电路理论基础第二版答案【篇一：潘双来版电路理论基础答案】>第一章1-1. (a)、(b)吸收10w；(c)、(d)发出10w.1-2. –1a; –10v; –1a; – 4mw.1.8cos22t w.1-4. u =104 i ; u = -104 i ; u =2000i ; u = -104 i ;1-5.1-6. 0.1a.1-7.1-8. 2?f; 4?c; 0; 4?j.1-9. 9.6v,0.192w, 1.152mj;16v, 0, 3.2mj.1-10. 1– e-106 ta , t 0 取s .1-11. 3h, 6(1– t )2 j; 3mh,6(1–1000 t ) 2 mj;1-12. 0.4f, 0 .1-13. 供12w; 吸40w;吸2w; (2v)供26w, (5a)吸10w.1-14. –40v, –1ma; –50v, –1ma; 50v, 1ma.1-15. 0.5a,1w; 2a,4w; –1a, –2w; 1a,2w.1-16. 10v,50w;50v,250w;–3v,–15w;2v,10w.1-17. (a)2v;r耗4/3w;us : –2/3w, is : 2w;(b) –3v; r耗3w; us : –2w, is :5w;(c)2v,–3v; r耗4w;3w;us :2w, is :5w;1-18. 24v, 发72w; 3a, 吸15w;1-19. 0,us/rl ,us ;us/r1 ,us/r1 , –us rf /r1 .1-20. 6a, 4a, 2a, 1a, 4a; 8v, –10v, 18v.1-21. k打开：(a)0, 0, 0; (b)10v, 0, 10v;(c)10v,10v,0; k闭合: (a)10v,4v,6v;(b)4v,4v,0; (c)4v,0,4v;1-22. 2v; 7v; 3.25v; 2v.1-24. 14v.1-25. –2.333v, 1.333a; 0.4v, 0.8a.1-26. 80v.※第二章2-2. , .2-4. 400v;363.6v;ia=.5a, 电流表及滑线电阻损坏. 2-11. –75ma; –0.5a.2-14.1.6v,-24v2-15. (a) (b) –2 a↓, 吸20w.2-16.2-17. 3a.2-18. 7.33v.2-19. 86.76w.2-20. 1v, 4w.2-21. 64w.2-22.电压源发50w，电流源发1050w2-232-24. 7v, 3a; 8v,1a.2-25. 4v, 2.5v, 2v.2-27. 60v.2-28. 4.5v.2-29. –18v.2-30. 原构成无解的矛盾方程组; (改后)4v,10v.2-312-32.2.5a2-33. 3.33 k?, 50 k?.2-34 加法运算2-35. r3 (r1 +r2 ) is /r1 .2-36. 可证明 i l =－ us /r3 .2-37. –2 ; 4 . ※第三章3-1. 44v;–1+9=8v; 6+9=15v; sin t +0.2 e – t v. 3-2. 155v.3-3. 190ma.3-4. 1.8倍.3-5. 左供52w, 右供78w.3-6. 1?; 1a; 0.75a.3-7. 3a; 1.33ma; 1.5ma; 2/3a; 2a.3-8. 20v, –75.38v.3-9. –1a; 2a; 1a.3-10. 5v, 20?; –2v, 4?.3-12. 4.6?.3-14. 10v, 5k?.3-15.3-16.22.5v3-17. 4/3?, 75w; 4/3?, 4.69w.3-18. 3?, 529/12w.; 1?, 2.25w.3-193-20. 50?.3-21. 0.2a.3-22. 1a.3-23. 1.6v.3-24. 4a;3-25. 23.6v; 5a,10v.3-26.3-27 4v3-28. ※第四章4-1. 141.1v, 100v, 50hz, 0.02s,0o, –120o; 120 o. 4-2. 7.07/0 o a, 1/–45 o a, 18.75/–40.9 o a.4-3., 7.75ma .4-4. 10/53.13oa, 10/126.87oa, 10/–126.87oa,10/–53.13oa；各瞬时表达式略。

4-5. 67.08v, 30v, 25v; 12v, 0, 12v, 0; 0, 0, 12v. 4-6. 7.07a; 10a, 50a.4-7. 173.2?.4-8. 4?, 1.5h.4-9.11v4-10. 5?, 0.1f.4-11. 5a; 20/–53.13o?, 0.05/53.13o s.4-124-13. 5?, 0.0577f; 3?, 29.33h;3?,0.125f; 0?,0.02f4-14.-z4-15.4-16. 10a, 141v.4-17. 3.47?, 53.2?f.4-18.4-19. 26.3?, 78.8mh, 34.6?f.4-20. 118.0v, 0.252?f.4-21. 0.751?f .4-23.4-24. 10/0o a, 10/0o v, 200w,1; 20a, 0；5a.4-25. 21.26a,1800w,0.846; 10.2?,2778w,0.926; 26.044-26. 495w, 0.375.4-27.4-28. 20 + j10?, 2.5w, 0.894.4-29. 1.99?,31.99?或6.11?, 11?,–19.05?.4-30. 30+j10=31.62/18.43o v, 300w, –300var.4-31. a;2va, j2va,2va, –j2va, –4va.4-32. 2/–90o a; 13.3/11.9o v, 7.97–j2.16?,3.16/63.4o v, 1+j1?.4-33.4-34. 5a, 11.09a, 10.83a, 1066w.4-35. .4-36. 200/–150o ma.4-37. 10h.4-38. 5?, 27.57mh, 367.75?f.4-39. 0.5?, 0.5h; 0.25w.4-40. 1.86 + j0.56?, 8.10w.4-41. 0.8 + j0.4?, 0.125w4-42.4-43. 100?, 0.667h, 0.167?f, 20..4-44. 10?, 0.796mh, 3183pf; 50.4-45. 0.1?f;4-46. 0.02h, 50.4-47. 100.5pf, 0.091v.4-48. 25?f , 180v.4-49. 0.253?f , 0.760?f .4-50. 4.12a. f. ?4-51.4-52. 30.09(-65.8)a, 17.37(-35.8)a.4-53. 2850w;1425w4-54.4.84?4-55. 9077w;7942w4-56. (1) ia不变，因对称时中线不起作用。

