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2019最新aA公路桥梁设计规范答疑物理


HRB400 2080 2090
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GB50010-2002:
HRB400 HRB335
.
JTG D62 HRB400
HRB400
4
137-138 T
T
T
T bf bf
T JTG D62
5
5.2
5.2.1-5.2.3
T
JTG D62T
JTG D62
N 0
0 Nd fcdbx fsd As s As
7.2-3
M As 0
0 Nd es
fcd bx(h0
x) 2
fsd
As (h0
as )
7.2-4
M As 0
0 Nd es
x fcdbx( 2
as )
s
As
(h0
as )
7.2-5
MN 0
fcd bx(es
Ah02 Bh0 C 0
A fcdb (1 0.5 )
B fcd (b'f b)h'f
C
0Md
1 2
fcd (b'f
b)h'f 2
b ABC,, h0 h h0 a
xb h0
(). ,
,, x b h0., (). ,, . ,
(3)
JTG D62 x 2a' x 2as'
2 ---- 2 1.0 2 1.25
2 1.0 3 ---- 3 1.1
b ----TI
mm
h0 ---- mm
p ---- p 100
( Ap Apb As ) / bh0 p>2.5p=2.5 fcu,k ----150mm
Mpa sv ----sv Asv / svb
ftdWt
0.05
N p0 A0
Wt
)
1.2
fsdv Asv1Acor Svt
Tu 0Td
Tu 0Td
6
JTG D62
6.3
JTG D62
1
st 0.85 pc 0
st 0.8 pc 0
9.2-1
2A
st pc 0.7 ftk
9.2-2
lt pc 0
----C50 =0.8C80 =0.74
x ----
hoi ----i
es --
es '
es
e0
h0
h 2
--
eo --
eo
Md Nd
--7.2-2
N 0 M 0 .
.
1
AsAsx
0e0 h0 0x.3 x bh0
s fsd x bh0 7.2-4 7.2-5 As As 0e0 h0 0.3 As 0.002bh As x As
s p =0.002 x 2as' x 2a'
JTG D62 x 2 x 2s
[
' pd
' p0
]
0Md f pd Ap (h ap a) fsd As (h as a)
5.2-10
[
] ' pd
' p0
0Md
'
f pd Ap (h ap as )s
fsd As (h as as' ) ( f pd p0)Ap (h a'p as')
5.2-11
5.2-10 ,5.2-11 .
(152)
5.2.5-1(5.2-10)
(a` a`s), ,?
: ( x 2a' ),
,
.
a`.
(
' pd
' p0
).
,
x 2s
(
' pd
po
po
B Mcr.
poNpe. pc.p, pc.p= pc.p Ep,, pc.p.
po= pe+ pc.p po= pe Ep pc.p
----Mcr Mud ----
M cr
b
(2
x b h0
xb----""
b----
1481150 4
x b h0
x b h0
x b h0
x b h0 h0
x0.7 b h0
99(,)
h/L
5.1-9T As ' 0, Ap ' 0 x h0 h0
.
.
(222):
A ( lt pc 0 ).
, ,,.
: A, . .,, ., (),. . ,, , ,.
f : Lc0.450.55 ck.
A
9.2-19.2-2
(1)
()
M s MGK 0.7MQ1K /(1 ) MQ2K
st M s /W0
1
N p0 p0 Ap p0 Ap l6 As l6 As
9.2-12
ep0
p0 Ap yp0 p0 Ap yp0 l6 As ys0 l6 As ys0 p0 Ap p0 Ap l6 As l6 As
9.2-13
p0 con l l 4
9.2-14
p0 con l l4 2
=1.01.3
211
8.1.1 8.1.4
0.6 1.7
5.5.6
JTG D62
1
(8.2-9)(8.2-10)
2(8.2-3) t
3(8.2-8) Asv.1
4 Ast
5 5)Asv1Ast(8.2(8.2-5)6tAsv1
Tu
t
(0.35a
Vcs ----
Vsb ---- Vpb ----
Vcs 1230.45103bh0 2 0.6 p f f cu,k sv sd,v KN
Vsb 0.75103 fsd,b Asb sins KN
Vpb 0.75103 fpd.b Apb sinp
KN
1 ----
1 1.0 1 0.9
5.1-6
[( f pd p0 )]
x2a`s
5.1-7
2 x hf T5.1-b 5.1-1
X=0
(5.1-8)
MZ=0
fcdbx fcd (bf b)hf fsd As ( f pd p0 ) Ap fsd As f pd Ap
(5.1-9)
0Md
f cd bx(h0
x) 2
yp0 ypn ----
yp0 ypn ----
ys0 ysn ----
ys0 ysn ----
l l ----
l6 l6 ----
l4 l4 ----
con con ----
L4.
() ,.(6.1.51)Npo , L4.
(213121513): po ?po?
as ) ( f pd
p0 ) A' (h0
ap )
5.1-3
MD=0
0M d
fsd As
h
as
x 2
f pd Ap (h ap
x) 2
f
sd
As
(
x 2
as ) ( f pd
p
0
)
Ap
(
x 2
ap ) 5.1-4
x bh0
5.1-5
[( f pd p0 )] x2a'
b`f15.1-1.xah`f
fsd As f pd Ap fcdbf hf fsd As f pd p0 Ap
5.1-1
X=0
fcd bf x fsd As ( f pd p0 ) Ap fsd As f pd Ap
5.1-2
MZ=0
0Md
fcd
bf
x
h0
x 2
fsd As(h0
a 1.0
:
,h ,b .
, h,
b
t10.1h t20.1b
(8.1.1) N p0
(8.1.1)
Ast f sd .t Svt
Asv.1 f sd u .v cor
(8.1.4)
0.5 ~ 2.0 JTG D62 0.6 1.7
:
JTG D620.6 1.7
0.75 Apv f pd.v
5.2.73
JTG D62
Vcd
Vd
Md ho
tg
Vcd--
Vd--
Md--
h0--
--
(162) ?
5 : . , .
. , ,.
.? .
5.3 5.3.1
Lo ? Lo=0.7-12H,H
5.3.3 :
fcd (bf
b)hf (h0
hf 2
)
fsd As(h0
as ) ( f pd
po ) Ap (h0
ap )
xbh0 x>h'fx2a'x2a's
(1)
JTG D62T
As / bh0min0.45ftd / fsd0.2%
b----T h0----
JTG D62
M ud 1.0
M
----
G1K
M
G
----
2K
M Q1K----
M Q2K----
WnW0--------
2
9.2-10 pc
N p0 A0
N p0ep0 W0
pc
Np An
N pepn Wn
9.2-11
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