if (k == 12) { if (wCurMonth == wNongliData[m] / 65536 + 1)
wCurMonth = 1 - wCurMonth; else if (wCurMonth > wNongliData[m] / 65536 + 1) wCurMonth = wCurMonth - 1; } /*--生成农历天干、地支、属相 ==> wNongli--*/ wsprintf(szShuXiang,"%s",cShuXiang[((wCurYear - 4) % 60) % 12]); wsprintf(szNongli,"%s(%s%s) 年 ",szShuXiang,cTianGan[((wCurYear - 4) % 60) % 10],cDiZhi[((wCurYear - 4) % 60) % 12]); /*--生成农历月、日 ==> wNongliDay--*/ if (wCurMonth < 1) wsprintf(szNongliDay,"闰%s",cMonName[-1 * wCurMonth]); else strcpy(szNongliDay,cMonName[wCurMonth]); strcat(szNongliDay,"月"); strcat(szNongliDay,cDayName[wCurDay]); return strcat(szNongli,szNongliDay); }
"七","八","九","十","十一","腊"}; /*公历每月前面的天数*/ const int wMonthAdd[12] = {0,31,59,90,120,151,181,212,243,273,304,334}; /*农历数据*/ const int wNongliData[100] = {2635,333387,1701,1748,267701,694,2391,133423,1175,396438
"未","申","酉","戌","亥"}; /*属相名称*/ const char *cShuXiang[] = {"鼠","牛","虎","兔","龙","蛇",
"马","羊","猴","鸡","狗","猪"}; /*农历日期名*/ const char *cDayName[] = {"*","初一","初二","初三","初四","初五",
static int wCurYear,wCurMonth,wCurDay; static int nTheDate,nIsEnd,m,k,n,i,nBit; TCHAR szNongli[30], szNongliDay[10],szShuXiang[10]; /*---取当前公历年、月、日---*/ wCurYear = pSt->wYear; wCurMonth = pSt->wMonth; wCurDay = pSt->wDay; /*---计算到初始时间 1921 年 2 月 8 日的天数：1921-2-8(正月初一)---*/ nTheDate = (wCurYear - 1921) * 365 + (wCurYear - 1921) / 4 + wCurDay + wMonthAdd[wCurMonth - 1] - 38; if((!(wCurYear % 4)) && (wCurMonth > 2)) nTheDate = nTheDate + 1; /*--计算农历天干、地支、月、日---*/ nIsEnd = 0; m = 0; while(nIsEnd != 1) { if(wNongliData[m] < 4095)
"初六","初七","初八","初九","初十", "十一","十二","十三","十四","十五", "十六","十七","十八","十九","二十", "廿一","廿二","廿三","廿四","廿五", "廿六","廿七","廿八","廿九","三十"};
/*农历月份名*/ const char *cMonName[] = {"*","正","二","三","四","五","六",
公历转农历(C 版本)
Tags：版本 wCurMonth wCurYear if 农历 nTheDate nBit const 公历转农历(C 版本) PHP 开发环境的选择、建立及使用[8] 编写自定义任务，轻松扩展 Ant (2) 代联接的自定义右键 菜单面试中如何体现身价希特勒生日（4 月 20 日）突破生命中那条线怎么用 ado 打开带密 码的 access 数据库算法复杂度攻击激烈讨论在 Visual StudBiblioteka 中使用自定义插 公历转农 历(C 版本) 版本 wCurMonth wCurYear if 农历 nTheDate nBit const
,3402,3749,331177,1453,694,201326,2350,465197,3221,3402 ,400202,2901,1386,267611,605,2349,137515,2709,464533,1738 ,2901,330421,1242,2651,199255,1323,529706,3733,1706,398762 ,2741,1206,267438,2647,1318,204070,3477,461653,1386,2413 ,330077,1197,2637,268877,3365,531109,2900,2922,398042,2395 ,1179,267415,2635,661067,1701,1748,398772,2742,2391,330031 ,1175,1611,200010,3749,527717,1452,2742,332397,2350,3222 ,268949,3402,3493,133973,1386,464219,605,2349,334123,2709 ,2890,267946,2773,592565,1210,2651,395863,1323,2707,265877};
前段时间做软件写了个公历转农历的函数,目前公开给大家参考,有兴趣的朋友可以在此 基础上进一步完善其功能 /*------------农历转换函数-----------*/ char *GetDayOf(PSYSTEMTIME pSt) { /*天干名称*/ const char *cTianGan[] = {"甲","乙","丙","丁","戊","己","庚","辛","壬","癸"}; /*地支名称*/ const char *cDiZhi[] = {"子","丑","寅","卯","辰","巳","午",
k = 11; else k = 12; n = k; while(n>=0) { //获取 wNongliData(m)的第 n 个二进制位的值 nBit = wNongliData[m]; for(i=1;i<n+1;i++)
nBit = nBit/2; nBit = nBit % 2; if (nTheDate <= (29 + nBit)) { nIsEnd = 1; break; } nTheDate = nTheDate - 29 - nBit; n = n - 1; } if(nIsEnd) break; m = m + 1; } wCurYear = 1921 + m; wCurMonth = k - n + 1; wCurDay = nTheDate;