(2) 仍不变，因为s闭合时各相负载电压未变，电流表所涉及的两个a相负载也未变。

4-57. 38/–53.13oa, 38/–66.87oa, 33.59/75oa; 64.41/–77.35oa; 9.09/–150.0oa; 67.68/95.29oa.4-58. 190w, 380w.4-59. 1kw.4-60. 6.06a.4-61. 871.2w, 1161.6var; 290.4w, –668.5var.4-62. p(a) =p左 +p右 ; q(b) = pw .4-63.可.4-64. 0.1103h, 91.89?f.※第五章5-1.5-2. 根据绘出.5-3.5-4. (b)读数大。

5-5. ,5-6. 52.83mh.5-7.5-8. 20mh, 2.2v, 4.4v, 4.4v, 44ma, 22ma, 66ma.5-9. 1.59/–12.7o a.5-10. 13.42/–10.3o v; 1.69/–61.3o v.5-11..5-12. j0.75?.5-13.5-14. 50mh.5-15. 20?h, 2.5w, 250v.5-16. 4.06/–20.98o a, 0.406/–9.05o a, 8.903/–157.8o a.5-17. 2kw, 3.2kw.5-18. 0.09w; 3, 0.25w.5-19. 1.414a.5-20. u2 /u1 从3.356 降为0.0239.5-21. 20 – j15?, 2.8125w.5-22. 80.0w, –20.0w, 100w.注意到pr1= 20w，pr2= 60w，可见：电源供给第2线圈共100w的功率，其本身仅耗60w，其余40w经互感耦合至第1线圈，线圈1耗20w，还剩20w送还给电源(p1=－20w) ? p =100－20 = 80w 。

【篇二：电路理论基础习题答案】>第一章1-1. (a)、(b)吸收10w；(c)、(d)发出10w. 1-2. –1a; –10v; –1a; –1-3. –0.5a; –6v; –15e–t 4mw.2t w.1-4. u =104i ; u = -104i ; u =2000i ; u = -104i ;1-8. 2?f; 4?c; 0; 4?j. 1-9. 9.6v,0.192w, 1.152mj; 16v, 0, 36.2mj. 1-10. 1–e-10 ta , t 0 取s . 1-11. 3h, 6(1– t )2j; 3mh, 6(1–1000 t ) 2 mj;1-12. 0.4f, 0 .1-13. 供12w; 吸40w;吸2w; (2v)供26w, (5a)吸10w. 1-14. –40v, –1ma; –50v, –1ma;50v, 1ma. 1-15. 0.5a,1w; 2a,4w; –1a, –2w; 1a,2w.1-16. 10v,50w;50v,250w;–3v,–15w;2v,10w. 1-17. (a)2v;r耗4/3w;us : –2/3w, is : 2w; (b) –3v; r耗3w; us : –2w, is :5w; (c)2v,–3v; r耗4w;3w;us :2w, is :5w; 1-18. 24v, 发72w; 3a, 吸15w;1-24. 14v. 1-25. –2.333v, 1.333a; 0.4v, 0.8a. 1-26. 12v, 2a, –48w; –6v, 3a, –54w .※第二章2-4. 400v;363.6v;i.2-21. 15a, 11a, 17a. 2-23. 7v, 3a; 8v,1a. 2-24. 4v, 2.5v, 2v. 2-26. 60v. 2-27. 4.5v. 2-28. –18v.2-29. 原构成无解的矛盾方程组; (改后)4v,10v. 2-30. 3.33 k?, 50 k?. 2-31. r3 (r1 +r2 ) is /r1 . 2-32. 可证明 i l =－ us /r3 . 2-33. –2 ; 4 . 2-34. (us1 + us2 + us3 )/3 . ※第三章3-1. –1+9=8v; 6+9=15v; sin t +0.2 e – t v. 3-2. 155v. 3-3. 190ma. 3-4. 1.8倍.3-5. 左供52w, 右供78w. 3-6. 1?; 1a; 0.75a.3-7. 3a; 1.33ma; 1.5ma; 2/3a; 2a.3-8. 20v, –75.38v.3-9. –1a; 2a; –17.3ma. 3-10. 5v, 20?; –2v, 4?. 3-12. 4.6?. 3-13.2v; 0.5a. 3-14. 10v, 5k?.3-15. 4/3?, 75w; 4/3?, 4.69w. 3-16. 1?, 2.25w. 3-18. 50?. 3-19. 0.2a. 3-20. 1a. 3-21. 1.6v. 3-22. 4a; –2a.3-23. 23.6v; 5a,10v. 3-24. 52v. ※第四章4-1. 141.1v, 100v, 50hz, 0.02s,0o, –120o; 120 o.4-2. 7.07 o– o.75– o4-3. um3 , 7.75ma .4-4. 10oa, 10oa, 10–o10/–53.13oa；各瞬时表达式略。