当前位置:文档之家› 《有机化学》(第四版)第三章-不饱和烃(习题答案)

《有机化学》(第四版)第三章-不饱和烃(习题答案)

第三章 不饱和烃 思考题 习题3.1 写出含有六个碳原子的烯烃和炔烃的构造异构体的构造式。其中含有六个碳原子的烯烃,哪些有顺反异构?写出其顺反异构体的构型式(结构式)。(P69) 解:C6H12有13个构造异构体,其中4个有顺反异构体:

CH2=CHCH2CH2CH2CH3CH3CH=CHCH2CH2CH3CH3CH2CH=CHCH2CH

3

(Z,E)(Z,E)

CH2=CCH2CH2CH3CH3CH2=CHCHCH2CH3CH3CH2=CHCH2CHCH3

CH3

CH3C=CHCH2CH3CH3CH3CH=CCH2CH3CH3CH3CH=CH2CHCH3

CH3

(Z,E)(Z,E)

CH2=CHCCH3

CH3

CH3

CH2=CCHCH3CH3CH3CH3C=CCH3

CH3

CH3

CH2=CCH2CH3

CH2CH3

C6H10有7个构造异构体: CHCCH2CH2CH2CH3CH3CCCH2CH2CH3CH3CH2CCCH2CH

3

CHCCHCH2CH3CH3CHCCH2CHCH3

CH3

CHCC(CH3)3

CH3CCCHCH3

CH3

习题3.2 用衍生物命名法或系统命名法命名下列各化合物:(P74) (1) (CH3)2CHCH=CHCH(CH3)2 对称二异丙基乙烯 or 2,5-二甲基-3-己烯

(2) (CH3)2CHCH2CH=CHCHCH2CH3CH312345678 2,6-二甲基-4-辛烯 (3) CH3CH2CCCH2CH3123456 二乙基乙炔 or 3-己炔 (4) CH3CH2C(CH3)2CCH12345 3,3-二甲基-1-戊炔 (5) CH2=CHCH2CCH12345 1-戊烯-4-炔

(6) HCCC=CCH=CH2CH2CH2CH3CH2CH2CH3123456 3,4-二丙基-1,3-己二烯-5-炔

(7) CH3CH3 2,3-二甲基环己烯 (8) CH3CH3 5,6-二甲基-1,3-环己二烯 习题3.3 用Z,E-命名法命名下列各化合物:(P74) (1) ↑C=CCH2CH3HClBr↑ (Z)-1-氯-1-溴-1-丁烯

(2) ↓C=CFCH3ClCH3CH2↑ (E)-2-氟-3-氯-2-戊烯 (3) ↑C=CCH2CH3CH2CH2CH3HCH3↓ (E)-3-乙基-2-己烯 (4) ↓C=CCH(CH3)2CH2CH2CH3CH3H↑ (E)-3-异丙基-2-己烯 习题3.4 完成下列反应式:(P83) (1) C3H7CCC3H7lindlar催化剂C=CHC3H7HC3H7

(2) Li , 液NH3C3H7CCC3H7C=CHC3H7C3H7H (3) + Br2C=CHC2H5C2H5HBrHC2H5HBrC2H5 (4) CCHOOCCOOHC=CHOOCBrBrCOOH+ Br2 习题3.5 下列各组化合物分别与溴进行加成反应,指出每组中哪一个反应较快。为什么?(P84)

(1) CF3CH=CH2 和 CH3CH=CH2 (2) CH3CH=CH2 和 (CH3)3NCH=CH2

(3) CH2=CHCl 和 CH2=CH2 (4) CHCl=CHCl 和 CH2=CHCl 解:烯烃与溴的加成反应是由亲电试剂首先进攻;双键上电子云密度越大,越有利于亲电加成反应的进行。所以,各组中反应较快者如上所示。

习题3.6 分别为下列反应提出合理的反应机理:(P84)

(1) ClCl+ Cl2CHCl3- 80 Co

解:ClCl+



ClCl -

Cl

Cl从背面进攻

(2) BrBrBrClBr2 , Cl -CCl4 , 0 Co+ 解:BrBr+





Cl -

从背面进攻BrBr

BrCl

Br

Br -

从背面进攻 习题3.7 完成下列反应式:(P90)

