ){|11}x x −<<(C ){|1}x x <−(D ){|1}x x −≤【答案】C45.(18-19北京市怀柔一模文 01)若集合{}A =-1,0,1,{}0,1,2B =,则AB =(A ){}0,1 (B ){}-1,0,1 (C ){}0,1,2(D ){}1,0,1,2−【答案】A46.(18-19北京市石景山一模文 01)已知集合{|1}P x x =∈R ≥,{1,2}Q =,则下列关系中正确的是(A )P Q = (B )P Q (C )Q P(D )P Q =R【答案】C47.(18-19北京市延庆区一模文 01)已知集合(){}10A x x x =+≤,集合{}11B x x =−<<,则=A B(A ){}-11x x ≤≤(B ){}-11x x ≤<(C ){}-10x x <≤(D ){}01x x <<【答案】B48.(18-19西城区高三二模理01)已知集合1{|1}A x x =>,1{2,,3}2B =−,则A B =(A )1{2,}2−(B )1{}2(C )1{,3}2(D )∅【答案】B49.(18-19昌平区高三二模理01) 已知全集U =R ,集合2{|1}A x x =≤,则UA =(A )(,1)(1,)−∞−+∞(B )(,1][1,)−∞−+∞ (C )(1,1)−(D )[1,1]−【答案】A50.(18-19东城区高三二模理01)已知集合2{2,1,0,1,2},{20}A B x x x =−−=−−≤,则AB =R(A ){2}− (B ){01},(C ){2,1,2}−−(D ){1,0,1,2}−【答案】A51.(18-19北京市海淀区二模文 01)已知集合{|15},{|36}A x x B x x =≤≤=≤≤,则A B =(A )[1,3] (B )[3,5] (C )[5,6] (D )[1,6]【答案】B52.(18-19北京市西城区二模文 01)设集合{|13},{|0A x x B x x =<<=<或2}x >,则=A B (A ){|0x x <或23}x << (B ){|23}x x <<(C ){|0x x <或1}x > (D ){|01x x <<或23}x <<【答案】B53.(18-19北京市昌平区二模文 01)已知集合2{|9}U x x =∈<Z ,集合{2,2}A =−,则UA =(A ){1,0,1}− (B ){1,1}−(C )[1,1]−(D )(1,1)−【答案】A54.(18-19北京市房山二模文 01)已知全集U =R ,集合{(3)0}A x x x =−>,则UA =(A )[0,3] (B )(,3]−∞ (C )(,0)(3,)−∞+∞(D )(,0][3,)−∞+∞【答案】A55.(18-19北京市丰台二模文 01)若集合2{|4}A x x =∈≤Z ,集合{|13}B x x =−<<,则A B =(A ){0,1,2} (B ){1,0,1,2}− (C ){1,0,1,2,3}−(D ){|12}x x −<≤【答案】A56.(18-19北京市朝阳区二模文 01)已知集合{|1}A x x =>,{|(2)0}B x x x =−<,则A B =(A ){|0}x x > (B ){|12}x x << (C ){|12}x x ≤<(D ){|0x x >且1}x ≠【答案】C 二、填空题57,.(16-17北京市朝阳区二模文 09)已知集合{}121x A x −=>,(){}20B x x x =−<,则AB =_______.{1AB x =<58.(17-18北京市丰台区一模文 09)已知集合{|20}A x x =−≤≤,{|03}B x x =<≤,则A B =______. 【答案】{|23}x x −≤≤59.(18-19北京市朝阳区二模文 14)设全集{1,2,3,,20}U =,非空集合A ,B 满足以下条件:①A B U =,A B =∅;②若,x A y B ∈∈,则x y A +∉且xy B ∉.当7A ∈时,1______B (填∈或∉),此时B 中元素个数为______. 【答案】∈;1860.(18-19北京市延庆区一模文 14)已知集合{}115M x N x =∈≤≤,集合123,,A A A 满足①每个集合都恰有5个元素;②123A A A M =.集合i A 中元素的最大值与最小值之和称为集合i A 的特征数,记为i X (1,2,3i =),则123X X X ++的最大值与最小值的和为 . 【答案】9661.(18-19海淀区高三二模理14)已知集合0{|01}A x x =<<.给定一个函数()y f x =,定义集合1{(),}n n A y y f x x A −==∈,若1n n A A −=∅对任意的n *∈N 成立,则称函数()y f x =具有性质“P ”.(Ⅰ)具有性质“P ”的一个一次函数的解析式可以是_____; (Ⅱ)给出下列函数:①1y x=;②2+1y x =;③πcos()22y x =+,其中具有性质“P ”的函数的序号是_____.(写出所有正确答案的序号)【答案】1y x =+(答案不唯一),①②。