(1) HICH3CH3I

(2) HBrC=CH3CCH3BrHCH3CH2CCH3BrBr (3) HBrCH2=CHCH2CCHCHCH2CCHCH3Br (4) HBrCH3(CH2)3CCHCCH2BrCH3(CH2)3 (5) HBr过氧化物(CH3)2C=CHCH3CHCH3(CH3)2CHBr (6) 2HBr过氧化物CH3CCHCH3CH2CHBr2 习题3.8 下列反应的产物是通过什么反应机理生成的?写出其反应机理。(P90) CH2=CHCCH3

CH3

CH3

CH3CHCCH3CH3CH3BrCH3CHCCH3

BrCH3CH3

HBr

H++

解: H+CH2=CHCCH3CH3CH3CH3CHCCH3CH3CH3BrCH3CHCCH3BrCH3CH3CHCCH3CH3CH3CH3CH3CHCCH3

CH3

CH3

Br -Br -

甲基迁移(二级碳正离子)(三级碳正离子)

习题3.9 在酸催化下,下列化合物与溴化氢进行加成反应的主要产物是什么?如果反应在过氧化物作用下进行,其主要产物有何不同?为什么?(P90) 在酸催化下,烯烃与溴化氢的加成是亲电加成反应,加成取向决定于碳正离子的稳定性; 在过氧化物存在下,烯烃与溴化氢的加成是自由基加成反应,加成取向决定于自由基的稳定性; (1) 2-甲基-1-丁烯

解:CH2=CCH2CH

3

CH3

HBrCH3CCH2CH

3

CH3

Br 稳定性:>CH2CHCH3CH2CH3CH3CCH3CH2CH

3

HBr过氧化物CH2=CCH2CH3CH3BrCH2CHCH2CH3

CH3

稳定性:>CH2CCH3CH2CH3

Br

CH2CCH3CH2CH3

Br

(2) 2,4-二甲基-2-戊烯

解:CH3C=CHCHCH3

CH3CH3HBr

(CH3)2CCH2CHCH3

CH3Br

稳定性:>

(CH3)2CCH2CHCH3

CH3

(CH3)2CHCHCHCH3

CH3 HBr过氧化物CH3C=CHCHCH

3

CH3CH3

(CH3)2CHCHCHCH3

CH3Br

稳定性:>(CH3)2CCHCHCH3

Br

CH3

(CH3)2CCHCHCH3

CH3Br

(3) 2-丁烯 解:HBrCH3CH=CHCH3CH3CH2CHCH

3

Br

稳定性:CH3CH2CHCH3CH3CHCH2CH3

CH3CH=CHCH3

HBr

过氧化物CH3CH2CHCH3

Br

稳定性:CHCH3BrCH3CHCHCH3CH3CHBr

习题3.10 烯烃加H2SO4的反应机理,与烯烃加HX的机理相似。试写出丙烯与硫酸加成的反应机理。(P94)

解:CH3CH=CH2CH3CHCH3CH3CHCH3OSO2OHH+-OSO2OH 习题3.11 完成下列反应式:(P94)

(1) (CH3)2C=CH2Br2 , H2OCH3CCH2OHCH3BrCH3CCH2BrCH3OH+多少

解释: (CH3)2CCH2BrH2O

(1)

(2)方式(1)空间障碍更小! (2) (CH3)2C=CH2H2OH+CH3CCH3CH3OH (3) Cl2 , H2OClOH (4) CCHOH+ H2OHgSO4H2SO4COHCH3O (5) (1) H2SO4(2) H2OOH (6) +CH280% H2SO4 -H2OOHCH3OH+主要产物 习题3.12 完成下列反应式:(P97) (1) (CH3)3CCH=CH2(2) H2O2 , OH-, H2O(1) BH3THF(CH3)3CCH2CH2OH

(2) C2H5C=CH2CH3(2) H2O2 , OH-, H2O(1) 1/2(BH3)2C2H5CHCH2OHCH3 (3) CH3(CH2)2CCC2H5(2) CH3CO2H , 0 Co(1) 1/2(BH3)2CH3(CH2)2C=CCH2CH3HH (4) C4H9CCH(2) H2O2 , OH-, H2O(1) BH3THFC4H9CH2CHOC4H9CH=CHOH

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